How to concatenate a string with a variable to include an image - php

Question

for($i ; $i < $rowcount ; $i++){
/*here i want to add an image to my page.*/
echo"<li class='streep mix'><img src='img/'".$productnaam."'.jpg'\>
<button>
<i class='fa fa-2x fa-shopping-cart' aria-hidden='true'></i>
</button>
</li>";
echo"<li class='gap'></li>";
}
i dont understand how to concatenate the image part

Answer 1

Try like this :
echo "<li class='streep mix'><img src='img/" . $productnaam . ".jpg'\>";
echo "<button>";
echo "<i class='fa fa-2x fa-shopping-cart' aria-hidden='true'></i>";
echo "</button>";
echo "</li>";
echo "<li class='gap'></li>";
Hope it helps.

Answer 2

Most probably; You are looking for something like this:
<?php
// OBSERVE THE PART: <img src='img/" . $productnaam . ".jpg' />
// AS WELL AS THE FORWARD SLASH BEFORE CLOSING THE <IMG /> TAG
echo"<li class='streep mix'><img src='img/" . $productnaam . ".jpg' />
<button>
<i class='fa fa-2x fa-shopping-cart' aria-hidden='true'></i>
</button>
</li>";
echo"<li class='gap'></li>";
However, It would be ideal for you (at this stage) to build up your Output-String in sequences so that you could easily spot any typos or potential quote-related errors without much fuss.
<?php
$output = "";
for($i; $i < $rowcount; $i++){
// EMBED AN IMAGE WITHIN A LIST ITEM
$output .= "<li class='streep mix'>";
$output .= "<img src='img/{$productnaam}.jpg' />"; //<== FORWARD SLASH HERE
// THEN, ADD THE SHOPPING-CART BUTTON
$output .= "<button>";
$output .= "<i class='fa fa-2x fa-shopping-cart' aria-hidden='true'></i>";
$output .= "</button>";
$output .= "</li>";
$output .= "<li class='gap'></li>";
}
echo $output;