How can I best write a query that selects 10 rows randomly from a total of 600k?
A great post handling several cases, from simple, to gaps, to non-uniform with gaps.
http://jan.kneschke.de/projects/mysql/order-by-rand/
For most general case, here is how you do it:
SELECT name
FROM random AS r1 JOIN
(SELECT CEIL(RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 1
This supposes that the distribution of ids is equal, and that there can be gaps in the id list. See the article for more advanced examples
SELECT column FROM table
ORDER BY RAND()
LIMIT 10
Not the efficient solution but works
Simple query that has excellent performance and works with gaps:
SELECT * FROM tbl AS t1 JOIN (SELECT id FROM tbl ORDER BY RAND() LIMIT 10) as t2 ON t1.id=t2.id
This query on a 200K table takes 0.08s and the normal version (SELECT * FROM tbl ORDER BY RAND() LIMIT 10) takes 0.35s on my machine.
This is fast because the sort phase only uses the indexed ID column. You can see this behaviour in the explain:
SELECT * FROM tbl ORDER BY RAND() LIMIT 10:
SELECT * FROM tbl AS t1 JOIN (SELECT id FROM tbl ORDER BY RAND() LIMIT 10) as t2 ON t1.id=t2.id
Weighted Version: https://stackoverflow.com/a/41577458/893432
I am getting fast queries (around 0.5 seconds) with a slow cpu, selecting 10 random rows in a 400K registers MySQL database non-cached 2Gb size. See here my code: Fast selection of random rows in MySQL
$time= microtime_float();
$sql='SELECT COUNT(*) FROM pages';
$rquery= BD_Ejecutar($sql);
list($num_records)=mysql_fetch_row($rquery);
mysql_free_result($rquery);
$sql="SELECT id FROM pages WHERE RAND()*$num_records<20
ORDER BY RAND() LIMIT 0,10";
$rquery= BD_Ejecutar($sql);
while(list($id)=mysql_fetch_row($rquery)){
if($id_in) $id_in.=",$id";
else $id_in="$id";
}
mysql_free_result($rquery);
$sql="SELECT id,url FROM pages WHERE id IN($id_in)";
$rquery= BD_Ejecutar($sql);
while(list($id,$url)=mysql_fetch_row($rquery)){
logger("$id, $url",1);
}
mysql_free_result($rquery);
$time= microtime_float()-$time;
logger("num_records=$num_records",1);
logger("$id_in",1);
logger("Time elapsed: <b>$time segundos</b>",1);
From book :
Choose a Random Row Using an Offset
Still another technique that avoids problems found in the preceding
alternatives is to count the rows in the data set and return a random
number between 0 and the count. Then use this number as an offset
when querying the data set
$rand = "SELECT ROUND(RAND() * (SELECT COUNT(*) FROM Bugs))";
$offset = $pdo->query($rand)->fetch(PDO::FETCH_ASSOC);
$sql = "SELECT * FROM Bugs LIMIT 1 OFFSET :offset";
$stmt = $pdo->prepare($sql);
$stmt->execute( $offset );
$rand_bug = $stmt->fetch();
Use this solution when you can’t assume contiguous key values and
you need to make sure each row has an even chance of being selected.
Its very simple and single line query.
SELECT * FROM Table_Name ORDER BY RAND() LIMIT 0,10;
Well if you have no gaps in your keys and they are all numeric you can calculate random numbers and select those lines. but this will probably not be the case.
So one solution would be the following:
SELECT * FROM table WHERE key >= FLOOR(RAND()*MAX(id)) LIMIT 1
which will basically ensure that you get a random number in the range of your keys and then you select the next best which is greater.
you have to do this 10 times.
however this is NOT really random because your keys will most likely not be distributed evenly.
It's really a big problem and not easy to solve fulfilling all the requirements, MySQL's rand() is the best you can get if you really want 10 random rows.
There is however another solution which is fast but also has a trade off when it comes to randomness, but may suit you better. Read about it here: How can i optimize MySQL's ORDER BY RAND() function?
Question is how random do you need it to be.
Can you explain a bit more so I can give you a good solution.
For example a company I worked with had a solution where they needed absolute randomness extremely fast. They ended up with pre-populating the database with random values that were selected descending and set to different random values afterwards again.
If you hardly ever update you could also fill an incrementing id so you have no gaps and just can calculate random keys before selecting... It depends on the use case!
