Here is a code that I've made:
<form method="post" action="test.php">
<input type="text" name="name" placeholder="name"/><br />
<input type="submit" value="Validate" />
</form>
<?php
$sum=0;
if(isset($_POST['name'])){
$sum+=1;
}
echo "sum = $sum";
?>
When I enter some text in the form and click Validate, the page display sum=1, but after this, when I enter nothing in the form and click Validate, the page STILL displays sum=1.
Why does the variable $sum is not reloaded between the two Validate ? Is there a way to escape it ?
Thanks
This will solve the issue
<?php
$sum=0;
if(isset($_POST['name']) && $_POST['name'] != ''){
$sum+=1;
}
echo "sum = $sum";
?>
This is because isset() checks for the existence of the $_POST variable. In your case, the $_POST variable exists and has an empty string value.
Your code will work if you change isset() to !empty() like so;
<form method="post" action="test.php">
<input type="text" name="name" placeholder="name"/><br />
<input type="submit" value="Validate" />
</form>
<?php
$sum=0;
if(!empty($_POST['name'])){
$sum+=1;
}
echo "sum = $sum";
?>
More about the empty() function here.
Another way would be to check the request that your client has made on your page. So that if it is a simple refresh (not with a form refresh), it is a GET request and so, the variable should not be incremented and if the form has been sent, then you can do whatever you want such as incrementing the data.
So if the client is sending the form with an input text filled, then you can increment the value. In all other cases, the value should remain a zero.
<form method="post" action="test.php">
<input type="text" name="name" placeholder="name"/><br />
<input type="submit" value="Validate" />
</form>
<?php
$sum=0;
if ($_SERVER['REQUEST_METHOD'] == 'POST' && isset($_POST['name']) && !empty($_POST['name']))
{
$sum++; /* strictly equivalent to: $sum += 1; */
}
?>
<samp>sum = <?php echo $sum; ?></samp>
Try this
<form method="post" action="test.php">
<input type="text" name="name" placeholder="name"/><br />
<input type="submit" name="submit" value="Validate" />
</form>
<?php
$sum=0;
if(isset($_POST['submit'])){
$sum+=1;
}
echo "sum = $sum";
?>
You can try below:
if(isset($_POST['name']) && strlen($_POST['name'])>0){
$sum+=1;
You have the code appending 1 to variable $sum
but your if statement is based on the name field being passed.
Not if the name field has any data in it.
So... you have made your code add 1 as long as name field is passed,
regardless if it has text input or not.
Also, you should reassign the varible to reset it.
+= should just be =
<form method="post" action="test.php">
//----------------------------- add empty value to input ------------
<input type="text" name="name" value="" placeholder="name"/><br />
<input type="submit" value="Validate" />
</form>
<?php
$sum=0;
if(isset($_POST['name'])){
$sum=1;
}
echo "sum = $sum";
?>
Related
Guys I just needed to display inputs one by one each time the user click the submit. The problem on using php is that when you use loop, it display all at one time. Please Help guys.
Output: enter image description here
This is my code
<?php
for($c=1;$c<=10;$c++){
echo '<form method="POST" class="form-anticlear">
Enter Number :
<input type="number" name="num[$c]" required />
<input type="SUBMIT" name="button" value="Submit" required>
</form>';
}
?>
Your question isn't really clear as too what it is you are trying to accomplish. Assuming you want to show another input field every time submit is called, the code below will give you that. The file is called test.php change the action="test.php" if your file is called something different.
<?php
$total = 1;
if (isset($_POST["background-number"])) {
$total += $_POST["background-number"];
}
for ($c = 1; $c <= $total; $c++) { ?>
<form method="POST" class="form-anticlear" action="test.php">
Enter Number :
<input type="hidden" name="background-number" value="<?= $total ?>"/>
<input type="number" name="number-input" required/>
<input type="SUBMIT" name="button" value="Submit" required>
</form>
<?php
}
?>
I am working on a project to take two submitted variables and turn them into php variables (eventually they will multiply together) but as of now I cannot get the variables to be treated as such/echo.
I tried changing from POST to GET and the variables are sent through (appear in query line) but they don't print on the page
<?php
if (isset($_POST['submit'])) {
echo $_POST['length'];
echo $_POST['numPass'];
}
?>
<form method="post" action="">
<input type="number" name="length">
<input type="number" name="numPass">
<input type="submit">
</form>
I expect that the variables will be echoed as a regular statement.
ie. length=2 and numPass=4
24
You can get the $_GET and $_POST request using $_REQUEST
if (isset($_REQUEST['submit'])) {
echo $_REQUEST['length'];
echo $_REQUEST['numPass'];
}
<form method="post" action="">
<input type="number" name="length">
<input type="number" name="numPass">
<input type="submit" value="submit">
</form>
$POST['submit'] does not exist because your submit button does not have a name, it needs a name the same as your other inputs
It is better to check the input to avoid possible errors. You can try its example:
<?php
if( $_POST["length"] && $_POST["numPass"] ) {
echo "1: " . $_POST['length'] . "<br>";
echo "2: " . $_POST['numPass'] . "<br>";
echo $_POST['length'] * $_POST['numPass'];
}
?>
<form method="post" action = "<?php $_PHP_SELF ?>">
<input type="number" name="length">
<input type="number" name="numPass">
<input type="submit">
</form>
I have a form field that looks like this:
<input type="hidden" name="last_amount_paid" value="<?php echo $amount; ?>">
$amount is set to 100.00 and shows up fine if I change the form field from hidden to text.
