Create managed stripe account with php and swift - php

so I'm trying to create managed stripe accounts with PHP Swift and Alamofire. But it's not working at all.
Here's my PHP code:
<?php
require_once('vendor/autoload.php');
\Stripe\Stripe::setApiKey("My APIKEY");
$country = $_POST['country'];
$create = \Stripe\Account::create(array(
"country" => $country,
"managed" => true
)
);
?>
Here's my swift code:
#IBAction func createBtn(_ sender: Any) {
let card = STPCardParams()
card.number = "5200828282828210"
card.expMonth = 4
card.expYear = 2024
card.cvc = "242"
card.currency = "usd"
STPAPIClient.shared().createToken(withCard: card ,completion: {(token, error) -> Void in
if let error = error {
print("ERROR: \(error.localizedDescription)")
}
else if let token = token {
print(token)
self.createUsingToken(token:token)
}
})
}
func createUsingToken(token:STPToken) {
let requestString = "My request URL"
let params = ["token": token.tokenId, "country": "US"]
//This line of code will suffice, but we want a response
Alamofire.request(requestString, method: .post, parameters: params).responseJSON { (response) in
print("REQUEST: \(response.request!)") // original URL request
print("RESPONSE: \(response.response!)") // URL response
print("DATA: \(response.data!)") // server data
print("RESULT: \(response.result)") // result of response serialization
if let JSON = response.result.error {
print("JSON: \(JSON.localizedDescription)")
}
}
}
And I'm getting this error from Alamofire: JSON: Response could not be serialized, input data was nil or zero length.
Thanks for your help.

It looks like your Swift/Alamofire request is expecting a JSON response, but your PHP code is not sending any response at all: you're sending an account creation request to Stripe but then never outputting any data.
You likely want to prepare an array with the attributes that you expect in your Swift code, then output it as JSON at the end of your PHP script:
echo json_encode($result);

