php : Issue on multidimensional array with PMA - php

Question

i'm working with php (ubuntu software).
I have some data into a PMA database, that i extract like this :
<?php
try
{
$db = mysql_connect('localhost', 'dbName', 'dbPwd');
mysql_select_db('dbName', $db);
}
catch(Exception $e)
{
die('Erreur : '. $e->getMessage());
}
$sql = "SELECT p.ean13, pl.id_product, pl.name FROM $product_lang pl INNER JOIN $product p ON pl.id_product = p.id_product WHERE name LIKE '1 agapanthe %'";
$result_agpt = mysql_query($sql, $db);
$data = mysql_fetch_row($result_agpt);
Now that I have my data into an array like this :
ean13 - id_product - name
NULL - 5389 - 1 agapanthe ivoire //////////////////////////////////////////////////////////////////////////////////////////////////////////////
4027234262147 - 5387 - 1 agapanthe lilas ////////////////////////////////////////////////////////////////////////////////////////////////
NULL - 5388 - 1 agapanthe parme ////////////////////////////////////////////////////////////////////////////////////////////////////////////
NULL - 5386 - 1 agapanthe violet //////////////////////////////////////////////////////////////////////////////////////////////////////////////
I want to display, for each row of my result, the following informations :
ean13 : NULL ////
id_product : 5389 ////
product_name : 1 agapanthe ivoire
And for each of this row, i must truncate the name like this :
"1 agapanthe ivoire" => "1 agapanthe"
I'm doing this using the preg_match function, as below :
foreach($data as $value)
{
// preg_match to truncate product names : '1 agapanthe verte' => '1 agapanthe'
$pattern = '/^(1\sagapanthe)\s(\w*)/is';
$match_truncate = preg_match($pattern, $data[2], $matches);
$name = $matches[1];
echo "Name : ".$name; echo "<br />";echo "<br />";
$attribute = $matches[2];
echo "Attribut : ".$attribute; echo "<br />";
I tried several ways of doing this foreach, but i can't manage to make it work.
EDIT : My aim here is to truncate every name of my product, as to modify its content into PMA. Should I consider using PDO over mysql connection ?
Any help or comment would be greatly appreciated :) !
Regards,
Stelio Kontos.

Answer 1

You appear to have several issues here. First, and most important is stop using the mysql database extension. Instead use mysqli or pdo. The older mysql extension is deprecated in all supported version of PHP, and has been dropped from PHP 7.0.
Second the manner in which you built your SQL string is susceptible to SQL Injection. It is always a bad idea to concatenate data that could come from a user into an sql statement string. Even if it passes through the database first. Best way is to use parameterized sql strings which is available in mysqli and pdo (but not mysql).
Here is a link to the docs http://php.net/manual/en/function.mysql-fetch-row.php
But to answer your question, using the mysql extension, the fetch needs to be inside the loop. It returns a single row at a time as an array with numerical indexes. So after:
$data = mysql_fetch_row($result_agpt);
$data will contain
[0] => 'NULL',
[1] => 5389,
[2] => '1 agapanthe ivoire'
The foreach is incorrect in this instance. You will need to do something more like
$data = mysql_fetch_row($result_agpt);
while($data !== false) {
$ean13 = $data[0];
$id = $data[1];
$name = $data[2];
// do something with it
$data = mysql_fetch_row($result_agpt);
}
Finally, regular expressions are hard to get just right. I use an online regex tester like the one at https://regex101.com/ to make sure my patterns work. Here is one I think might work for you /([0-9]+ \w+) (\w+)/is.

Answer 2

Not sure if I understand the question properly, but if you want to display only portion of the value from the database column pl.name, you could rework the SQL query:
$sql = "SELECT p.ean13, pl.id_product, '1 agapanthe' FROM $product_lang pl INNER JOIN $product p ON pl.id_product = p.id_product WHERE name LIKE '1 agapanthe %'"
The above query will display always 1 agapanthe as product name, no need for complex regular expressions here ;)
EDIT:
You can provide the portion for the LIKE clause dynamically and then use it to select it as column:
$like = "something";
$sql = "SELECT p.ean13, pl.id_product, '".$like."' FROM $product_lang pl INNER JOIN $product p ON pl.id_product = p.id_product WHERE name LIKE '".$like."%'";
Also - do not forget to escape the contents, if they are going to be user-defined or use prepared statements and PDO to access/query your database. This way you will be protected from SQL injection attacks.