How to select random rows from a table:
From here:
Select random rows in MySQL
A quick improvement over "table scan" is to use the index to pick up random ids.
SELECT *
FROM random, (
SELECT id AS sid
FROM random
ORDER BY RAND( )
LIMIT 10
) tmp
WHERE random.id = tmp.sid;
I improved the answer #Riedsio had. This is the most efficient query I can find on a large, uniformly distributed table with gaps (tested on getting 1000 random rows from a table that has > 2.6B rows).
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max := (SELECT MAX(id) FROM table)) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1)
Let me unpack what's going on.
#max := (SELECT MAX(id) FROM table)
I'm calculating and saving the max. For very large tables, there is a slight overhead for calculating MAX(id) each time you need a row
SELECT FLOOR(rand() * #max) + 1 as rand)
Gets a random id
SELECT id FROM table INNER JOIN (...) on id > rand LIMIT 1
This fills in the gaps. Basically if you randomly select a number in the gaps, it will just pick the next id. Assuming the gaps are uniformly distributed, this shouldn't be a problem.
Doing the union helps you fit everything into 1 query so you can avoid doing multiple queries. It also lets you save the overhead of calculating MAX(id). Depending on your application, this might matter a lot or very little.
Note that this gets only the ids and gets them in random order. If you want to do anything more advanced I recommend you do this:
SELECT t.id, t.name -- etc, etc
FROM table t
INNER JOIN (
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max := (SELECT MAX(id) FROM table)) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * #max) + 1 as rand) r on id > rand LIMIT 1)
) x ON x.id = t.id
ORDER BY t.id
All the best answers have been already posted (mainly those referencing the link http://jan.kneschke.de/projects/mysql/order-by-rand/).
I want to pinpoint another speed-up possibility - caching. Think of why you need to get random rows. Probably you want display some random post or random ad on a website. If you are getting 100 req/s, is it really needed that each visitor gets random rows? Usually it is completely fine to cache these X random rows for 1 second (or even 10 seconds). It doesn't matter if 100 unique visitors in the same 1 second get the same random posts, because the next second another 100 visitors will get different set of posts.
When using this caching you can use also some of the slower solution for getting the random data as it will be fetched from MySQL only once per second regardless of your req/s.
I've looked through all of the answers, and I don't think anyone mentions this possibility at all, and I'm not sure why.
If you want utmost simplicity and speed, at a minor cost, then to me it seems to make sense to store a random number against each row in the DB. Just create an extra column, random_number, and set it's default to RAND(). Create an index on this column.
Then when you want to retrieve a row generate a random number in your code (PHP, Perl, whatever) and compare that to the column.
SELECT FROM tbl WHERE random_number >= :random LIMIT 1
I guess although it's very neat for a single row, for ten rows like the OP asked you'd have to call it ten separate times (or come up with a clever tweak that escapes me immediately)
I needed a query to return a large number of random rows from a rather large table. This is what I came up with. First get the maximum record id:
SELECT MAX(id) FROM table_name;
Then substitute that value into:
SELECT * FROM table_name WHERE id > FLOOR(RAND() * max) LIMIT n;
Where max is the maximum record id in the table and n is the number of rows you want in your result set. The assumption is that there are no gaps in the record id's although I doubt it would affect the result if there were (haven't tried it though). I also created this stored procedure to be more generic; pass in the table name and number of rows to be returned. I'm running MySQL 5.5.38 on Windows 2008, 32GB, dual 3GHz E5450, and on a table with 17,361,264 rows it's fairly consistent at ~.03 sec / ~11 sec to return 1,000,000 rows. (times are from MySQL Workbench 6.1; you could also use CEIL instead of FLOOR in the 2nd select statement depending on your preference)
DELIMITER $$
USE [schema name] $$
DROP PROCEDURE IF EXISTS `random_rows` $$
CREATE PROCEDURE `random_rows`(IN tab_name VARCHAR(64), IN num_rows INT)
BEGIN
SET #t = CONCAT('SET #max=(SELECT MAX(id) FROM ',tab_name,')');
PREPARE stmt FROM #t;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SET #t = CONCAT(
'SELECT * FROM ',
tab_name,
' WHERE id>FLOOR(RAND()*#max) LIMIT ',
num_rows);
PREPARE stmt FROM #t;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
END
$$
then
CALL [schema name].random_rows([table name], n);
Here is a game changer that may be helpfully for many;
I have a table with 200k rows, with sequential id's, I needed to pick N random rows, so I opt to generate random values based in the biggest ID in the table, I created this script to find out which is the fastest operation:
logTime();
query("SELECT COUNT(id) FROM tbl");
logTime();
query("SELECT MAX(id) FROM tbl");
logTime();
query("SELECT id FROM tbl ORDER BY id DESC LIMIT 1");
logTime();
The results are:
Count: 36.8418693542479 ms
Max: 0.241041183472 ms
Order: 0.216960906982 ms
Based in this results, order desc is the fastest operation to get the max id,
Here is my answer to the question:
SELECT GROUP_CONCAT(n SEPARATOR ',') g FROM (
SELECT FLOOR(RAND() * (
SELECT id FROM tbl ORDER BY id DESC LIMIT 1
)) n FROM tbl LIMIT 10) a
...