Related

Swift - PHP : Textfield value sent over to PHP is received as null

I hope you all are doing well and staying safe! :)
I am new to iOS programming. I am trying to post values from a textfield to a MYSQL Database. As a first step, I tried to just print the values received on the PHP end.
The values are printed on the Swift end but on the PHP end, an empty string(null) is received. Could you please help and let me know why the string received on PHP end is null? Please help! I am stuck and unsure of what to do next.
I have tried retrieving values from the database and that code works perfectly fine.
Thanks in advance!
EDITED:
This has been now fixed. The correct code is below -
Swift Code:
struct DatatoPost : Codable{
var name : String
init() {
name = "Empty String"
}
}
var myDatatoPost = DatatoPost()
//Protocol created for this structure so that it can be applied to multiple class (View Controllers) that create a delegate for it(ManageDataDelegate)
protocol ManageDataDelegate {
func updateViewController(_ myManager : ManageData, saveOutputData: OutputData)
func didFailError(error : Error)
}
/* what action is expected to be taken on data reached through PHP file*/
struct ManageData {
var delegate : ManageDataDelegate?
var data : Data
init() {
data = Data()
}
//create POST URL based on function - this is the URL to post data to the backend.
mutating func postPHPData(){
let urlPostString = myConstant.baseURL + myConstant.postPHPValue
print(urlPostString)
performPostOperation(urlPostString)
}
//Steps to create URL and other related objects - prepare data for parsing.
mutating func performPostOperation(_ urlPostString : String) {
//1. Create URL
if let url = URL(string: urlPostString){
//Create request variable
var request : URLRequest = URLRequest(url: url)
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
do{
let params : [String : Encodable] = ["name": myDatatoPost.name]
data = try JSONSerialization.data(withJSONObject: params, options: .init())
let body = Data(data).base64EncodedData()
print("Data is: ")
let dataString = String(data: data, encoding: .utf8)
print(dataString)
request.httpBody = body
let requestString = String(data: request.httpBody!, encoding: .utf8)
print("Request String is:")
print(requestString)
//2. Create URLSession
let session = URLSession(configuration: .default)
//3. Give the session a task
let task = session.dataTask(with: request as URLRequest, completionHandler: handlePOST(data:response:error:))
//4. Start the session
task.resume()
}catch{
print(error)
}
}
}
//Function that lists the activities that need to be completed in the URL session - GET Data.
func handlePOST(data : Data?, response : URLResponse?, error: Error?){
if error != nil {
delegate?.didFailError(error: error!)
print("error is")
print(error!)
return
}
if let safeData = data{
let dataString = String(data: safeData, encoding: .utf8)
print(dataString)
}
print(response)
}
}
PHP Code:
<?php
echo "we are here";
// Create connection
$con = mysqli_connect("localhost","username","password","dbname");
echo "we are here again";
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: ";
}
$postdata = json_decode(file_get_contents("php://input"),TRUE);
$decoded = base64_decode($postdata);
echo "decoded!";
print_r($decoded,true);
//this value is not printed
echo "postdata";
echo $postdata->name;
//this value is not printed
$name= $postdata["name"];
echo "Name";
echo $postdata["name"];
//this value is not printed
echo "Base 64";
echo base64_decode($postdata["name"]);
echo base64_decode($postdata->name);
//This value is not printed
if (empty($postdata["name"])){
echo "String is empty";
//this is printed
}
if (empty($postdata->name)){
echo "String is empty";
//This is printed
}
echo "Its done";
// Close connections
mysqli_close($con);
?>
You have specified your request’s Content-Type to be application/json. So it should be JSON, free of base64 encoding. The only time you should use base64-encoding is if you are trying to send binary data in JSON. (And even then, in that case, we would reach for application/x-www-form-urlencoded request, not application/json request.)
Anyway, to send JSON request and parse JSON response:
