I am trying to make registration in swift3 with mysql
but there is some thing wrong ,
when I run my app and make register return msg "some fields are empty"
In php code:
$fullname = htmlentities($_REQUEST["fullname"]);
$username = htmlentities($_REQUEST["username"]);
$email = htmlentities($_REQUEST["email"]);
$password = htmlentities($_REQUEST["password"]);
$phone = htmlentities($_REQUEST["phone"])
swift code:
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
let url = URL(string: "http://localhost/php/register.php?")
var request = URLRequest(url: url!)
request.httpMethod = "POST"
let body = "fullname=\(FirstName.text)%20\(LastName.text)&username=\(UserName.text)&email=\(Email.text)&password=\(Password.text)&phone=\(Phone.text)"
request.httpBody = body.data(using: String.Encoding.utf8)
let task = session.dataTask(with: url!) {data, response, error in
if error != nil {
print(error!.localizedDescription)
} else {
do {
if let json = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String: Any]
{
print(json)
}
} catch {
print("error in JSONSerialization")
}
}
}
task.resume()
I think you missed this
let task = session.dataTask(with: request) {data, response, error in
replace url with request
Related
I'm working on a project where I need to send some data to the remote database. So I'm developing an iOS app using Swift 3.1 and when I try to send data to the database it says,
The data couldn’t be read because it isn’t in the correct format.
Also there is another error;
Error Domain=NSCocoaErrorDomain Code=3840 "No value." UserInfo={NSDebugDescription=No value.}
This is my swift code:
let urlOfSMARTCF = URL(string: "http://192.168.1.99/insertData.php")
let request = NSMutableURLRequest(url: urlOfSMARTCF! as URL)
request.httpMethod="POST"
request.addValue("application/json", forHTTPHeaderField: "Accept")
for contact in contactsCaptuure
{
let userMobileNumber = DBManager.shared.retriveRegisteredNumberOfMobile()
let postParameters = "{\"usermobilenum\":\(String(describing: userMobileNumber!)),\"contactnum\":\(contact.phoneNumber!)}";
request.httpBody = postParameters.data(using: String.Encoding.utf8)
let task = URLSession.shared.dataTask(with: request as URLRequest)
{
data, response, error in
if error != nil
{
print("error is \(String(describing: error))")
return;
}
do
{
let myJSON = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
if let parseJSON = myJSON
{
var msg : String!
msg = parseJSON["message"] as! String?
print(msg)
}
}
catch
{
print(error.localizedDescription)
print(error)
}
}
print("Done")
task.resume()
}
This is my PHP in remote database:
<?php
if($_SERVER["REQUEST_METHOD"]=="POST")
{
require 'connectDB.php';
$userPhone = $_POST["usermobilenum"];
$contactNum = $_POST["contactnum"];
$query = "SELECT * FROM user WHERE UserMobNum='".$userPhone."'"; // Usermobile is registered.SIP exists.
if($results= mysqli_query($connect,$query))
{
if(mysqli_num_rows($results)>0)
{
$i=0;
while($rows=mysqli_fetch_assoc($results))
{
$sip[$i] = $rows["SIP"];
$i++;
}
$queryToAddData = "INSERT INTO user (UserMobNum,SIP,Phone) VALUES ('".$userPhone."','".$sip[0]."','".$contactNum."')";
if(mysqli_query($connect,$queryToAddData))
{
//Return success message to the app
echo "Success"
}
else
{
die(mysqli_error($connect));
}
}
else
{
$availableSIP=false;
while($availableSIP==false) // Assign a random value until it's being a valid one.
{
$sip[0]=rand(1,9999);
$queryToCheck = "SELECT * FROM user WHERE SIP='".$sip[0]."'";
if($results= mysqli_query($connect,$queryToCheck))
{
if(mysqli_num_rows($results)==0)
{
$availableSIP=true;
}
}
}
$queryToAddData = "INSERT INTO user (UserMobNum,SIP,Phone) VALUES ('".$userPhone."','".$sip[0]."','".$contactNum."')";
if(mysqli_query($connect,$queryToAddData))
{
//Return success message to the app
echo "Success"
}
else
{
die(mysqli_error($connect));
}
}
}
else
{
echo "First Level Failure!";
die(mysqli_error($connect));
}
mysqli_close($connect);
}
else
{
echo "Failed in POST Method"
}
?>
What I did
Went through all of stack overflow and other site suggestions but had no luck. I even checked my jSon string using a json validator and it passed. This is how my jSon string looks like.