$_POST['last_amount_paid '] is empty when I try and retrieve the value after submit.
I ran var_dump($_POST); and it's showing up as a string and empty
["last_amount_paid"]=> string(0) ""
Any ideas?
This should be working:
<?php
if(!empty($_POST["last_amount_paid"]))
{
echo $_POST["last_amount_paid"];
} else
{
$amount = 100.00;
?>
<form method="POST" action="">
<input type="hidden" name="last_amount_paid" value="<?=$amount; ?>" />
<input type="submit" value="Submit" />
</form>
<?php
}
?>
I am trying want to ouput a string ,stored in a variabel, in a label on a page when i click on a button.
But i can't find out how. Still a beginner.
<form action="Test.php" method="post">
Output text: <input type="label" name="word" />
<input type="submit" method="submit" value="Print!" />
</form>
<?php
$word = "test";
if (isset($_POST['submit']))
{
//something that gives the label value $word//
}
?>
There are a few things wrong with your code.
Let me outline them.
Your submit input should have a name attribute, since your conditional statement is based on it if (isset($_POST['submit'])){...}, something I've modified to check if the input is not left empty, using PHP's empty() function.
The input type you have for your "Output text" is invalid, it should be type="text" and not type="label", there is no type="label".
method="submit" for your submit button is invalid for a few reasons. Method belongs in <form> and there is no method="submit".
You then need to assign a POST variable from the input:
such as:
$word = $_POST['word'];
Plus, from what looks to me that you're executing the entire code from within the same page, you can just do action="", unless your code is set in 2 seperate files.
In regards to what you want to achieve: You can then echo the input (if one was entered) using a ternary operator and giving it (the input) a value.
I.e.:
value="<?php echo isset($_POST['word']) ? $_POST['word']: '' ?>"
Here:
<form action="" method="post">
Output text: <input type="text" name="word" value="<?php echo isset($_POST['word']) ? $_POST['word']: '' ?>" />
<input type="submit" name="submit" value="Print!" />
</form>
<?php
if ( isset($_POST['submit']) && !empty($_POST['word']) )
{
$word = $_POST['word'];
echo $word;
}
?>
If you want to use a "label" for your input, then use:
<label for="word">Output text:
<input type="text" name="word" />
</label>
You should also guard against XSS attacks (Cross-side scripting) using:
http://php.net/strip_tags
http://php.net/htmlentities
http://php.net/manual/en/function.htmlspecialchars.php
I.e.:
$word = strip_tags($_POST['word']);
$word = htmlentities($_POST['word']);
$word = htmlspecialchars($_POST['word']);
A few articles you can read on XSS:
http://en.wikipedia.org/wiki/Cross-site_scripting
https://www.owasp.org/index.php/XSS_%28Cross_Site_Scripting%29_Prevention_Cheat_Sheet
Your code should look like this
<form action="Test.php" method="post">
Output text: <input type="label" name="word" value ="<?php echo isset($label['data'])?$label['data']: '' ?>" />
<input type="submit" method="submit" value="Print!" />
</form>
<?php
$word = "test";
$label = array();
if (isset($_POST['submit']))
{
//something that gives the label value $word//
$label['data'] = $word;
}
?>
This should work
Regards
Ahmad rabbani
First of all your input element has type = label, it doesn't mean anything. Change it to type=text
And you are submitting value but not printing it. So in input field you have to print it also.
Look below code.
<?php
$word = "test";
if (isset($_POST['submit']))
{
// whatever you do with $word
}
?>
<form action="Test.php" method="post">
Output text: <input type="text" name="word" value="<?php echo $word; ?>"/>
<input type="submit" name="submit" value="Print!" />
</form>
UPDATE
One more thing I forgot to mention that you are submitting form to Test.php and printing this to file, if this file's name is Test.php then not an issue, other wise leave action property blank, so it submit data to itself.
method = submit there is nothing like this. you can set button name to submit, like name= "submit".
I'm trying to submit two form field values to a PHP function, on the same page.
The function works perfect manually filling the two values.
<?PHP // Works as expected
echo "<br />"."<br />"."Write text file value: ".sav_newval_of(e, 45);
?>
On the form I must be missing something, or I have a syntax error. The web page doesn't fail to display. I found the below example here: A 1 Year old Stackoverflow post
<?php
if( isset($_GET['submit']) ) {
$val1 = htmlentities($_GET['val1']);
$val2 = htmlentities($_GET['val2']);
$result = sav_newval_of($val1, $val2);
}
?>
<?php if( isset($result) ) echo $result; //print the result of the form ?>
<form action="" method="get">
Input position a-s:
<input type="text" name="val1" id="val1"></input>
<br></br>
Input quantity value:
<input type="text" name="val2" id="val2"></input>
<br></br>
<input type="submit" value="send"></input>
</form>
Could it be the placement of my code on the form?
Any suggestions appreciated.
You need to name your submit button, or check for something else on your if(isset($_GET['submit'])) portion:
<form action="" method="get">
Input position a-s:
<input type="text" name="val1" id="val1" />
<br></br>
Input quantity value:
<input type="text" name="val2" id="val2" />
<br></br>
<input type="submit" name="submit" value="send" />
</form>
OR keep same form, but change php to:
<?php
if( isset($_GET['val1']) || isset($_GET['val2'])) {
$val1 = htmlentities($_GET['val1']);
$val2 = htmlentities($_GET['val2']);
$result = sav_newval_of($val1, $val2);
}
?>
You can you hidden field as:
<input type='hidden' name='action' value='add' >
And check on php by using isset function that form has been submitted.