protocol ManageDataDelegate: class {
func didFailError(error: Error)
func didReceiveResponse(object: Any)
}
/* what action is expected to be taken on data reached through PHP file*/
struct ManageData {
weak var delegate: ManageDataDelegate? // delegates should always be weak to avoid strong reference cycle; obviously `ManageDataDelegate` must be class protocol
//create POST URL based on function - this is the URL to post data to the backend.
func postPHPData(name: String) {
let urlPostString = URL(string: MyConstant.baseURL)!.appendingPathComponent(MyConstant.postPHPValue)
print(urlPostString)
performPostOperation(urlPostString, name: name)
}
//Steps to create URL and other related objects - prepare data for parsing.
func performPostOperation(_ url: URL, name: String) {
//Create request variable
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
do {
let params = ["name": name]
let body = try JSONSerialization.data(withJSONObject: params)
// 1. for diagnostic purposes, let's look at the JSON
if let json = String(data: body, encoding: .utf8) {
print("JSON is:", json)
}
request.httpBody = body
//2. Create URLSession
let session = URLSession(configuration: .default)
//3. Give the session a task
let task = session.dataTask(with: request, completionHandler: handlePOST(data:response:error:))
//4. Start the session
task.resume()
//5. If creating a URLSession locally, make sure to invalidate it when the request is done or else you will leak memory; better, create one `URLSession` and reuse it for all of your requests (and then you don't need/want to invalidate it)
session.finishTasksAndInvalidate()
} catch {
print(error)
}
}
enum ManageDataError: Error {
case unknownError(Data?, URLResponse?, Error?)
case notJsonResponse(String)
}
//Function that lists the activities that need to be completed in the URL session - GET Data.
func handlePOST(data: Data?, response: URLResponse?, error: Error?) {
guard let responseData = data, error == nil else {
let error = error ?? ManageDataError.unknownError(data, response, error)
delegate?.didFailError(error: error)
print("error is")
print(error)
return
}
if let object = try? JSONSerialization.jsonObject(with: responseData) {
delegate?.didReceiveResponse(object: object)
} else if let string = String(data: responseData, encoding: .utf8) {
delegate?.didFailError(error: ManageDataError.notJsonResponse(string))
} else {
delegate?.didFailError(error: ManageDataError.unknownError(data, response, error))
}
print(response ?? "No response")
}
}
There are a variety of refinements buried in the above (if creating a session, you must invalidate it when finished; passing responses to the delegate; making sure delegate reference is weak to avoid strong reference cycles; etc.), but hopefully this illustrates the idea: No base64-encoding is needed or desired with JSON requests.
Note, you have specified the request’s Accept to also be application/json so I would make sure it did precisely that:
<?php
header("Content-Type: application/json");
// Create connection
$con = mysqli_connect("localhost","username","password","dbname");
// Check connection
if (mysqli_connect_errno())
{
$result = [
"success" => false,
"message" => "Failed to connect to MySQL: " . mysqli_connect_error()
];
echo json_encode($result, JSON_PRETTY_PRINT);
exit();
}
$postdata = json_decode(file_get_contents("php://input"), true);
if (isset($postdata["name"]))
{
$result = [
"success" => true,
"name" => $postdata["name"]
];
}
else
{
$result = [
"success" => false,
"message" => "'name' not found",
"postdata" => $postdata
];
}
echo json_encode($result, JSON_PRETTY_PRINT);
// Close connections
mysqli_close($con);
?>
So, this parses the JSON and checks for name, but returning a JSON response, which is what the client was looking for.
There are other refinements I would suggest (e.g. I would use JSONEncoder and JSONDecoder rather than JSONSerialization; not create new URLSession for every request; usually a “network controller” like this would be a reference type so that you can use the same one wherever needed; I would use a framework such as Laravel in the server code, etc.), but I did not want to stray too far from the question at hand.

