I have php file named http://example.com/result.php?site=qxvyp6g6vefmt6tduifcr3swhuzo0uju&num=2
which when executed, given only top 2 results. Here num is variable and can be changed to any value n to get top n results. This works fine when called from browser address bar.
Now i use to get this file content by
<?php
echo file_get_contents("http://example.com/result.php?site=" . $_GET["site"] . "&num="2"");
?>
On a page having url ABC.com/index.php?site=qxvyp6g6vefmt6tduifcr3swhuzo0uju
This was working fine before adding &num="2" to file_get_contents. but after adding this gives a mysql error. Kindly help.
Just change this line
<?php
echo file_get_contents("http://example.com/result.php?site=" . $_GET["site"] . "&num="2"");
?>
like this
<?php
echo file_get_contents("http://example.com/result.php?site=" . $_GET["site"] . "&num=2");
?>
You are using "" inside "", so php thinks this is not a string. Replace the "" around the 2 with single ones (like '2') and it should work.
Related
I'm using the echo command in PHP, but I want to enter PHP code like <?php echo $variable [id_login]?>, while echoing something else out, but this does not work.
Is this possible to do, and if so, how would I do it?
echo "<script>location='member.php?&id=<?php echo $taruh[id_login] ?></script>";
You cannot use echo or open/cloce php twice like you did, you might want to try something like the line below,
echo '<script>location=member.php?id=' . $taruh[id_login] . '</script>';
after echo you can write enything you'd like, even if it's a php variable, just use single quote and dot where you need it (like I do here), as you can see, echo is only used once..
For example:
<?php
$your_variable = 'some text';
$other_variable = 'some PHP code';
echo 'I wrote: ' . $your_variable . ' and ' . $other_variable . '!';
?>
Output will be:
I wrote: some text and some PHP code!
I hope this will bring you into the right direction..
EDIT
Also important: if you use query string in URLs, the first 1 can be a ? every other part after should be a & for example see the url below
http://www.example.com/index.php?id=12345&coder=yes&country=usa
before id I used a quest sign, for all others I didn't use the quest sign...
So I'm basically calling and returning an entire row from a mysql table using a while loop (which is working), but I'm trying to use the data that I call inside an html link, but I can't seem to get it to work.
Ideally, eventually it will just be a list of links with each person's individual name. I can return the list fine, but I can't seem to return the list with a link.
Here is my code that I feel should be working :(
<?php
require 'db/connect.php';
$result = $con->query('SELECT distinct name FROM mytable');
while($rows = $result->fetch_assoc())
{
echo ''$rows['name']'' , "</br>";
}
?>
Any help would be greatly appreciated!
Issue might be with your string concatenation. Try following code block
echo ''.$rows['name'].'';
echo ''. $rows['name']. '' , "</br>";
You just need to use . to concatenate strings together.
try this
echo ''.$rows['name'].'' , "</br>";
Should work just fine. Basically it's '.$row['name'].'
when concatenating strings with variables you have to use dot(.) like echo "string".$var; it will be invalid to write echo "string"$var; in your example you have ignored this point.
Still learning php as I go so this might just be something I haven't gotten to yet but it's the next roadblock in building my personal site. I have a basic understanding of includes such as linking:
<a href="art.php?id=image id&name=This is my title&menu=side-menu-portfolio">
to pull my includes but I've come to a small problem in that my generic art-gallery page needs to switch between a 'portfolio' header and an 'artwork' header. So I figured I could either build "art-gallery.php" AND "port-gallery.php" and go back and relink everything or just make it so that when you call the link like the above code I just specify which header goes with it. Unfortunately this would also require going back and changing every link. But I noticed that I did state:
...&menu=side-menu-portfolio...
and the pages are already calling side-menu-artwork or side-menu-portfolio so if I could just call in menu and cast aside the 'side-menu-" portion then it would just use artwork or portfolio and call the right header. Unfortunately this is where my limited knowledge of php and syntax come in. I have tried to produce the following code based on my php and js understanding:
<?php include("headlines/headline-" . $_GET[menu - "side-menu-" ] . ".php"); ?>
but I don't know if my syntax is just wrong or if what I'm trying to do is impossible to begin with. Note that when I try this I get
Function Include error of "Warning: include(headlines/headline-.php)"
so it looks like everything else is reading correctly, I just don't know if or how I can extract the word I want from the rest of the menu name.
