how to get the user id of the user in php? - php

Question

im still developing android my android project i really need help, my problem is i couldn't get the user id of the user that login in my system so when they put a record a user id will attached to it data .. i want to do this to output their own data in my system. hope someone could help. its only php code thank you someone who would help.
<?php
// Connection Details altered to hide actual values.
$con = mysqli_connect("localhost", "db_user", "db_password", "db_name");
$username = $_POST['username'];
$password = $_POST['password'];
$sql = "SELECT * FROM tbl_userinfo WHERE username = '$username' AND password='$password' LIMIT 1";
$res = mysqli_query($con,$sql);
$response = array();
$response["success"] = false;
$row = mysqli_fetch_array($res);
if(mysqli_num_rows($res)> 0){
$response["success"] = true;
session_start();
$_SESSION['user_id'] =$userID;
}
echo json_encode($response);
?>
thats for log in, here's for saving data..
<?php
session_start();
$userID ="";
// Connection Details altered to hide actual values.
$con = mysqli_connect("localhost", "db_user", "db_password", "db_name");
if(!isset($_SESSION['user_id'])){
$userID = $_SESSION['user_id'];
$checkdate = $_POST["checkdate"];
$checkno = $_POST["checkno"];
$datepaid = $_POST["datepaid"];
$clientname = $_POST["clientname"];
$bank = $_POST["bank"];
$amount = $_POST["amount"];
$status = "UNFINISHED";
$statement = mysqli_prepare($con, "INSERT INTO tbl_checkinfo (user_id,checkno, checkdate, datepaid, clientname, bank, amount, status) VALUES (?,?, ?, ?, ?,?,?,?)");
mysqli_stmt_bind_param($statement, "iissssis", $userID, $checkno, $checkdate, $datepaid, $clientname, $bank, $amount, $status);
mysqli_stmt_execute($statement);
$response = array();
$response["success"] = false;
if($statement){
$response["success"] = true;
}
echo json_encode($response);
}
?>
and for displaying user data.
<?php
// Connection Details altered to hide actual values.
$con = mysqli_connect("localhost", "db_user", "db_password", "db_name");
$checkdate = $_POST["checkdate"];
$checkno = $_POST["checkno"];
$datepaid = $_POST["datepaid"];
$clientname = $_POST["clientname"];
$bank = $_POST["bank"];
$amount = $_POST["amount"];
$status = "UNFINISHED";
$sql = "Select * from tbl_checkinfo";
$result = mysqli_query($con, $sql);
// $statement = mysqli_prepare($con, "Select * from tbl_checkinfo");
// mysqli_stmt_execute($statement);
// mysqli_stmt_store_result($statement);
// mysqli_stmt_bind_result($statement, $user_id, $checkdate, $checkno, $datepaid, $clientname, $bank, $amount, $status);
$response = array();
$info=array();
$flag = array();
$response["success"] = false;
if( mysqli_num_rows( $result ) > 0 ) {
while($row = mysqli_fetch_array($result))
{
$flag[checkdate]=$row[checkdate];
$flag[checkno]=$row[checkno];
$flag[datepaid]=$row[datepaid];
$flag[clientname]=$row[clientname];
$flag[bank]=$row[bank];
$flag[amount]=$row[amount];
$flag[status]=$row[status];
array_push($info, $flag);
}
$response["success"] = true;
$response["message"] = $info;
echo json_encode($response);
}
else
{
$response["success"] = 0;
$response["message"] = "No entries yet";
echo json_encode($response);
}
?>

Answer 1

Firstly, when posting questions on public forums, please remove your host, DB name, password, etc from the code. :)
Secondly, try to print_r($row) and see on which index is the user id available, then in your code, add this line:
if(mysqli_num_rows($res)> 0){
$response["success"] = true;
$response["user_id"] = $row[USER_ID_INDEX];
session_start();
$_SESSION['user_id'] =$row[USER_ID_INDEX];
}

Answer 2

Where you defined $userID variable, You have to assign proper value to session variable,
if(mysqli_num_rows($res)> 0){
$response["success"] = true;
session_start();
$_SESSION['user_id'] =$row[USER_ID_INDEX];
}

Answer 3

$row['user_id_in_table'] should give you the id.