I am trying print out a table that has student testimonials and I want to print out the ID, title, text and student ID but when hit the "search_all" button, I am told that it can't fetch mysqli and I am not sure what to do.
<?php ("session.php"); ?>
<?php require_once("connect.php"); ?>
<?php include("header.php"); ?>
<html>
<body>
<!-- Page Content -->
<h1 class="page-header">Learning Journals
<small>- Admin Search</small>
</h1>
<h3>Search Learning Journals</h3>
<form name="membership_form" action= "<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" id="contactForm" method="post">
<label>Search Journals ID:</label>
<br>
<input type="text" name="journal_search">
<br>
<button type="submit" name ="search_all" class="btn btn-primary">All Journals</button>
</form>
<?php
if(isset($_POST["search_button"]))
{
//create the sql statement
$sql_all= "SELECT * FROM testimonials";
$result = mysqli_query($con,$sql_all);
while ($row = mysqli_fetch_assoc($result))
{
echo
"<h4>Testimonial ID:</h4>". $row["testimonial_ID"].
"<h4>Title:</h4> ". $row["testimonial_title"].
"<h4>Text:</h4> ". $row["testimonial_text"].
"<h4>Student ID:</h4>". $row["student_ID"].
"</br>";
}
mysqli_close($con);
}
include("footer.php");
?>
</body>
</html>
Related
I am currently working on a school project and I need a little help. I am writing PHP/SQL code for a page where, when the user submits a form, a query runs that loops through and displays the user text input and also the value associated with the <select> dropdown.
(For a visual idea of what I mean, visit http://themanaclub.com/themarketplace2/themarketplace2.php)
Here is my code:
<?php
include_once ('connection2.php');
if (($_SERVER["REQUEST_METHOD"] == "POST") && (isset($_POST['card_catalog_form']))) {
$card_name = mysqli_real_escape_string($conn, $_POST['card_name']);
$card_label = mysqli_real_escape_string($conn, $_POST['card_genre']);
$insert_card_genre_query = sprintf("INSERT into card_catalog (card_name, label_id) VALUES ('%s', %u)",
$card_name,
$card_label);
$insert_card_genre = mysqli_query($conn, $insert_card_genre_query) or die (mysqli_error($conn));
$last_record = mysqli_insert_id($conn);
}
$card_genre_query = "SELECT card_genre.genre_id, card_label from `card_genre` order by genre_id desc";
$card_genre = mysqli_query($conn, $card_genre_query) or die(mysqli_error($conn));
$get_card_genre_query = "SELECT card_catalog.id, card_name, label_id, card_label from card_catalog left join card_genre on label_id = genre_id";
$get_card_genre = mysqli_query($conn, $get_card_genre_query) or die(mysqli_error($conn));
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>The Marketplace By The Mana Club</title>
<link rel="stylesheet" type="text/css" href="stylesheets2/tmp2.css">
</head>
<body>
<?php include('templatestuff2/top_of_tmp2.php'); ?>
<main>
<h1>Card Input Form:</h1>
<form id="card_name_entry" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post" enctype="multipart/form-data">
<h4>What Card Are You Looking For?</h4>
<textarea name="card_label" rows="5" cols="30" placeholder="Write the name of the card here"></textarea>
<p>
<select name="card_genre">
<?php while ($row_card_genre = mysqli_fetch_assoc($card_genre)) { ?>
<option value="<?php echo $row_card_genre['genre_id'];?>"><?php echo $row_card_genre['card_label'];?><?php echo $row_card_genre['card_name'];?></option>
<?php } ?>
</select>
</p>
<?php $query = "SELECT label_id from `card_catalog` right join `card_genre` on genre_id"; ?>
<p id="textareasubmit"><input type="submit"></p>
<input type="hidden" name="card_catalog_form">
</form>
<section id="all_questions">
<ul>
<?php while ($row_card_genre = mysqli_fetch_assoc($get_card_genre)) { ?>
<li><?php echo $row_card_genre['card_label'];?></li>
<?php }
$row_card_genre = mysqli_data_seek($get_card_genre, 0);
?>
</ul>
</section>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="post" enctype="multipart/form-data">
<p id="deletethissubmit"><input type="submit" value="Delete This"></p>
<input type="hidden" name="card_catalog_delete">
