I am stuck. I want to make a session of the ID that belongs to a certain link. However, the code results into multiple ID's. And multiple links with different ID's coming from one code.
This is what I have:
$sql = "SELECT * FROM `lijsten` ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "<a href='lijst.php'> Naam: " . $row["naamlijst"]. " - taal: " . $row["taal"]. "</a> <br>";
}
} else {
echo "0 results";
}
$conn->close();
?
The statement gives links for all the results of the rows naamlijst and taal. But I only want to make a session of ID of the link that I click.
This is my first question on Stackoverflow. I hope someone can help me! :)
Picture of webpage
Here is the webpage, I want to store the ID of the link that I click into sessions
Related
I am updating all my code to Mysqli, before I did I had this code and it worked:
while($row = mysql_fetch_assoc($WildHorses)){
$InWild[] = $row['id'];
}
$RandomWild = array_rand($InWild);
$RandomHorse = $InWild[$RandomWild];
This is my SELECT statement:
$sql = "SELECT Horse.id, Horse.Name, Horse.Age, Horse.Image_name, Horse.Owner, Horse.Barn, Images.Image_path, Images.Image_name FROM Horse, Images WHERE Horse.Owner = '$colname_WildHorseList' AND Images.Image_name = Horse.Image_name";
$result = mysqli_query($con,$sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["id"]. " Name: " . $row["Name"]. " ImageName: " . $row["Image_name"]. "<br>";
}
} else {
echo "0 results";
}
The SELECT statement ends up echoing all of the correct information, but I want to make an array of only the Id's so that I can pick one at random each time a button is clicked.
I have tried multiple different copies and pastes of code to try and get what I want, but nothing seems to come out right.
Can someone point me in the right direction or explain what I'm doing wrong?
In your while loop you can simply do this :-
$i=0;
$animals=array();
$animals[$i]=$row["id"]; //puts id in array
And then you can create a random number by "rand()" between the length of 0-$i
and can get the job done.
I have a database and I generated a code that creates links depending on the name of the person in the database and I want the names to be
"sent" in the next page ( link's page). So I used the method "get" to do that but it does not work and I don't know why.
$sql = "SELECT * FROM table_personne; ";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo ("<a href=\"traitement.php?firsname=".$row["firsname"]."%"."&lastname=".$row["lastname"]."%".">".$row["firsname"]. " ".$row["lastname"]);
echo "<br>";
}
} else {
echo " 0 results";
}
The URL that is created is: traitement.php?prenom=paul%&nom=vincent%>paul%20vincent
Problems: The URL does not match the name of the person displayed and the lastname is "vincent%>paul" meaning lastname=$GET["lastname"]= "firstname%lastname<" and there is no $GET["firstname"].
Thanks a lot.
What about this :
echo (''.$row["firstname"]. " ".$row["lastname"]).'';
Maybe You have to change this :
$row["firsname"]
to
$row["firstname"]
I'm really stuck on this guys, and I know where the fault is but I can't seem to fix it.
The while loop itself works it's the if that is causing all the trouble.
Whenever there are 3 groups in the database it only displays 2 the strange part it will only display the items in the while loop. But the first item is somehow tied to the if statement.
public function get_group($user_id){
$sql3="SELECT * FROM groups WHERE user =
$user_id";
$results = mysqli_query($this->db, $sql3);
$user_data = mysqli_fetch_array($results);
if ($results->num_rows > 0) {
// output data of each row
while($row = $results->fetch_assoc()){
echo "hello";
echo "group :" . $row["group"] . "<br>";
echo "groupdesc:" . $row["groupdesc"] . "<br>";
echo "<a class='btn btn-primary' href='project.php?groupid=" . $row["groupid"] . "'>></a>";
}
}
else {
echo "0 results";
}
}
It seems it can't output the first one the first one just keeps hidden.
You fetch your first row in this line:
$user_data = mysqli_fetch_array($results);
And you do nothing with it.
And please do not mix procedural and object-oriented usage of mysqli.