How to handle incoming JSON in PHP from a Swift (iOS) app?

I have an iOS application (Swift) which encodes some data and does a JSONSerialization and creates a JSON object. My code is below, I've done my best to keep it tidy, so I hope it makes sense:
struct Order: Codable {
let idQty: [FoodIdAndQuantity]
let collection: String
let name: String
let phone: Int
let doorNum: Int
let street: String
let postcode: String
}
struct FoodIdAndQuantity: Codable {
let itemId: Int
let qty: Int
}
class CheckoutServer: NSObject, URLSessionDataDelegate {
var inputValuesForItemAndQuantity = [Int:Int]()
var idQty = [FoodIdAndQuantity]()
var collection = String()
var name = String()
var phone = Int()
var doorNum = Int()
var street = String()
var postcode = String()
var request = URLRequest(url: NSURL(string: "http://192.168.1.100/api/AddOrder.php")! as URL)
func sendToDatabase() {
for(key,value) in inputValuesForItemAndQuantity {
idQty.append(FoodIdAndQuantity(itemId: key, qty: value))
}
let order = Order(idQty: idQty,collection: collection,name: name,phone: phone,doorNum: doorNum,street: street,postcode: postcode)
let encodedOrder = try? JSONEncoder().encode(order)
var json: Any?
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
if let data = encodedOrder {
json = try? JSONSerialization.jsonObject(with: data, options: .allowFragments)
if var json = json {
if JSONSerialization.isValidJSONObject(json) {
do {
json = try JSONSerialization.data(withJSONObject: json, options: .prettyPrinted)
} catch {
print("There was a problem creating the JSON object")
}
} else {
print("not valid JSON")
}
}
}
let postParameters = "json="+String(describing: json!)
print(String(describing: json!)) //Print JSON for debugging purposes
request.httpBody = postParameters.data(using: .utf8)
let defaultSession = URLSession(configuration: URLSessionConfiguration.default)
let task = defaultSession.dataTask(with: request) { (data, response, error) in
if error != nil {
print("Failed to download data at Menu Type Items")
} else {
print("Data uploaded")
}
}
task.resume()
}
}
So the above code does the following:
Creates an encodable object called 'order'.
Creates a POST request to my API.
Passes the encoded JSON object via a POST parameter.
I've printed the json object that gets posted back to the console in XCode and that looks as follows:
{
collection = Delivery;
doorNum = 99;
idQty = (
{
itemId = 17;
qty = 5;
},
{
itemId = 1;
qty = 3;
}
);
name = James;
phone = 012345667;
postcode = LXU49RT;
street = Hope Street;
}
Next, I'll move over to my server/API which accepts the POST parameter.
Below is my AddOrder.php page:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
require_once dirname(__FILE__) . '/DbOperation.php';
$json = $_POST["json"];
$db = new DbOperation();
$json = $db->addOrder($json);
}
And below is my DbOperation addOrder function:
public function addOrder($json) {
require dirname(__FILE__) . '/../../dbconnect.php';
$decoded = json_decode($json);
$collection = $decoded{"collection"};
$stmt2 = $pdo->prepare("INSERT INTO TestTable (collection) VALUES (:collection)");
$stmt2->bindParam(':collection',$collection);
$stmt2->execute();
}
It's worth noting that, whilst I try to fix this issue, I have created a test table in my Database which simply stores the collection element of the JSON.
The problem I have is, when I run my application and send the data, nothing gets stored in the database, and my apache error.log file says the Column 'collection' cannot be null. So I assume I am handling the POST parameter incorrectly at some point of my PHP. Unless the fault lies at a Swift level, which I'll add the Swift tag to this post if asked by an admin.
The full error is below:
[Wed Feb 28 15:44:55.178184 2018] [:error] [pid 520] [client 192.168.1.46:52400] PHP Fatal error: Uncaught PDOException: SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'collection' cannot be null in /var/www/api/DbOperation.php:111\nStack trace:\n#0 /var/www/api/DbOperation.php(111): PDOStatement->execute()\n#1 /var/www/api/AddOrder.php(16): DbOperation->addOrder(NULL)\n#2 {main}\n thrown in /var/www/api/DbOperation.php on line 111
What I've tried
I've tried altering my AddOrder.php page to the following:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
require_once dirname(__FILE__) . '/DbOperation.php';
//$json = $_POST["json"];
$json = json_decode(file_get_contents('php://input'),true);
$db = new DbOperation();
$json = $db->addOrder($json);
}
Your swift code doesn't make much sense. You have code that uses a JSONEncoder to encode your swift object into Data. If that succeeds, you then convert the data back to a Swift object using JSONSerialization. if that succeeds, you then use JSONSerialization.data(withJSONObject:options:) to convert your Swift object back to JSON data, and then use String(describing:) your insanely over-processed JSON Data to a string, which is very, very wrong.
Get rid of all that code. Try this instead:
func sendToDatabase() {
for(key,value) in inputValuesForItemAndQuantity {
idQty.append(FoodIdAndQuantity(itemId: key, qty: value))
}
let order = Order(idQty: idQty,collection: collection,name: name,phone: phone,doorNum: doorNum,street: street,postcode: postcode)
guard let encodedOrder = try? JSONEncoder().encode(order) else { return }
request.httpBody = encodedOrder
let defaultSession = URLSession(configuration: URLSessionConfiguration.default)
let task = defaultSession.dataTask(with: request) { (data, response, error) in
if error != nil {
print("Failed to download data at Menu Type Items")
} else {
print("Data uploaded")
}
}
task.resume()
}
The following is not valid code, and should throw a fatal "Cannot use object of type stdClass as array":
$decoded = json_decode($json);
$collection = $decoded{"collection"};
You probably want this:
$decoded = json_decode($json, true);
$collection = $decoded["collection"];
Or this:
$decoded = json_decode($json);
$collection = $decoded->collection;
I noticed a json decoding issue with incoming json from Swift 5 to php. Using file_put_contents in my php API, I found the json string from Swift looks like this
[{"Description":"box 3 of 3","Name":"Box S-7","Barcode":"1007","ComponentID":"50","Notes":"ok"}]
which if you convert with json_decode will throw an error, unless you remove the [ and ] from beginning and end of the string, respectively
$new_json = substr($json, 1, -1);
$decode = json_decode($new_json);