<input type="hidden" name="genre_id" value="<?php echo $row_card_catalog['label_id'];?>"
</form>
<p>You're asking this at
<?php
date_default_timezone_set('America/New_York');
echo date('g:i a T \o\n l, F j, Y');
?>
</p>
<p id="backtothemarketplace">Back To The Marketplace</p>
<?php
/*if (isset($_POST['card_genre'])) {
$query = "SELECT card_catalog.card_name, card_catalog.label_id, card_genre.genre_id, card_genre.card_label FROM card_catalog, card_genre WHERE card_genre.genre_id = ?";
$stmt = mysqli_prepare($conn, $query);
$stmt->bind_param('s', $_POST['card_genre']);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
echo $row['card_name']." - ".$row['label_id'];
echo "<br />";
}
}*/
?>
</main>
<?php include('templatestuff2/bottom_of_tmp2.php'); ?>
</body>
</html>
If anybody has any help or constructive criticism, it would be greatly appreciated (I'm a PHP/SQL newbie so I'll take all the help that I can get).
Thanks
Messed around with the code and I fixed it. The id is now being displayed and it links to the correct page.
All that was wrong with my code was that I mixed up some of the variables and ids.
Thank you all for your help.
this is what i want to do, i have two pages, first is the "edit.php" and second is the "edit2.php". the page "edit.php" this is the page where all the news is shown and you will select what news you will edit by clicking the "edit button" and the "edit2.php" where will i exactly edit the news. i want to pass the value of the selected news in another page. But here is the problem, when i clicked the "Sample news 1" edit button the data showing in another page is the "Sample news 2". Even when i clicked the "Sample news 2" edit button, the data is also the "Sample news 2". Can someone give me ideas on how to fix this?
here is the picture of edit.php. I click the edit button of "Sample news 1".
here is the picture of edit2.php. and this is the output data. The data should be "Sample news 1" not "Samplel news 2".
here is my php code in edit.php
<?php
session_start();
include_once('connection.php');
$sql ="SELECT * FROM news ORDER BY news_id";
$result = mysqli_query($con, $sql);
while($row = mysqli_fetch_array($result)){
$newsid = $row['news_id'];
$title = $row['news_title'];
$date = $row['news_date'];
$content = $row['news_content'];
$newsimage = $row['news_image'];
if(isset($_POST['esubmit'])){
$_SESSION['news_id'] = $newsid;
$_SESSION['n_title'] = $title;
$_SESSION['n_date'] = $date;
$_SESSION['n_content'] = $content;
$_SESSION['n_image'] = $newsimage;
header('Location: edit2.php');
}
?>
<div class="fix single_news">
<div class="single_image">
<img src="<?php echo $newsimage; ?>" style="width:200px; height:140px; alt="court">
</div>
<?php echo $title; ?>
<p><?php echo $date; ?></p>
<p><?php echo $content; ?></p>
</div>
<form action="" method="post">
<input type="submit" name="esubmit" value="edit" />
</form>
<hr>
<?php
}
?>
here is my php code for "edit2.php"
<?php
session_start();
?>
<!DOCTYPE HTML>
<html>
<head>
</head>
<body>
<form method="post" action ="" enctype="multipart/form-data">
Title<input type ="text" name ="title" value="<?php echo $_SESSION['n_title']; ?>"/><br>
Date<input type ="text" name="date" value="<?php echo $_SESSION['n_date']; ?>" /><br>
Content<textarea name="content"><?php echo $_SESSION['n_content']; ?></textarea>
<input type="submit" name="submit" value="Update" />
<input class="form-control" id="image" name="image" type="file" accept="image/*" onchange='AlertFilesize();'/>
<img id="blah" src="<?php echo $_SESSION['n_image']; ?>" alt="your image" style="width:200px; height:140px;"/>
</form>
<hr>
<script src="js/jquery-1.12.4.min.js"></script>
<script src="js/bootstrap.min.js"></script>
</body>
</html>
Remove if(isset($_POST['esubmit'])){ code out of while loop and add values in form as I shown in below example
Pass $newsid in edit form as hidden and retrieve the content based on new
<form action="" method="post">
<input type='hidden' value="<?php echo $newsid;?>" name="news_id">
<input type="submit" name="esubmit" value="edit" />
</form>
and in your php add this line.