I have a link/page 'myfiles.php' which shows the details of the file that a certain user uploaded. But after clicking again/entering the 'myfiles.php' into the address bar, the records are gone in the page. What's supposed to be the solution? Please help. Thanks. Here's my code:
while ($row=mysql_fetch_array($query)) {
$row1 = $row['name'];
$row2 = $row['size'];
$row3 = $row['type'];
$delfile = "<a href='deletefile.php?file=$row1'>Delete file</a>";
$dlfile = "<a href='download.php?file=$row1'>Download</a> ";
echo "<p>";
echo $row1;
echo "<br>";
echo $row2;
echo "<br>";
echo $row3;
echo "<br>";
echo $dlfile;
echo $delfile;
}
Are you using some sort of browsing accelerator and don´t you have a deletion confirmation?
It seems your browser is requesting all links on your page and deleting your records.
If you want to delete, insert, update, etc. records in a database, it is a very good idea to use POST instead of GET (like a clickable link), so you would have to add a form around every entry that posts the data to the server. You can of course skip this, but then you definitely need a POST based deletion confirmation.
I am assuming that $usersess is not changing? If this is dependent on a session or cookie - you should check that it is not expiring or being destroyed.
$query = mysql_query("SELECT * FROM uploadedfiles WHERE username='$usersess' ");
while ($row = mysql_fetch_array($query)) {
$delfile = "Delete file";
$dlfile = "Download ";
echo "<p>{$row['name']}<br>
{$row['size']}<br>
{$row['type']}<br>
{$dlfile}{$delfile}</p>";
}
There's a form called discussion.php, in which a user will fill out his/her question/discussion and post it to savedisc.php. Some of the savedisc.php looks like this:
$message = $_POST['message'];
$title = $_POST['title'];
$represents = $_POST['represents'];
//connect to database
//save the content of discussion/question into the database for future use
$sql="INSERT INTO Discussion (Message, Title, Type)
VALUES
('$message','$title','$represents')";
//Display user's question/discussion again
echo $message . "<br />";
echo $title . "<br />";
echo $represents . "<br />";
It is not shown above, but I am saving the id field manually, i.e. via phpmyadmin as a auto increment and primary key of course. Therefore, all of the values in the table Discussion will have their own unique id. Once the question/discussion is saved, I want to be able to display $title of each question on wb.php as a link, which as of now looks like this(some code from wb.php):
$result = mysql_query("SELECT * FROM Discussion ORDER BY id DESC");
//When user clicks the question/discussion Title, he/she will be directed to wbcomm.php
while($row = mysql_fetch_array($result))
{
echo "<a href='wbcomm.php' >{$row['Title']}</a><br />";
}
Until here, everything is working smooth. However, from here on, what I'm trying to do is, when the user clicks the question/discussion title via above code, I want him/her to be directed to wbcomm.php?id=1, where id=1 represents the unique id of the question/discussion. Some of the code from wbcomm.php is below:
if (isset($_GET['id']))
{
//connect to db
$wbid = mysql_real_escape_string($_GET['id']);
$sql = "SELECT * FROM Discussion WHERE id = '$wbid' LIMIT 1";
$res = mysql_query($sql);
if (mysql_num_rows() > 0) {
$discussion = mysql_fetch_object($res);
//display member's question here:
echo $discussion['id'] . "<br />";
echo $discussion['Title'] . "<br />";
echo $discussion['Type'] . "<br />";
echo $discussion['Message'] . "<br />";
}
else {
// discussion does not exist with ID
}
}
However, for some reason, the result is blank. I.e. the question/discussion doesn't even show up. What am I doing wrong? Is my procedure even correct?
Thank you.
In your wb.php, you create a link to wbcomm.php but you are not passing the ID of the discussion, so your $wbid will be empty. You need to pass the ID along with the link, like this:
while($row = mysql_fetch_array($result))
{
echo "<a href='wbcomm.php?id={$row['id']}' >{$row['Title']}</a><br />";
}
Your ID column is an autoincrement int type so you do not need to put it in quotes or escape it. You should definitely test it to see if it's numeric, though.
Use this SQL mysql_num_rows($res) > 0