SELECT * FROM tbl WHERE id IN ($result);
FYI: To get 10 random rows from a 200k table, it took me 1.78 ms (including all the operations in the php side)
I used this http://jan.kneschke.de/projects/mysql/order-by-rand/ posted by Riedsio (i used the case of a stored procedure that returns one or more random values):
DROP TEMPORARY TABLE IF EXISTS rands;
CREATE TEMPORARY TABLE rands ( rand_id INT );
loop_me: LOOP
IF cnt < 1 THEN
LEAVE loop_me;
END IF;
INSERT INTO rands
SELECT r1.id
FROM random AS r1 JOIN
(SELECT (RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 1;
SET cnt = cnt - 1;
END LOOP loop_me;
In the article he solves the problem of gaps in ids causing not so random results by maintaining a table (using triggers, etc...see the article);
I'm solving the problem by adding another column to the table, populated with contiguous numbers, starting from 1 (edit: this column is added to the temporary table created by the subquery at runtime, doesn't affect your permanent table):
DROP TEMPORARY TABLE IF EXISTS rands;
CREATE TEMPORARY TABLE rands ( rand_id INT );
loop_me: LOOP
IF cnt < 1 THEN
LEAVE loop_me;
END IF;
SET #no_gaps_id := 0;
INSERT INTO rands
SELECT r1.id
FROM (SELECT id, #no_gaps_id := #no_gaps_id + 1 AS no_gaps_id FROM random) AS r1 JOIN
(SELECT (RAND() *
(SELECT COUNT(*)
FROM random)) AS id)
AS r2
WHERE r1.no_gaps_id >= r2.id
ORDER BY r1.no_gaps_id ASC
LIMIT 1;
SET cnt = cnt - 1;
END LOOP loop_me;
In the article i can see he went to great lengths to optimize the code; i have no ideea if/how much my changes impact the performance but works very well for me.
You can easily use a random offset with a limit
PREPARE stm from 'select * from table limit 10 offset ?';
SET #total = (select count(*) from table);
SET #_offset = FLOOR(RAND() * #total);
EXECUTE stm using #_offset;
You can also apply a where clause like so
PREPARE stm from 'select * from table where available=true limit 10 offset ?';
SET #total = (select count(*) from table where available=true);
SET #_offset = FLOOR(RAND() * #total);
EXECUTE stm using #_offset;
Tested on 600,000 rows (700MB) table query execution took ~0.016sec HDD drive.
EDIT: The offset might take a value close to the end of the table, which will result in the select statement returning less rows (or maybe only 1 row), to avoid this we can check the offset again after declaring it, like so
SET #rows_count = 10;
PREPARE stm from "select * from table where available=true limit ? offset ?";
SET #total = (select count(*) from table where available=true);
SET #_offset = FLOOR(RAND() * #total);
SET #_offset = (SELECT IF(#total-#_offset<#rows_count,#_offset-#rows_count,#_offset));
SET #_offset = (SELECT IF(#_offset<0,0,#_offset));
EXECUTE stm using #rows_count,#_offset;
I know it is not what you want, but the answer I will give you is what I use in production in a small website.
Depending on the quantity of times you access the random value, it is not worthy to use MySQL, just because you won't be able to cache the answer. We have a button there to access a random page, and a user could click in there several times per minute if he wants. This will cause a mass amount of MySQL usage and, at least for me, MySQL is the biggest problem to optimize.