if(isset($_POST['esubmit'])){
$_SESSION['news_id'] = $_POST['news_id'];
The problem is, in each iteration of while loop you're overwriting $newsid, $title, $date,... variables. So when you submit the form, the last row's data will get stored in the corresponding $_SESSION variables.
So here's the solution to your problem.
You don't need $_SESSION to pass the form values to edit2.php page, instead change the <form> element in the following way,
<form action="edit2.php?news_id=<?php echo $newsid; ?>" method="post">
On edit2.php page, first catch the news_id value using $_GET superglobal , like this:
$newsid = $_GET['news_id'];
And then get the appropriate news details using this $newsid, and finally populate the form.
Here's the complete code,
edit.php
<?php
include_once('connection.php');
$sql ="SELECT * FROM news ORDER BY news_id";
$result = mysqli_query($con, $sql);
while($row = mysqli_fetch_array($result)){
$newsid = $row['news_id'];
$title = $row['news_title'];
$date = $row['news_date'];
$content = $row['news_content'];
$newsimage = $row['news_image'];
?>
<div class="fix single_news">
<div class="single_image">
<img src="<?php echo $newsimage; ?>" style="width:200px; height:140px; alt="court">
</div>
<?php echo $title; ?>
<p><?php echo $date; ?></p>
<p><?php echo $content; ?></p>
</div>
<form action="edit2.php?news_id=<?php echo $newsid; ?>" method="post">
<input type="submit" name="esubmit" value="edit" />
</form>
<hr>
<?php
}
?>
edit2.php
<?php
if(isset($_POST['esubmit'])){
$newsid = $_GET['news_id'];
include_once('connection.php');
/* create a prepared statement */
if ($stmt = mysqli_prepare($con, "SELECT * FROM news WHERE news_id = ? LIMIT 1")) {
/* bind parameters */
mysqli_stmt_bind_param($stmt, "s", $newsid);
/* execute query */
mysqli_stmt_execute($stmt);
/* get the result set */
$result = mysqli_stmt_get_result($stmt);
/* fetch row from the result set */
$row = mysqli_fetch_array($result);
}
}
if(isset($_POST['submit'])){
// Write code to commit the edit details
}
?>
<!DOCTYPE HTML>
<html>
<head>
</head>
<body>
<?php
if(isset($_POST['esubmit'])){
?>
<form method="post" action ="edit2.php?news_id=<?php echo $row['news_id']; ?>" enctype="multipart/form-data">
Title<input type ="text" name ="title" value="<?php echo $row['news_title']; ?>"/><br>
Date<input type ="text" name="date" value="<?php echo $row['news_date']; ?>" /><br>
Content<textarea name="content"><?php echo $row['news_content']; ?></textarea>
<input class="form-control" id="image" name="image" type="file" accept="image/*" onchange='AlertFilesize();'/>
<img id="blah" src="<?php echo $row['news_image']; ?>" alt="your image" style="width:200px; height:140px;"/>
<input type="submit" name="submit" value="Update" />
</form>
<?php
}
?>
<script src="js/jquery-1.12.4.min.js"></script>
<script src="js/bootstrap.min.js"></script>
</body>
</html>
Here is the issue, You are looping your data to the session, usually single session keeps only a value. Since that final item of your loop will store on the session [in this case it is 'Sample news 2']. I believe, you can place it on a hidden field & post it to the next page or you can use URL Parameter [GET], to pass the Id to the next page.
