array_search function not returning values - php

Question

Here am having two tables namely tools and tool_use.
tools table looks like this
id name tools_names quantity type
13 cutting player cutting playerA,cutting playerB,cutting playerC 3 engineer
12 REFLECTORS REFLECTORSA,REFLECTORSB 2 team
tool_use table looks like this
id user_id type tools
8 siraj engineer cutting playerA,cutting playerB
7 siraj team REFLECTORSB
6 siraj team REFLECTORSA
i want to display the tools_names except inserted to tool_use table while inserting but the entire tools_names are displaying eventhough the result looks like in the table.here is my control
public function ajax_tools()
{
$data['tools']=$this->Tools_model->view_available_tools($_POST['type']);
foreach ($data['tools'] as $key=>$val) {
$data['toolss'][] =explode(',',$val['tools_names']);
}
$data['tools_names'] = $this->Tools_model->get_tool_names($_POST['type'])->result();
foreach ($data['tools_names'] as $row)
{
if (($key =array_search($row->tools,$data['toolss'])) !== false)
{
unset($data['toolss'][$key]);
$data['toolss'] = array_values($data['toolss']);
}
}
return $data['toolss'];
$this->load->view('ajax_tools',$data);
}
Here is my models
public function view_available_tools($type)
{
$this->db->order_by('id','desc');
$this->db->where('status',1);
$this->db->where('type',$type);
$query=$this->db->get('tools');
return $query->result_array();
}
public function get_tool_names($type)
{
return $this->db->get_where('tool_use',array('type'=>$type));
}
this is my view
<div class="form-group">
<label for="type" class="control-label">Type:</label>
<select name="type" id="type" class="form-control" required>
<option value="">please select</option>
<option value="team" <?php echo set_select('type','team'); ?>>Team</option>
<option value="engineer" <?php echo set_select('type','engineer'); ?>>Engineer</option>
</select>
</div>
<div class="form-group ">
<label for="tools" class="control-label">Tools:</label>
<select name="tools[]" id="tools" multiple="multiple" required>
<option value="">please select</option>
</select>
</div>
<script>
$('#type').change(function(){
var type=$('#type').val();
var url='<?php echo base_url(); ?>tools/tools_control/ajax_tools';
$.post(url, {type:type}, function(data)
{
$('#tools').html(data);
});
});
</script>
please help me to solve my issue

Answer 1

When you array_search, you're trying to search for $row->tools which supposedly contains cutting playerA,cutting playerB. And you search for that inside an array that does not contain the same kind of comma-separated lists of values but instead contains their exploded versions (as you did an explode on line 3).

Answer 2

if tools in table tool_use contain single values i find it out the solution but if it contains more values i mean stored as an array keeping me away from the destination please have a look
public function ajax_tools()
{
$data['tools']=$this->Tools_model->view_available_tools($_POST['type']);
foreach ($data['tools'] as $key=>$val)
{
$data['toolss'][] = $data['t']=explode(',',$val['tools_names']);
}
$data['tools_names'] = $this->Tools_model->get_tool_names($_POST['type'])->result();
var_dump($data['tools_names']);
foreach ($data['tools_names'] as $val)
{
if (($key =array_search($val->tools,$data['t'])) !== false)
{
unset($data['t'][$key]);
$data['t'] = array_values($data['t']);
}
}
$this->load->view('ajax_tools',$data);
}