How to output product variations - php

Question

I would like some advice on how best to approach outputting multiple products and their variations from a database.
I am building an eCommerce application and need to output a series of products and their product variations (colour, size).
My database has:
Table 1: ProductID, ProductTitle, ProductImg, ProductCat
Table 2: ProductID, ProductSize, ProductColour
Foreign key on ProductID
My current code is this:
<?php
$q = $_GET['cat']; // this pulls the category from URL param
include 'db_connect.php';
$result = mysqli_query($con, "SELECT DISTINCT a.ProductTitle, a.ProductImg, b.ProductColour
FROM product_info AS a
JOIN product_options AS b ON a.ProductID=b.ProductID
WHERE a.ProductCat = '".$q."'");
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo "<div class='product-display'>";
echo "<img id='prodImage' src='Images/" . $row['ProductImg'] . ".jpg' alt='product photo'>";
echo "<h3>" . $row['ProductTitle'] . "</h3>";
echo "<h3>" . $row['ProductColour'] . "</h3>";
echo "</div>";
}
?>
This outputs:
Product 1, Colour 1
Product 1, Colour 2
Product 2, Colour 1
Product 2, Colour 2
Product 3, Colour 1
Product 3, Colour 2
I want it to output:
Product 1, Colour 1, Colour 2
Product 2, Colour 1, Colour 2
Product 3, Colour 1, Colour 2
What is the best way to achieve this?
FYI - my array output is this:
Array ( [ProductTitle] => Puffer Jacket [ProductImg] => 444 [ProductColour] => Aubern )
Array ( [ProductTitle] => Puffer Jacket [ProductImg] => 444 [ProductColour] => Black )
Array ( [ProductTitle] => The Bander [ProductImg] => 111 [ProductColour] => Aubern )
Array ( [ProductTitle] => The Bander [ProductImg] => 111 [ProductColour] => Black )
Array ( [ProductTitle] => The comfy one [ProductImg] => 222 [ProductColour] => Aubern )
Array ( [ProductTitle] => The comfy one [ProductImg] => 222 [ProductColour] => Black )
SOLUTION:
Please refer to:
Parsing one col of multiple rows php
and
SQL JOIN - Need to return one product id but all variations of it (e.g. Size, colour)
These answer it nicely... problem solved.