I would go another approach, where you can store in cache the answer. Do one call to your MySQL:
SELECT min(id) as min, max(id) as max FROM your_table
With your min and max Id, you can, in your server, calculate a random number. In python:
random.randint(min, max)
Then, with your random number, you can get a random Id in your Table:
SELECT *
FROM your_table
WHERE id >= %s
ORDER BY id ASC
LIMIT 1
In this method you do two calls to your Database, but you can cache them and don't access the Database for a long period of time, enhancing performance. Note that this is not random if you have holes in your table. Having more than 1 row is easy since you can create the Id using python and do one request for each row, but since they are cached, it's ok.
If you have too many holes in your table, you can try the same approach, but now going for the total number of records:
SELECT COUNT(*) as total FROM your_table
Then in python you go:
random.randint(0, total)
And to fetch a random result you use the LIMIT like bellow:
SELECT *
FROM your_table
ORDER BY id ASC
LIMIT %s, 1
Notice it will get 1 value after X random rows. Even if you have holes in your table, it will be completely random, but it will cost more for your database.
If you want one random record (no matter if there are gapes between ids):
PREPARE stmt FROM 'SELECT * FROM `table_name` LIMIT 1 OFFSET ?';
SET #count = (SELECT
FLOOR(RAND() * COUNT(*))
FROM `table_name`);
EXECUTE stmt USING #count;
Source: https://www.warpconduit.net/2011/03/23/selecting-a-random-record-using-mysql-benchmark-results/#comment-1266
This is super fast and is 100% random even if you have gaps.
Count the number x of rows that you have available SELECT COUNT(*) as rows FROM TABLE
Pick 10 distinct random numbers a_1,a_2,...,a_10 between 0 and x
Query your rows like this: SELECT * FROM TABLE LIMIT 1 offset a_i for i=1,...,10
I found this hack in the book SQL Antipatterns from Bill Karwin.
The following should be fast, unbiased and independent of id column. However it does not guarantee that the number of rows returned will match the number of rows requested.
SELECT *
FROM t
WHERE RAND() < (SELECT 10 / COUNT(*) FROM t)
Explanation: assuming you want 10 rows out of 100 then each row has 1/10 probability of getting SELECTed which could be achieved by WHERE RAND() < 0.1. This approach does not guarantee 10 rows; but if the query is run enough times the average number of rows per execution will be around 10 and each row in the table will be selected evenly.
If you have just one Read-Request
Combine the answer of #redsio with a temp-table (600K is not that much):
DROP TEMPORARY TABLE IF EXISTS tmp_randorder;
CREATE TABLE tmp_randorder (id int(11) not null auto_increment primary key, data_id int(11));
INSERT INTO tmp_randorder (data_id) select id from datatable;
And then take a version of #redsios Answer:
SELECT dt.*
FROM
(SELECT (RAND() *
(SELECT MAX(id)
FROM tmp_randorder)) AS id)
AS rnd
INNER JOIN tmp_randorder rndo on rndo.id between rnd.id - 10 and rnd.id + 10
INNER JOIN datatable AS dt on dt.id = rndo.data_id
ORDER BY abs(rndo.id - rnd.id)
LIMIT 1;
If the table is big, you can sieve on the first part:
INSERT INTO tmp_randorder (data_id) select id from datatable where rand() < 0.01;
If you have many read-requests
Version: You could keep the table tmp_randorder persistent, call it datatable_idlist. Recreate that table in certain intervals (day, hour), since it also will get holes. If your table gets really big, you could also refill holes
select l.data_id as whole
from datatable_idlist l
left join datatable dt on dt.id = l.data_id
where dt.id is null;
Version: Give your Dataset a random_sortorder column either directly in datatable or in a persistent extra table datatable_sortorder. Index that column. Generate a Random-Value in your Application (I'll call it $rand).
select l.*
from datatable l
order by abs(random_sortorder - $rand) desc
limit 1;
This solution discriminates the 'edge rows' with the highest and the lowest random_sortorder, so rearrange them in intervals (once a day).
Another simple solution would be ranking the rows and fetch one of them randomly and with this solution you won't need to have any 'Id' based column in the table.
SELECT d.* FROM (
SELECT t.*, #rownum := #rownum + 1 AS rank
FROM mytable AS t,
(SELECT #rownum := 0) AS r,
(SELECT #cnt := (SELECT RAND() * (SELECT COUNT(*) FROM mytable))) AS n
) d WHERE rank >= #cnt LIMIT 10;
You can change the limit value as per your need to access as many rows as you want but that would mostly be consecutive values.