Should be, Assumed your included file name is headline-side-menu-portfolio.php
<?php
$filename = str_replace("side-menu-", "", $_GET['menu']); // headline-portfolio
include("headlines/headline-" . $filename . ".php"); // headline-portfolio.php
?>
Something like this :
<?php include("headlines/headline-" . $_GET["menu"].".php"); ?>
<!--gives include("headlines/headline-side-menu-portfolio.php")-->
where
$_GET["menu"] = 'side-menu-portfolio'
Try this:
<?php include("headlines/headline-" . $_GET['menu'] . ".php"); ?>
Your code is wrong.
Instead of
<?php include("headlines/headline-" . $_GET[menu - "side-menu-" ] . ".php"); ?>
try
<?php include("headlines/headline-" . $_GET['menu'] . ".php"); ?>
You should check if the file exists before you try including it.
if (file_exists($filesrc)) { ... }
Better yet don't let the user change the menu through a $_GET variable. Instead link to a specific page or pass a variable then decide what menu to get. Like
switch ($_GET['menu']) {
case 'side-menu':
include("headlines/headline-side-menu.php");
break;
}
Just use
$_GET['menu']
, the "side-menu-" part is already in the content of your variable passed as param.
You propably want to do an if .... else so to include one header or another based on the $_GET variable menu.
So something like this will do this:
if($_GET['menu'] == 'side-menu-portfolio') {
include 'headliens/side-menu-portfolio.php';
} elseif($_GET['menu'] == 'side-menu-other') {
include 'headliens/side-menu-other.php';
}
okay....your are almost there....just quotes missing from include syntax...it should be
include("headlines/headline-.php"); /* notice the quotes*/
so it should be
<?php include("headlines/headline-" .$_GET['menu'].".php"); ?>
where $_GET['menu'] should be in the url, like:
art.php?id=image id&name=This-is-my-title&menu=side-menu-portfolio
so what's happening her ??
Upon execution of the line :
<?php include("headlines/headline-" .$_GET['menu'].".php"); ?>
$_GET is fetched from the url and replaced in the header tag, so now the header tag becomes :
<?php include("headlines/headline-"."side-menu-portfolio".".php"); ?> => <?php include("headlines/headline-side-menu-portfolio.php"); ?>
Also. may i suggest that for :
<a href="art.php?id=image id&name=This is my title&menu=side-menu-portfolio">
don't use space in the url, either replace it by - or _
The following code is for a Wordpress plugin, it displays points and tank of a user:
<?php
if(function_exists('cp_displayPoints') && $authordata->ID){
echo '<span class="cubepoints_buddypress">'; cp_displayPoints($authordata->ID); echo '</span>';
if(function_exists('cp_module_ranks_getRank')) echo ' <span class="cupepoints_buddypress_rank">'.cp_module_ranks_getRank($authordata->ID).'</span>';
}
?>
I am trying to extract these two echo functions from the If statement but only succeeded with one of them. I can echo the points like this:
<?php cp_displayPoints($authordata->ID); ?>
Works fine. Now I tried doing the same with the second echo:
<?php cp_module_ranks_getRank($authordata->ID); ?>
But it did not work. Obviously, there is some basic thing that I am missing here. Do you know what it is?
The first one likely prints directly to output, while the second returns its value. So, you need to echo() the second one, just as they're doing in your sample code:
<?php echo cp_module_ranks_getRank($authordata->ID); ?>
This is the code I am working with:
echo '' . $post_type->labels->singular_name . '' .$markup;
It currently links correctly but shows the entire http string before the link.
Example: http://www.blah.com/blah/blahPortfolio. When it should be just "Portfolio".
Fresh eyes on this would be so helpful.
There are two errors that I can see:
<?php bloginfo('template_directory'); ?> If you are using echo it means <?php tag is already open so use only bloginfo('template_directory')
There are two closing tag for a tag (i.e. />) You use only one (i.e. >)
So the code will be like this:
echo '' . $post_type->labels->singular_name . '';
Try this code chunk and let me know --
echo '' . $post_type->labels->singular_name . '';