Remove Duplicate Values From Select Option In PHP - php

Question

here's the code and i want to echo only 1 city from mysql database!
<?php
include('db.php');
$queryss = mysqli_query($conn, 'SELECT * FROM areas');
while ($rowx = mysqli_fetch_array($queryss)) {
echo "{pro:'$rowx[1]',city:'$rowx[2]', dist:'$rowx[3]', town:'$rowx[4]', area:'$rowx[5]',subarea:'$rowx[6]',ucname:'$rowx[7]'},";
}
?>
and i'm, getting this input here! 3 time karachi in my html, but i want only 1 of this city. SELECT DISTINCT is working in mysql but how can i use it in PHP?

Answer 1

Your query should be
SELECT * FROM areas GROUP BY id
I have tested it.

Answer 2

Use
SELECT DISTINCT column_name1,column_name2 FRAM areas
in your SQL where column_nameN stands for the columns you need for your output.
OR use something like this (untested):
$results = [];
while ($rowx = mysqli_fetch_array($queryss)) {
$results[] = $rowx;
}
$results= array_unique($results);
foreach($results as $rowx) {
echo "{pro:'$rowx[1]',city:'$rowx[2]', dist:'$rowx[3]', town:'$rowx[4]', area:'$rowx[5]',subarea:'$rowx[6]',ucname:'$rowx[7]'},";
}

Answer 3

First Solution
You can insert distinct keyword into your SQL to accomplish what you need, like so
SELECT DISTINCT your_column_name FROM table_name
Second Soltion
You can execute your SQL statement and then use array_unique, to be like so
$selectStatement = mysqli_query($con, 'SELECT * FROM areas');
$selectedArrayValues = mysqli_fetch_array($selectStatement);
$selectedUniqueArrayValues = array_unique(selectedArrayValues);
// Then return that array to your HTML code
I recommend the first solution because it's more optimized