However, if you don't want consecutive random values then you can fetch a bigger sample and select randomly from it. something like ...
SELECT * FROM (
SELECT d.* FROM (
SELECT c.*, #rownum := #rownum + 1 AS rank
FROM buildbrain.`commits` AS c,
(SELECT #rownum := 0) AS r,
(SELECT #cnt := (SELECT RAND() * (SELECT COUNT(*) FROM buildbrain.`commits`))) AS rnd
) d
WHERE rank >= #cnt LIMIT 10000
) t ORDER BY RAND() LIMIT 10;
One way that i find pretty good if there's an autogenerated id is to use the modulo operator '%'. For Example, if you need 10,000 random records out 70,000, you could simplify this by saying you need 1 out of every 7 rows. This can be simplified in this query:
SELECT * FROM
table
WHERE
id %
FLOOR(
(SELECT count(1) FROM table)
/ 10000
) = 0;
If the result of dividing target rows by total available is not an integer, you will have some extra rows than what you asked for, so you should add a LIMIT clause to help you trim the result set like this:
SELECT * FROM
table
WHERE
id %
FLOOR(
(SELECT count(1) FROM table)
/ 10000
) = 0
LIMIT 10000;
This does require a full scan, but it is faster than ORDER BY RAND, and in my opinion simpler to understand than other options mentioned in this thread. Also if the system that writes to the DB creates sets of rows in batches you might not get such a random result as you where expecting.
I think here is a simple and yet faster way, I tested it on the live server in comparison with a few above answer and it was faster.
SELECT * FROM `table_name` WHERE id >= (SELECT FLOOR( MAX(id) * RAND()) FROM `table_name` ) ORDER BY id LIMIT 30;
//Took 0.0014secs against a table of 130 rows
SELECT * FROM `table_name` WHERE 1 ORDER BY RAND() LIMIT 30
//Took 0.0042secs against a table of 130 rows
SELECT name
FROM random AS r1 JOIN
(SELECT CEIL(RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 30
//Took 0.0040secs against a table of 130 rows
SELECT
*
FROM
table_with_600k_rows
WHERE
RAND( )
ORDER BY
id DESC
LIMIT 30;
id is the primary key, sorted by id,
EXPLAIN table_with_600k_rows, find that row does not scan the entire table
I Use this query:
select floor(RAND() * (SELECT MAX(key) FROM table)) from table limit 10
query time:0.016s
This is how I do it:
select *
from table_with_600k_rows
where rand() < 10/600000
limit 10
I like it because does not require other tables, it is simple to write, and it is very fast to execute.
Use the below simple query to get random data from a table.
SELECT user_firstname ,
COUNT(DISTINCT usr_fk_id) cnt
FROM userdetails
GROUP BY usr_fk_id
ORDER BY cnt ASC
LIMIT 10
I guess this is the best possible way..
SELECT id, id * RAND( ) AS random_no, first_name, last_name
FROM user
ORDER BY random_no
I have database table as below.
id, bungalow_name, type, address, featured
A bungalow can be featured in the home page. If a bungalow is featured, featured column has the value 1. I have 50 bungalows in the tables and 5-7 bungalows are featured at a given time.
Let's assume featured bungalow names are as below.
bungalow 1, bungalow 2, bungalow 3, .........., bungalow 6
What I'm trying to do is show a featured bungalow in the home page for each day. And I want to loop like below as below for each month. Given that I don't want to show a bungalow randomly for each page load. I want to show per day one bungalow basis.
today -> bungalow 1
tomorrow -> bungalow 2
day after tomorrow -> bungalow 3
...
After bungalow 6, bungalow 1 is shown on the next day.
How can I do it? Is it even possible with SQL/PHP?
You could use this MySQL query:
SELECT *
FROM Bungalows
WHERE id = (
SELECT b1.id
FROM
Bungalows b1 LEFT JOIN Bungalows b2
ON b1.id>b2.id AND b2.featured=1
WHERE
b1.featured=1
GROUP BY
b1.id
HAVING
COUNT(b2.id) = (SELECT
DATEDIFF(CURDATE(), '2013-05-06') MOD
(SELECT COUNT(*) FROM Bungalows WHERE Featured=1))
)
Please see fiddle here. '2013-05-06' is the day when you want to start to show the first featured bungalow. They will be shown ordered by ID, strarting from '2013-05-06'.