POST data from iOS to php server always NULL - iOS 10, Swift 3, php

i am implementing a FCM app server and wanted to store the device registration token id into my own database (Server written in PHP).
I realise the data in device id token is always null, Can someone point the right way to store the token accordingly into database?
Really appreciated perhaps someone could guide me on this issue, thanks!
Kindly refer the code/screenshots below:-
AppDelegate.swift
func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) {
var token = ""
for i in 0..<deviceToken.count {
token += String(format: "%02.2hhx", arguments: [deviceToken[i]])
}
print("Registration succeeded!")
print("Token: ", token)
Callquery(token)
}
AppDelegate.swift (Callquery method which send a POST request to server side script)
func Callquery(_ token: String)
{
// append parameter to oneDictionary
let tokenString = ["token": token] as [String: Any]
// create the request
var request = URLRequest(url: URL(string:"https://YourURL.com/admin/registerToken.php")!)
// set the method as POST
request.httpMethod = "POST"
// append the paramter to body
request.httpBody = try! JSONSerialization.data(withJSONObject: tokenString, options: [])
// create the session
URLSession.shared.dataTask(with:request, completionHandler: {(data, response, error) in
if error != nil {
print("There was error during datatask session")
print(error)
} else {
do {
guard let json = try? JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? [String: Any] else { return }
guard let errors = json?["errors"] as? [[String: Any]] else { return }
if errors.count > 0 {
// show error
print("There is an error during parse JSON datatask")
return
} else {
// show confirmation
print("datatask with JSON format performed successfully")
}
}
}
print(request)
}).resume()
}
Service Side Script(registerToken.php):
<?php
include 'config.php';
$token = $_POST['token'];
$sql = "INSERT INTO users (email,device_id) VALUES ('email','$token')";
mysqli_query($conn, $sql);
mysqli_close($conn);
?>
Running App with real devices log as below:-
Database users table (device id always has nothing):-
users table structure:-
tokenString :-
I had solved this issue by using GET method instead of POST method as below:-
Appdelegate.swift :
var request = URLRequest(url: URL(string:"https://YourURL.com/admin/registerToken.php?token=\(token)")!)
Server side script :
$token = $_GET['token'];

Invalid JSON require Swift iOS

I am developing a simple iOS Swift app. I want to make a log-in screen for my app that will connect to already existing user database in Wordpress. I found some PHP scripts and Swift code.
I am trying to post username and login, check it and return the result(isUser = true/false or 1/0)
Here is a PHP script
<?php
// Read request parameters
$username= $_REQUEST["username"];
$password = $_REQUEST["password"];
// Store values in an array
$returnValue = array("username"=>$username, "password"=>$password);
// Send back request in JSON format
echo json_encode($returnValue);
?>
and a Swift function
func getPHPJson() {
let urlPath: String = "LINK_TO_PHP_FILE?username=\(user)&password=\(pass)"
let url: NSURL = NSURL(string: urlPath)!
let request1: NSMutableURLRequest = NSMutableURLRequest(URL: url)
request1.HTTPMethod = "GET"
let queue:NSOperationQueue = NSOperationQueue()
NSURLConnection.sendAsynchronousRequest(request1, queue: queue, completionHandler:{ (response: NSURLResponse?, data: NSData?, error: NSError?) -> Void in
do
{
if let jsonResult = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? NSDictionary
{
print(jsonResult)
//print(jsonResult["isUser"] as! Bool)
let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
print("raw response: \(responseString!)")
}
} catch let error as NSError
{
print(error.localizedDescription)
print("error")
let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
print("raw response: \(responseString)")
}
})
}
it gives me a desired result.
OUTPUT
{
password = iosappusettest1;
username = iosappusettest;
}
raw response: {"username":"iosappusettest","password":"iosappusettest1"}
But when I add function to check if user is registered - I always get an invalid JSON
here is PHP function
function authentication ($user, $pass){
global $wp, $wp_rewrite, $wp_the_query, $wp_query;
if(empty($user) || empty($pass)){
return 0;
} else {
require_once('../wp-blog-header.php');
$status = 0;
$auth = wp_authenticate($user, $pass );
if( is_wp_error($auth) ) {
$status = 0;
} else {
$status = 1;
}
return $status;
}
}
I believe the problem is require_once function. In raw response I get a lot of html tags and other data that make my JSON invalid.
Is there any way to clear the page and output in the JSON only? echo "<script> document.documentElement.innerHTML = ''; </script>"; in PHP did't help me. maybe jQuery will help?
Maybe I can check if user is registered in another way?
Maybe I can store my result in a separate place or temp file?
Maybe I should wrap my data not in JSON but something else?
So I need to pass username and password to PHP, check it with authentication function(that uses require_once) and send back the $status to iOS Swift app ass variable.
Question is answered.
The problem was in WP plugin, that redirected all unlogined users from all the links in that domain, so when i called require_once('../wp-blog-header.php'); i was always redirected to main page and that was the reason for wrong JSON file with all the HTML markup.
Keep your response in pure JSON, and leave out any html tags as they are not needed by your ios end.

