PHP SQLSRV: passing a string of values to IN clause - php

Question

I need a way to perform the following query:
SELECT *
FROM myTable
WHERE column NOT IN ('val1', 'val2')
Now, val1 and val2 are inside an array that I'm imploding into a string like this:
$inClause = "'" . implode("','", $inClauseArr) . "'";
If I put the string in the query declaration like this it works:
$sql = "[...]WHERE column NOT IN ($inClause)";
But if I pass it as a sqlsrv_query parameter like this, the query is not working:
$stmt = sqlsrv_query($conn, $sql, array($inClause));
I'm not getting any error. $stmt is true but while cycle is not returning anything.
I absolutely need to pass it through sqlsrv_query, how can i do this?
UPDATE
Here's the $sql value:
SELECT *
FROM orders(NOLOCK)
WHERE order_id NOT IN (?)

Answer 1

Count of question marks in your original SQL query must match with the count of parameters you have passed into the query.
Supposing $inClauseArr is like:
$inClauseArr = array('val1', 'val2');
There are two elements. Actually, it is not important how much element it has. As long as $inClauseArr is an array, there will be no problem.
So, the query should be constructed as ([...] is the beginning of the query):
$sql = "[...]WHERE column NOT IN ("
. implode(',', array_fill(0, count($inClauseArr), '?'))
. ")";
// For $inClauseArr = array('val1', 'val2');
// Output should be [...]WHERE column NOT IN (?, ?)
And execution should be like:
$stmt = sqlsrv_query($conn, $sql, $inClauseArr);
References:
sqlsrv_query
implode
array_fill

Answer 2

Pass it in a a comma delimited string (varchar) then use a split function to create a table:
declare #vars varchar(14) = 'G' + ',' + 'H'
select * from syscode_detail
where code in (select value from dbo.Split(#vars, ','))
using this function:
CREATE function [dbo].[Split]
(
#List nvarchar(2000),
#SplitOn nvarchar(5)
)
returns #tblReturn table
(
id int identity(1,1),
value nvarchar(100)
)
as
Begin
While (Charindex(#SplitOn, #List) > 0)
Begin
Insert Into #tblReturn (value)
Select value = ltrim(rtrim(Substring(#List, 1, Charindex(#SplitOn,
#List) - 1)))
Set #List = Substring(#List, Charindex(#SplitOn, #List) +
len(#SplitOn), len(#List))
End
Insert Into #tblReturn (value)
Select Value = ltrim(rtrim(#List))
Return
End