{"usermobilenum":1234567890,"contactnum":9345}
However after some search I found that this happens because Remote database PHP sends this error message. So I checked each and every variable in PHP but couldn't find any problem. Also this couldn't be a problem with PHP cause I work with those exact php files when I connect to via my android app. That works fine. But in iOS it generates that error. Can someone help me please?
UPDATE
This is insertdataTest.php file:
<?php
if($_SERVER["REQUEST_METHOD"]=="POST")
{
$userPhone = $_POST["usermobilenum"];
echo $userPhone;
mysqli_close($connect);
}
else
{
echo json_encode("Failed in POST Method");
}
?>
{"usermobilenum":1234567890,"contactnum": 9345} - this is treated as a String. It's not a VALID JSON.
Updated code:
let urlOfSMARTCF = URL(string: "http://192.168.1.99/insertData.php")
let request = NSMutableURLRequest(url: urlOfSMARTCF! as URL)
request.httpMethod="POST"
request.addValue("application/json", forHTTPHeaderField: "Accept")
for contact in contactsCaptuure {
let userMobileNumber = DBManager.shared.retriveRegisteredNumberOfMobile()
let postParameters = NSMutableDictionary()
postParameters["usermobilenum"] = userMobileNumber
postParameters["contactnum"] = contact.phoneNumber!
let jsonData = try? JSONSerialization.data(withJSONObject: postParameters, options: .prettyPrinted)
request.httpBody = jsonData
let task = URLSession.shared.dataTask(with: request as URLRequest) {
data, response, error in
if error != nil {
print("error is \(String(describing: error))")
return;
}
do {
let myJSON = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? [String: Any]
if let parseJSON: NSMutableDictionary = NSMutableDictionary(dictionary: myJSON as! NSMutableDictionary){
let msg = parseJSON["message"] as! String
print(msg)
}
}
catch {
print(error.localizedDescription)
print(error)
}
}
print("Done")
task.resume()
}
Buddy I debug you code and found that there is error in server response not in you code. try this and reply me ASAP please
before this line "let myJSON = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary"
add "let str = String.init(data: data!, encoding: .utf8)
print(str ?? "error")"
I am waiting please.
I'm trying to get parameters in my php file when I'm posting from SWIFT (login file)
This is my php file :
<?
$json = array();
$json['username'] = $_POST['username'];
$json['password'] = $_POST['password'];
$json['result'] = "false";
$json['id_familia'] = 148;
$json['id_centre'] = 2;
$json['web'] = "www.cec-escolalolivar.cat";
echo json_encode($json);
?>
This is swift code (of course I've tried with different options, sync, not sync, ....)
let url : NSURL = NSURL(string: "http://www.cec-info.cat/app/config.inc.main_families_json.php")!
let request:NSMutableURLRequest = NSMutableURLRequest(url: url as URL)
let bodyData="data=xgubianas#gmail.com"
request.httpMethod = "POST"
request.httpBody = bodyData.data(using: String.Encoding.utf8)
NSURLConnection.sendAsynchronousRequest(request as URLRequest, queue: OperationQueue.main)
{
(response,data,error) in
print (response as Any)
if let data = data{
do {
let json = try JSONSerialization.jsonObject(with: data, options: [])
print (json)
}
catch
{
print (error)
}
}
}
I have a Swift function for a button that when pressed writes some details into a database via PHP:
#IBAction func createCommunityButtonTapped(_ sender: AnyObject) {
let communityName = communityNameTextField.text;
if (communityName!.isEmpty){
displayMyAlertMessage(userMessage: "You must name your Community");
return;
}else{
func generateRandomStringWithLength(length: Int) -> String {
var randomString = ""
let letters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
for _ in 1...length {
let randomIndex = Int(arc4random_uniform(UInt32(letters.characters.count)))
let a = letters.index(letters.startIndex, offsetBy: randomIndex)
randomString += String(letters[a])
}
return randomString
}
let communityCode = generateRandomStringWithLength(length: 6)
passwordTextField.text = communityCode
let myUrl = URL(string: "http://www.quasisquest.uk/KeepScore/createCommunity.php?");
var request = URLRequest(url:myUrl!);
request.httpMethod = "POST";
let postString = "communityname=\(communityName!)&code=\(communityCode)&email=\(myEmail!)";
request.httpBody = postString.data(using: String.Encoding.utf8);
let task = URLSession.shared.dataTask(with: request) { (data, response, error) in
if (try! JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]) != nil {
}
}
task.resume()
}
}
The function works great apart from whenever I add this echo jsonline into the PHP script:
if($newresult)
{
$returnValue["status"] = "Success";
$returnValue["message"] = "Community is registered";
echo json_encode($returnValue);
return;
}
Then I get an error Thread 8: EXC_BAD_INSTRUCTION (code=EXC_I386_INVOP, subside = 0x0) on this line:
if (try! JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String:AnyObject]) != nil {
}
And in the debug area the following details
data Data? some
response URLResponse? 0x0000618000223500
error Error? nil none
I think I'm missing a line, or need to set a variable to the JSONSerialization instead of 'try!' but I'm very unsure what.
