Lets say I have the following string:
"**link(http://google.com)*{Google}**"
And I want to use preg_match to find the EXACT text **link(http://google.com) but the text inside the brackets changes all the time. I used to use:
preg_match('#\((.*?)\)#', $text3, $match2);
Which would get what is inside the brackets which is good but if I had: *hwh(http://google.com)** it would get whats inside of that. So how can i get whats inside the brackets if, in front of the brackets has **link?
~(?:\*\*link\(([^\)]+)\))~ will match contents in the brackets for all inputs that look like **link(URL) but do not contain extra ) inside URLs. See the example on Regexr: http://regexr.com/3en33 . The whole example:
$text = '"**link(http://google.com)*{Google}**"
**link(arduino.cc)*{official Arduino site}';
$regex = '~(?:\*\*link\((?<url>[^)]+))~';
preg_match_all($regex, $text, $matches);
var_dump($regex, $matches['url']);
Here
preg_match("/\*\*link\((\D+)\)/",$text,$match);
Use a lookbehind operator ?<=
(?<=\*\*link)\((.*)\) gives you what's inside braces if the text behind is **link
Update:
Here's a PHP example
Here's a regex example
Related
I'm trying to retrieve the followed by count on my instagram page. I can't seem to get the Regex right and would very much appreciate some help.
Here's what I'm looking for:
y":{"count":
That's the beginning of the string, and I want the 4 numbers after that.
$string = preg_replace("{y"\"count":([0-9]+)\}","",$code);
Someone suggested this ^ but I can't get the formatting right...
You haven't posted your strings so it is a guess to what the regex should be... so I'll answer on why your codes fail.
preg_replace('"followed_by":{"count":\d')
This is very far from the correct preg_replace usage. You need to give it the replacement string and the string to search on. See http://php.net/manual/en/function.preg-replace.php
Your second usage:
$string = preg_replace(/^y":{"count[0-9]/","",$code);
Is closer but preg_replace is global so this is searching your whole file (or it would if not for the anchor) and will replace the found value with nothing. What your really want (I think) is to use preg_match.
$string = preg_match('/y":\{"count(\d{4})/"', $code, $match);
$counted = $match[1];
This presumes your regex was kind of correct already.
Per your update:
Demo: https://regex101.com/r/aR2iU2/1
$code = 'y":{"count:1234';
$string = preg_match('/y":\{"count:(\d{4})/', $code, $match);
$counted = $match[1];
echo $counted;
PHP Demo: https://eval.in/489436
I removed the ^ which requires the regex starts at the start of your string, escaped the { and made the\d be 4 characters long. The () is a capture group and stores whatever is found inside of it, in this case the 4 numbers.
Also if this isn't just for learning you should be prepared for this to stop working at some point as the service provider may change the format. The API is a safer route to go.
This regexp should capture value you're looking for in the first group:
\{"count":([0-9]+)\}
Use it with preg_match_all function to easily capture what you want into array (you're using preg_replace which isn't for retrieving data but for... well replacing it).
Your regexp isn't working because you didn't escaped curly brackets. And also you didn't put count quantifier (plus sign in my example) so it would only capture first digit anyway.
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)
Is it possible to have a PHP regex expression that extracts the content from the first ] to the last [?
For example if I had the following string:
$string = [shortcode]You write a shortcode by using ([])[/shortcode]
I would want to extract:
You write a shortcode by using brackets ([])
and store it in a variable. The content to be extracted could be anything. Thanks in advance.
You should be using capturing groups to make sure you match the closing tag.
\[(\w+)\].*?\[/\1\]
This will match a word inside [] and keep going until if finds the same word inside [/...].
Regexes are greedy by default, so this will do the job just fine:
/\](.*)\[/
To get this working in PHP properly, you would do something like this:
preg_match('/\](.*)\[/', $text, $matches);
$result = $matches[1];
this could make, what you need
[^\]]\](.*)\[[^\[]
This works:
preg_match( '#\](.*)\[#', $string, $matches);
print_r($matches);
Just a quick regex question...hopefully
I have a string that looks something like this:
$string = 'some text [ something {"index":"{"index2":"value2"}"}] [something2 {"here to be":"more specific"}]';
I want to be able to get the value:
{"index":"{"index2":"value2"}"}
But all my attempts at matching (or replacing) keep giving me:
{"index":"{"index2":"value2"}
preg_replace('/\[(.*?)({.*?[^}]})*?\]/is', "", $string);
Here I'm matching the whole square bracket area, but hopefully you can see what I'm trying to do.
The negation of the "do not match }" doesn't seem to be doing anything. Maybe I just need an OR in there or something.
Well, thanks if you have time to answer.
The $string could contain multiple instances of the {} so a greedy regex won't work....that I know of.
You can't make a regex count the opening brackets and the corresponding closeing brackets, you should use a simple for loop to do that, but you can get the complete string from the first opening bracket to the last closeing one with a greedy expression like: ({.*}). Note that simple string functions are much faster then regular expressions, so you should use those instead.
I'm trying to parse some text for example:
$text = "Blah blah [a]findme[/a] and [b]findmetoo[b], maybe also [z]me[/z].";
What I have now is:
preg_match_all("/[*?](.*?)[\/*?]/", $text, $matches);
Which doesn't work unfortunately.
Any ideas how to parse, return the node key and the corresponding node value?
Well firstly by you not putting () around your *? your not matching the tag name, and secondly, using [*?] will match multiple [ until the ] where you want to match inside, so you should be doing [(.*?)] and [\/(.*?)]
You would have to try something along the lines of:
/\[(.*?)\](.*?)\[\/(.*?)\]/is
this is not guaranteed to work but will get you closer.
you could also do:
/\[(.*?)\](.*?)\[\/\1\]/is
and then foreach result loop recursively until preg_match_all returns false, that's a possible way how to do nesting.
In order to match the same tags, you need a backreference:
This assumes no nesting, if you need nesting then let me know.
$matches = array();
if (preg_match_all('#\[([^\]]+)\](.+?)\[/\1\]#', $text, $matches)) {
// $matches[0] - entire matched section
// $matches[1] - keys
// $matches[2] - values
}
Incidentally, I do not know what you are going to do with this bbcode style work, but usually you would want to use preg_replace_callback() to deal with inline modification of this sort of text, with a regexp similar to the above.
Try:
$pattern = "/\[a\](.*?)\[\/a\]/";
$text = "Blah blah [a]findme[/a] and [b]findmetoo[b], maybe also [z]me[/z].";
preg_match_all($pattern, $text, $matches);
That should point you in the right direction.
I came up with this regex ((\[[^\/]\]).+?(\[\/[^\/]\])). Hope will work for you
I'm no regex monkey, but I think you need to escape those brackets and create groups to search for, as brackets don't return results (parentheses do):
preg_match_all("/\\[(*?)\\](.*?)\\[\(\/*?)\\]/", $text, $matches);
Hope this works!
Should your second example also be captured even though the [b] "tag" is not closed with the [\b] backslash 'b'. If tags should be properly closed then use
/\[(.*?)\](.*?)\[\/\1\]/
This will ensure that opening and closing tags match.
You can try this:
preg_match_all("/\[(.*?)\](.*?)\[\/?.*?\]/", $text, $matches);
See it
Changes made:
[ and ] are regex meta-characters
used to define character class. To
match literal [ and ] you need to
escape them.
To match any arbitrary text(without
newline) in non-greedy way you use
.*?.
To match the node key you need to
enclose the pattern matching it in
(..) so that they get captured.