EDIT
The following query will return the number of elapsed days since 2013-05-06:
SELECT DATEDIFF(CURDATE(), '2013-05-06')
the MOD function will return the integer remainder of the division of the number of elapsed day by the number of featured rows:
SELECT DATEDIFF(CURDATE(), '2013-05-06') MOD
(SELECT COUNT(*) FROM Bungalows WHERE Featured=1)
If there are 6 featured bungalows, it will return 0 the first day,1 the second,2,3,4,5, and then 0,1,2...again.
MySQL does not have a function to return a RANK (number of row), so you have to simulate it somehow. I simulated it this way:
SELECT b1.id, COUNT(b2.id)
FROM
Bungalows b1 LEFT JOIN Bungalows b2
ON b1.id>b2.id AND b2.featured=1
WHERE
b1.featured=1
GROUP BY
b1.id
I'm joining the Bungalows table with itself. The rank of bungalow ID is the count of bungalows that have an ID less than that (hence the join b1.id>b2.id).
I'm then selecting only the row that have the RANK returned by the function above:
HAVING
COUNT(b2.id) = (SELECT
DATEDIFF(CURDATE(), '2013-05-06') MOD
(SELECT COUNT(*) FROM Bungalows WHERE Featured=1))
If you use MySQL, my initial query could be simplified as this:
SELECT b1.*
FROM
Bungalows b1 LEFT JOIN Bungalows b2
ON b1.id>b2.id AND b2.featured=1
WHERE
b1.featured=1
GROUP BY
b1.id
HAVING
COUNT(b2.id) = (SELECT
DATEDIFF(CURDATE(), '2013-05-06') MOD
(SELECT COUNT(*) FROM Bungalows WHERE Featured=1))
$dbh = new PDO(....); // use your connection data
$statement = $dbh->query("SELECT count(*) as size FROM bungalows where features = 1");
$data = $statement->fetchALL(PDO::FETCH_CLASS,"stdClass");
$i = date('z') % $data[0]->size;
$statement = $dbh->query("SELECT * FROM bungalows where features = 1 order by id LIMIT $i,1");
$bungalow = reset($statement->fetchALL(PDO::FETCH_CLASS,"stdClass"));
EDIT
Removed mysql_ calls
added an order clause as fthiella suggested (thank you :) )
Try this query it will work in every case with increase in number of featured bungalows etc
and daily will give a different one.
Here in the query I am assigning numbers to each featured bungalow from 0 to n and receiving then by dividing total number of featured bungalow to date diff I find the bungalow to be displayed.
Query 1:
select
a.*
from
(select
#rn:=#rn+1 as rId,
b.cnt,
a.*
from
Bunglows a
join
(select #rn:=-1) tmp
join
(select
count(*) as cnt
from
Bunglows
where
featured=1)b
where
featured=1) a
where
datediff(CURDATE(), '2013-01-01')%a.cnt=a.rId
SQL FIDDLE:
| RID | CNT | ID | BUNGALOW_NAME | FEATURED |
---------------------------------------------
| 3 | 4 | 6 | bungalow 4 | 1 |
EDIT
select count(*) as cnt from Bunglows where featured=1
This query finds the total featured bungalows
select #rn:=#rn+1 as rId, b.cnt, a.* from Bunglows a join (select #rn:=-1) tmp join select count(*) as cnt from Bunglows where featured=1
This query adds the a rownumber to each featured bungalow starting from 0 to n
The main query first finds date diff from current date and a old date and find mod value by total featured bungalows which will give values from 0 to n-1 and I have added a where clause which checks for the divided value to be equal to the rowid which we have assigned..
Hope this helps...
The basic concept of my answer is to;
1/ Create a list of all featured bungalows. This is achieved in the sub-query, where each bungalow is given a unique sequence number. The code for the seq_num field is based on the answer here
2/ Pick a single bungalow from that listed based on where we are in the month. To do this I look at the day of the month for today, using the code day(curdate()) and I find the mod of that number to the total number of featured bungalows.
select sq.bungalow_name
from (
select bungalow_name
,#curRow := #curRow + 1 AS seq_num
from table1, (SELECT #curRow := 0) r
where featured = 1
order by
bungalow_name desc
) sq
where sq.seq_num = mod(day(curdate()),(select count(*) from table1 where featured = 1))
Example at this SQL Fiddle
You have to track the last date of display for each featured record (last_viewed).
