Populating checkbox from server side data using 2 loops - php

Question

I have a need to check the checkboxes which values are available in the database, with that i has to display additional options avaialable also.
I was trying, as i am using two loops it's repeating the same set of checkboxes and check differnt values in each instance.
I need to check the appropriate checkboxes in first loop itself. Is there any way to achieve this
The following was my output
Output of the code
Following is the code i am using
$sid;//Retrived from DB
$iDLst=array();
$sql1 = "SELECT
`id1`
FROM `tbl1`
where `tbl1_sid`='" . $sid . "'";
$result1 = $conn->query($sql1);
if ($result1->num_rows > 0) {
while ($row = $result1->fetch_assoc()) {
$iDLst[]=$row['id1'];
}
}
foreach ($iDLst as $id){
$sql2 = "SELECT
`id`,
`nme`
FROM `tbl2`;
";
$result2 = $conn->query($sql2);
if ($result2->num_rows > 0) {
while ($rowC = $result2->fetch_assoc()) {
if (strpos($rowC['id'], $id) !== FALSE ) {
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]" checked/> <label>' . $rowC['nme'] . ' </label>';
} else {
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]" /> <label>' . $rowC['nme'] . ' </label>';
}
}
}
}
Note: I have changed to general code, There is no errors in code. I am getting the display. I need the solution regarding the logic part...

Answer 1

I think you can replace this:
if (strpos($rowC['id'], $id) !== FALSE ) {
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]" checked/> <label>' . $rowC['nme'] . ' </label>';
} else {
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]" /> <label>' . $rowC['nme'] . ' </label>';
}
with this:
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]" ' . strpos($rowC['id'], $id) ? 'checked ' : '' . '/> <label>' . $rowC['nme'] . ' </label>';
It's a ternary statement that says if strpos($rowC['id'], $id) evaluates true, 'checked ' will be in the enclosing echo statement, otherwise '' will be in the enclosing echo statement.

Answer 2

I have found the way after some research.
The way i am doing is only half part.
Following code will do the work addition to the provided code.
//Print the checkbox with checeked for the values in array
foreach ($iDLst as $id){
$sql2 = "SELECT
`id`,
`nme`
FROM `tbl2`;
";
$result2 = $conn->query($sql2);
if ($result2->num_rows > 0) {
while ($rowC = $result2->fetch_assoc()) {
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]" checked/> <label>' . $rowC['nme'] . ' </label>';
}
}
}
//Print the checkbox without checeked for the values Not in array
$sql3 = "$sql2 = "SELECT
`id`,
`nme`
FROM `tbl2` where id NOT IN (" . implode(',', array_map('intval', $iDLst)) . "); ";
$result3 = $conn->query($sql3);
if ($result3->num_rows > 0) {
while ($rowC = $result3->fetch_assoc()) {
echo ' <input value="' . $rowC['id'] . '" type="checkbox" name="upD[]"/> <label>' . $rowC['nme'] . ' </label>';
}
}
the following questions lead me the way to do this
MySQL PHP - SELECT WHERE id = array()? [duplicate]
mysql syntax on not equal many values