Ex : <a href ='edit2.php?newsId ='<?php echo $newsid?>> Edit </a>
what I think is happening is when you are clicking edit button this edit.php page is again reloading and that sql query is running again that's why it is taking value of first image in both cases.what I suggest you to try is use $_get[] instead of $_SESSION and $_POST and pass value of image id directly to page edit2.php and query others details from database in that page and then display it.try it
Remove <form> and <input> use just <a> instead like this.
<a href='edit2.php?id=$news_id'>Edit</a>
and then fetch this id in edit2.php like following
$news_id=$_GET['id'];
and atlast fetch other details of news from the database using this id like'
$query='select * from news where news_id=$news_id';
I am new in php my query is, how to display data in a text box after an insertion operation. I've a page where I can set the input fields and when I click save button the inputs will be inserted in database and will stay in the same page. This is a product page where a list of products are available and there is an edit and delete button in each row. Now i will click on edit button the data can be edited in the same page.. I'm creating an admin panel.
<div class="panel-body">
<form role="form" method="post" enctype="multipart/form-data" name="myform" action="<?php $_SESSION['PHP_SELF']?>">
<br/>
<label>Select Category:</label>
<div class="form-group">
<?php
include('config.php');
$query1=mysql_query("select catnm from addcategory");
?>
<select class=form-control m-b-10 name=catnm id=catnm>
<?php
echo"<option>---select---</option required>";
while($query=mysql_fetch_array($query1))
{
echo "<option value=$query[catnm]>$query[catnm]</option>";
}
?>
</select>
<br/>
<div class="form-group">
<input type="text" class="form-control" id="prodnm" placeholder="Product Name" name="prodnm" required value="<?php
echo $query4['prodnm'];
?> " />
</body>
<?php
//coding for insert .
$catnm=$_POST['catnm'];
$prodnm=$_POST['prodnm'];
$prod_dtl=$_POST['prod_dtl'];
//$updates=$_POST['downld'];
$date=$_POST['date'];
$query=("insert into addproduct(catnm,prodnm,prod_dtl,pdf,downld,date)
values('$catnm','$prodnm','$prod_dtl','$uploadPath','$updates','$date')");
$result = mysql_query($query,$conn);
echo"record inserted";
if($result)
{
header("location:addProduct.php");
}
?>
<?php
//coding for update.
include('config.php');
if(isset($_GET['id']))
{
$id=$_GET['id'];
echo $_SERVER['QUERY_STRING'];
if(isset($_POST['submit']))
{
$updates['downld'] = isset($_POST['downld']) ? 'Yes' : 'No';
$cat['catnm']=$_GET['catnm'];
$prodnm['prodnm']=$_GET['prodnm'];
if($query3)
{
header('location:addProduct.php');
}
}
$query1=mysql_query("select * from addproduct where id='$id'");
$query4=mysql_fetch_array($query1);
?>
The idea is the page in which you select a category from drop-down menu, then after you click remove button, new form shows(contains yes/no buttons) that asks you if you really want to remove selected category. Problem is the second yes/no script. It works on separate page, but on page with first form it doesn't echo anything nor does it remove a pet. Please help, thanks!