How can I get a PHP variable over to swift [duplicate]

This question already has answers here:
How to make HTTP request in Swift?
(21 answers)
Closed 8 years ago.
I want a variable in php to get over in swift (or get the value for the variable). How can I do that?
$name = "William";
How can I get this string "William" to my Swift script? Can anyone help me?
I know it's something with JSON and POST or something but otherwise I am complete lost.
When you want to get data from PHP to an iOS device, I would recommend having the PHP code send it as JSON. JSON is easier for the the client app to parse (especially as your web service responses get more complicated) and it makes it easier to differentiate between a valid response and some generic server error).
To send JSON from PHP, I generally create an "associative array" (e.g., the $results variable below), and then call json_encode:
<?php
$name = "William";
$results = Array("name" => $name);
header("Content-Type: application/json");
echo json_encode($results);
?>
This (a) specifies a Content-Type header that specifies that the response is going to be application/json; and (b) then encodes $results.
The JSON delivered to the device will look like:
{"name":"William"}
Then you can write Swift code to call NSJSONSerialization to parse that response. For example, in Swift 3:
let url = URL(string: "http://example.com/test.php")!
let request = URLRequest(url: url)
// modify the request as necessary, if necessary
let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data else {
print("request failed \(error)")
return
}
do {
if let json = try JSONSerialization.jsonObject(with: data) as? [String: String], let name = json["name"] {
print("name = \(name)") // if everything is good, you'll see "William"
}
} catch let parseError {
print("parsing error: \(parseError)")
let responseString = String(data: data, encoding: .utf8)
print("raw response: \(responseString)")
}
}
task.resume()
Or in Swift 2:
let url = NSURL(string: "http://example.com/test.php")!
let request = NSMutableURLRequest(URL: url)
// modify the request as necessary, if necessary
let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
guard let data = data else {
print("request failed \(error)")
return
}
do {
if let json = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String: String], let name = json["name"] {
print("name = \(name)") // if everything is good, you'll see "William"
}
} catch let parseError {
print("parsing error: \(parseError)")
let responseString = String(data: data, encoding: NSUTF8StringEncoding)
print("raw response: \(responseString)")
}
}
task.resume()
I'm answering this as an iOS/PHP dev rather than a Swift programmer.
You need to send an HTTP request to the webserver hosting the PHP script, which will return the contents of the web page given any specified parameters.
For example, if you sent an GET HTTP request to the following PHP script, the response would be "William" in the form of NSData or NSString depending on the method you use.
<?php
$name = "William";
echo $name;
?>
With a parameter GET http://myserver.com/some_script.php?name=William:
<?php
$name = $_GET['name']; // takes the ?name=William parameter from the URL
echo $name; // William
?>
As to the Swift side of things, there is a perfectly valid answer here which denotes one of the myriad methods of sending a request: https://stackoverflow.com/a/24016254/556479.

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