Passing variable values into another if condition - php

Question

Here is my code and i need to insert array values in $testar in to the table patients_testings. But it doesn't work with this code, where is the error? if i can do this using one global variable. it will be more helpful. thank you.
<form role="form" method="post" action="" name="testing" onsubmit="return validate_form()">
<?php
$sqltestin = "SELECT * FROM testings";
$querytestin = mysqli_query($dbhandle, $sqltestin);
while ($rowtestin = mysqli_fetch_assoc($querytestin)) {
echo '<input type="checkbox" name="testingar[]" value="' . $rowtestin['TestId'] . '">' . $rowtestin['TestName'] . '<br>';
}
?>
<div class="modal-footer">
<input type="submit" name="submittestin" id="submittestin" class="btn btn-success" value="Add Tests">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</form>
</div>
</div>
</div></div>
<?php
$checkBox = '';
$testar = '';
if (isset($_POST['submittestin'])) {
global $checkBox;
global $testar;
$checkBox = $_POST['testingar'];
foreach ($checkBox as $testar1) {
$testar .= $testar1 . ",";
}
$tot = 0.00;
for ($i = 0; $i < sizeof($checkBox); $i++) {
$queryt2 = "SELECT * FROM testings WHERE TestId = $checkBox[$i] ";
$resultt2 = mysqli_query($dbhandle, $queryt2) or die (mysql_error());
while ($rowt2 = mysqli_fetch_assoc($resultt2)) {
echo "<tr><td>" . $rowt2['TestName'] . "</td>";
echo "<td width='100'>" . $rowt2['specimen'] . "</td>";
echo "<td>" . $rowt2['HopePrice'] . "</td></tr>";
//echo '<br/>';
$tot = $tot + $rowt2['HopePrice'];
}
}
echo "<tr><td><b>Total</b></td><td <b>:</b></td><td><b>" . number_format($tot, 2) . "</b></td></tr>";
echo "<tr><td><form role='form' method='post' action=''><input type='submit' name='printinv' id='printinv' class='btn btn-success' value='Print'></form></td></tr>";
//echo $testar;
if (isset($_POST['printinv'])) {
$sqltnum = "INSERT INTO patients_testings VALUES ('$ref_no','$testar')";
if (mysqli_query($dbhandle, $sqltnum) or die (mysql_error())) {
echo "Entered Successfully";
//}
}
}
}
?>

Answer 1

Why your code does not work:
I think the concept that you are missing is that when the page is requested, and on every subsequent form submission, the PHP code is executed then exits which throws out the values of the variables stored in memory. Making the variables global does not make them persist between requests.
Specifics to your code:
The first time the form is submitted isset($_POST['submittestin']) is true and it successfully populates the $testar variable with data. However, on the second post isset($_POST['submittestin']) is false and so you never hit the if (isset($_POST['printinv'])) section. Now, even if you move the if (isset($_POST['printinv'])) outside the first if ... submittestin you still have a problem because the $testar will no longer be populated with data.
Additionally, you use variables which are never initialized anywhere that I can see. $ref_no is an example.
I would also suggest echoing out your DB queries to see if they are properly formatted before you run them. I think that some of them may be missing 's in places.
How to make data persist between requests?
The best way is to start a session. By starting a session you can save variables in the $_SESSION array and then access them durring a different request.
Note: You cannot serialize resorces so you will need to reconnect to the database on each request. I.e., this won't work: $_SESSION['dbhandle'] = $dbhande;
Another way to set <input type=hidden ... elements in your form so that on the second post you can access them again through the $_POST variable.
Attempt to make your code use sessions:
<?php
session_start();
?>
<form role="form" method="post" action="" name="testing" onsubmit="return validate_form()">
<?php
$sqltestin = "SELECT * FROM testings";
$querytestin = mysqli_query($dbhandle, $sqltestin);
while ($rowtestin = mysqli_fetch_assoc($querytestin)) {
echo '<input type="checkbox" name="testingar[]" value="' . $rowtestin['TestId'] . '">' . $rowtestin['TestName'] . '<br>';
}
?>
<div class="modal-footer">
<input type="submit" name="submittestin" id="submittestin" class="btn btn-success" value="Add Tests">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</form>
</div>
</div>
</div></div>
<?php
$checkBox = '';
$testar = '';
if (isset($_POST['submittestin'])) {
global $checkBox;
global $testar;
$checkBox = $_POST['testingar'];
foreach ($checkBox as $testar1) {
$testar .= $testar1 . ",";
}
$_SESSION['testar'] = $testar;
$_SESSION['ref_no'] = "This gets used below but I don't see it initialized anywhere?";
$tot = 0.00;
for ($i = 0; $i < sizeof($checkBox); $i++) {
$queryt2 = "SELECT * FROM testings WHERE TestId = '".$checkBox[$i]."'"; // syntax issue here
$resultt2 = mysqli_query($dbhandle, $queryt2) or die (mysql_error());
while ($rowt2 = mysqli_fetch_assoc($resultt2)) {
echo "<tr><td>" . $rowt2['TestName'] . "</td>";
echo "<td width='100'>" . $rowt2['specimen'] . "</td>";
echo "<td>" . $rowt2['HopePrice'] . "</td></tr>";
//echo '<br/>';
$tot = $tot + $rowt2['HopePrice'];
}
}
echo "<tr><td><b>Total</b></td><td <b>:</b></td><td><b>" . number_format($tot, 2) . "</b></td></tr>";
echo "<tr><td><form role='form' method='post' action=''>";
echo "<input type='submit' name='printinv' id='printinv' class='btn btn-success' value='Print'>";
echo "</form></td></tr>";
}
//echo $testar;
if (isset($_POST['printinv'])) {
if(isset($_SESSION['testar']) {
$testar = $_SESSION['testar'];
$ref_no = $_SESSION['refno'];
$sqltnum = "INSERT INTO patients_testings VALUES ('$ref_no', '$testar')"; // Where is $ref_no set?
if (mysqli_query($dbhandle, $sqltnum) or die (mysql_error())) {
echo "Entered Successfully";
}
}
}
?>