<?php
/*remove a category*/
include("connection.php");
?>
<html><head></head>
<body>
<?php
$PetListquery= "SELECT distinct petType From petType ORDER by petType";
$PetListResult= mysqli_query($cxn,$PetListquery) or die ("Couldn't execute query.");
?>
<div style="border:2px solid;">
<form method="POST" action="removeCategory.php">
<div align='left'>
Choose category you want to remove:
<select name='petType'>
<option value='-1'>Type:</option>
<?php
while($row = mysqli_fetch_assoc($PetListResult))
{
extract($row);
?>
<option value='<?php echo $petType;?>' ><?php echo $petType;?> </option>
<?php }?>
</select>
</div>
<div>
<p><input type='submit' name='Remove' value='Remove Category' />
</div>
</div>
</form>
<?php
foreach($_POST as $field => $value)
{ //second form starts after if
if($field == 'petType')
{
?>
<form method="POST" action="<?php echo $_SERVER['PHP_SELF']?>">
<div>
<input name="Yes" type="submit" value="Yes">
<input name="No" type="submit" value="No">
</div>
</form>
<?php
echo "Are you sure you want to delete selected category?";
//clicking any of these buttons doesn't display anything
if(isset($_POST['Yes']))
{
echo "yes";
$DeleteQuery= "DELETE From petType WHERE petType='$petType'";
$DeleteResult= mysqli_query($cxn,$DeleteQuery) or die ("Error1!");
}
if(isset($_POST['No']))
{
echo "No!";
}
}
}
?>
</body></html>
I am trying to make another page to appear when I click certain button, I basically know how to do this, but this time I am in trouble.I have following code:
<html>
<head>
<meta charset="UTF-8"/>
</head>
<body>
<!--See siin all tekstiväli-->
<H3>Minu küsitlused </H3>
<hr>
<br>
<br>
<br>
<ol>
<?php
include_once 'init/init.funcs.php';
$result = mysql_query('SELECT * from katse_kysimustik_pealkiri');
while($row = mysql_fetch_assoc($result)) {
$titles[] = $row['pealkiri'];
}
foreach($titles as $title) {
?>
<li>
<?php echo $title ?>
<form action='Minu_kysitlused_1.php'>
<input type="button" name = "saada" value="saada">
<input type="button" value="tulemused">
<input type="button" value="lõpeta ennetähtaegselt">
<input type="button" value="X">
</li>
</form>
<?php
}
?>
</ol>
</body>
</html>
<?php
if(isset($_POST['saada'])){
echo "<meta http-equiv='refresh' content='0;url=http://localhost/Praks/saada.html'>";
}
?>
Everything works just fine but when I click button 'saada' nothing happens. What should I do to make saada.html appear on this click?
replace this:
<form action='Minu_kysitlused_1.php' method="post">
Missing:
method="post"
why you try with meta tag
You just put header("location:yourpagename");
just like below
if(isset($_POST['saada'])){
header("Location:http://localhost/Praks/saada.html");
}
try like this
header function must be First thing to sent as html otherwise it will not work
<?php
if(isset($_POST['saada'])){
header( "Location : localhost/Praks/saada.html");
die();
}
?>
<html>
<head>
<meta charset="UTF-8"/>
</head>
<body>
<!--See siin all tekstiväli-->
<H3>Minu küsitlused </H3>
<hr>
<br>
<br>
<br>
<ol>
<?php
include_once 'init/init.funcs.php';
$result = mysql_query('SELECT * from katse_kysimustik_pealkiri');
while($row = mysql_fetch_assoc($result)) {
$titles[] = $row['pealkiri'];
}
foreach($titles as $title) {
?>
<li>
<?php echo $title ?>
<form action='Minu_kysitlused_1.php'>
<input type="button" name = "saada" value="saada">
<input type="button" value="tulemused">
<input type="button" value="lõpeta ennetähtaegselt">
<input type="button" value="X">
</li>
</form>
<?php
}
?>
</ol>
</body>
</html>
second approach
<form action="your-url">
<input type="submit" name="Submit" value="saada"/>
</form>
in first time, I don't understand why do you use the form tag to call a page, if there aren't any data passed via POST?
Anyway, in your foreach cicle you can use a very simple collection of link:
foreach($titles as $title) {
echo $title;
echo 'Link 1';
echo 'Link 2';
echo 'Link 3';
echo 'Link 4';
}
This solution is too clean.
Bye
Marco