You are returning null. Try this
if($newresult)
{
$returnValue["status"] = "Success";
$returnValue["message"] = "Community is registered";
return json_encode($returnValue);
}
Hello I have a small a problem with the code below, Xcode print this error:
ERROR: json error: Error Domain=NSCocoaErrorDomain Code=3840 "No
value." UserInfo={NSDebugDescription=No value.}
SWIFT CODE:
let yourUrl=“mylink.php”
let URL = NSURL(string:yourUrl)
let request:NSMutableURLRequest = NSMutableURLRequest(URL: URL!)
let boundaryConstant = "V2ymHFg03esomerandomstuffhbqgZCaKO6jy";
let contentType = "multipart/form-data; boundary=" + boundaryConstant
NSURLProtocol.setProperty(contentType, forKey: "Content-Type", inRequest: request)
let dataString = "Email=\(Email.text)&Password=\(Password.text)"
request.HTTPMethod = "POST"
request.HTTPBody = (dataString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
let task = NSURLSession.sharedSession().dataTaskWithRequest(request, completionHandler: { (data, response, error) -> Void in
//reponse recieved
//in this case response string will be saved in data, its of type NSData
do{
let str = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.AllowFragments) as! [String:AnyObject]
print(str)
}
catch {
print("json error: \(error)")
}
})
task.resume()
PHP CODE:
mylink.php
<?php
header("Content-Type: application/json");
$email = $_POST["Email"];
$password = $_POST["Password"];
$stat=“myvalue”;
return json_encode($stat);
?>
How can I solve this error?
I want to send data from my iOS app to a PHP sever in JSON format. I am doing this at the backend with the following code:
$json = $_POST['json'];
$data = json_decode($json, TRUE);
$email = $data['email'];
$user_password = $data['password'];
I want to send data in a JSON variable such that I can accept the data in
the JSON variable and then extract the fields one by one.
At the moment, I am doing this in my iOS app with the following Swift code:
func login(){
let email:NSString = txtEmail.text!
let password:NSString = txtPassword.text!
let post:NSString = "username=\(email)&password=\(password)"
NSLog("PostData: %#",post);
let url:NSURL = NSURL(string:"http://example.com/test.php")!
let postData:NSData = post.dataUsingEncoding(NSASCIIStringEncoding)!
let postLength:NSString = String( postData.length )
let request:NSMutableURLRequest = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST"
request.HTTPBody = postData
request.setValue(postLength as String, forHTTPHeaderField: "Content-Length")
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
var reponseError: NSError?
var response: NSURLResponse?
var urlData: NSData?
do {
urlData = try NSURLConnection.sendSynchronousRequest(request, returningResponse:&response)
} catch let error as NSError {
reponseError = error
urlData = nil
}
if ( urlData != nil ) {
let res = response as! NSHTTPURLResponse!;
NSLog("Response code: %ld", res.statusCode);
if (res.statusCode >= 200 && res.statusCode < 300)
{
let responseData:NSString = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!
NSLog("Response ==> %#", responseData);
do {
let jsonData = try NSJSONSerialization.JSONObjectWithData(urlData!, options: NSJSONReadingOptions.MutableContainers) as? NSDictionary
let success:NSInteger = jsonData!.valueForKey("success") as! NSInteger
NSLog("Success: %ld", success);
} catch let error as NSError {
print(error.localizedDescription)
}
}
}
}
I think I have to send a JSON array, but I don't know how can I save the variables in the array and send the JSON array to the PHP server. Anyone have any ideas?
You can do this by creating an array of dictionaries:
var user_outer_arrary = [[String:Any]]()
var user_inner_array = [String: Any]();
var jsonData : Data? = nil
let user_data :[String:Any]=["email": email,"password": password];
user_outer_arrary.append(user_data);
user_inner_array=["json": user_outer_arrary]
Then convert to JSON:
do
{
jsonData = try JSONSerialization.data(withJSONObject: user_inner_array, options: JSONSerialization.WritingOptions.prettyPrinted)
}
catch
{
}