For new records, set this date to a day in the past, eg. 2000-01-01.
If there is a record with the current date, use that.
In not, use the record with the earliest date.
SELECT *, IF(DATE(last_viewed)=CURDATE(), 1, 0) AS current
FROM #__bungalows
WHERE featured=1
ORDER BY current DESC, last_viewed ASC
LIMIT 0,1
Like the hit counter in com_content, you should add a hit method to your bungalow model, which sets the last_viewed column of the selected bungalow to now().
select ....
where featured = 1
limit DAYOFYEAR(NOW()) % (select count(*) from ... where featured = 1), 1
I'm not sure if subselect is allowed in limit. You may have to perform that query separately. This will rotate every day. Easy peasy lemon squeezy.
edit: to perform in 2 queries
$query = "SELECT COUNT(*) FROM ... WHERE FEATURED = 1";
$count = intval(array_pop(mysql_fetch_assoc(mysql_query($query))));
$query = "
select ....
where featured = 1
limit DAYOFYEAR(NOW()) % {$count}, 1
";
DONE!
The modulo-operator % does the trick:
First, add a column "counter int".
Next, number the featured columns like 1,2,3... if you are lazy, you can use this:
set #cc=0;
update bungalows set counter=(select #cc:=#cc+1) where featured=1;
Now, everything is prepared and you simply can do a first select:
select * from bungalows where featured=1 and counter%(select count(*) from bungalows where featured=1)=0;
And everytime before you need the next featured bungalows, do a:
update bungalows set counter=counter+1 where featured=1;
Then again:
select * from bungalows where featured=1 and counter%(select count(*) from bungalows where featured=1)=0;
...
update bungalows set counter=counter+1 where featured=1;
and so on...
Check here with SQLFiddle
SELECT *
FROM bungalows b
JOIN (SELECT
( DAYOFMONTH(CURDATE() ) % COUNT(b2.id) ) AS slab,
COUNT(b2.id) AS total_count
FROM bungalows b2
WHERE b2.featured = 1) AS b3
WHERE IF(b3.slab = 0, b3.total_count, b3.slab) = (SELECT
COUNT(id)
FROM bungalows b1
WHERE b.id >= b1.id
AND b1.featured = 1)
AND b.featured = 1
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Mysql rank function
I have the following countryTable
country clicks
------- ------
0 222
66 34
175 1000
45 650
How do I get the ranking of say country 45 which is 2 in this case?
Ordered by country ASC:
SELECT 1+COUNT(*) AS ranking
FROM countryTable
WHERE country < 45 ;
Ordered by clicks DESC:
SELECT 1+COUNT(*) AS ranking
FROM countryTable AS t
JOIN countryTable AS c
ON c.clicks > t.clicks
WHERE t.country = 45 ;
You can get 2 rank as below it like below:
Select * from tabeName order by clicks limit 1,1
For 3 rank:
Select * from tabeName order by clicks limit 2,1
SELECT *
FROM
(
SELECT #ranking:= #ranking + 1 rank,
a.country,
a.clicks
FROM tableName a, (SELECT #ranking := 0) b
ORDER BY a.clicks DESC
) s
WHERE country = 45
SQLFiddle Demo
This will show the correct rank (2) for country 45. You don't specify how to rank ties, so you may want to change the comparison to suit you. Non existing countries rank as 0.
SELECT COUNT(*) rank
FROM countryTable a
JOIN countryTable b
ON a.clicks <= b.clicks
WHERE a.country = 45
SQLfiddle here.
X is the rank you need to look for:
SELECT * FROM T ORDER BY clicks DESC LIMIT X-1,1
Here's another (stunningly fast) way (albeit limited to 256 rows):
SELECT country
, clicks
, FIND_IN_SET(clicks,(SELECT GROUP_CONCAT(DISTINCT clicks ORDER BY clicks DESC) FROM country_clicks)) rank
FROM country_clicks
or, if you prefer...
SELECT FIND_IN_SET(clicks,(SELECT GROUP_CONCAT(DISTINCT clicks ORDER BY clicks DESC) FROM country_clicks)) rank
FROM country_clicks
WHERE country = 45;