The problem is related to php. I have a text in a variable say $text and some start position and end positions. How to inject the some substring on the specific position. the problem is that if i put some text in a specific position then position index changes and it will be difficult to put next sub string to the right place. Help me. thanks in advance.
function previewTxt($text,$topicid, $sectionid)
{
$dbConn = new DBConnUtil();
$queryString = "SELECT * from inline_topic_xref where TOPIC_ID=$topicid and SECTION_ID=$sectionid";
$result = $dbConn->run_query($queryString);
$newtext=$text;
$count=0;
while($row = $result->fetch_object())
{
$newtext = replace($newtext, "<a href='#'>" ,$row->REF_TEXT_START);
$newtext = replace($newtext, "</a>" ,$row->REF_TEXT_END);
}
return $newtext;
}
function replace($org_text,$str_rep, $position)
{
$length=strlen($org_text);
$temp1=substr($org_text,0,$position);
$temp2=substr($org_text,$position,$length);
$replaced =$temp1.$str_rep.$temp2;
return $replaced;
}
have you tried
substr_replace($oldstr, $str_to_insert, $pos, 0)
?
here is the documentation
http://php.net/manual/en/function.substr-replace.php
Related
i'm using this code to replace shortcodes in a CMS with links including images but it replaces only the first shortcode
$string = $row['Content'];
if(stristr($string,'[gal=')){
$startTag = "[gal=";
$endTag = "]";
$pos1 = strpos($string, $startTag) + strlen($startTag);
$pos2 = strpos($string, $endTag);
$gal = substr($string, $pos1, $pos2-$pos1);
$q=$db->prepare("select * from images where Gal_ID = :gal");
$q->execute(["gal"=>$gal]);
$imgs='';
while($r=$q->fetch(PDO::FETCH_ASSOC)){
$images[] = $r['Image'];
}
foreach($images as $val){
$imgs .= "<a href='gallery/large/$val' class='fancybox-thumbs' rel='gallery'><img src='gallery/thumb/$val'></a>";
}
$result = substr_replace($string, $imgs, $pos1, $pos2-$pos1);
$result = str_replace($startTag,'',$result);
$result = str_replace($endTag,'',$result);
echo $result;
}
else{
echo $string;
}
string contains some paragraphs and 2 shortcodes
[gal=36] and [gal=37]
the result is replacing only the first shortcode with links and images but the second shortcode is displayed like this: "37" just the number. So how to loop through all shortcodes to replace them with links not only the first shortcode
Here is a full example how I described above.
//get matches
if(preg_match_all('/\[gal=(\d+)\]/i', $string, $matches) > 0){
//query for all images. You could/should bind this, but since the expression
//matches only numbers, it is technically not possible to inject anything.
//However best practices are going to be "always bind".
$q=$db->prepare("select Gal_ID, Image from images where Gal_ID in (".implode(',', $matches[1]).")");
$q->execute();
//format the images into an array
$images = array();
while($r=$q->fetch(PDO::FETCH_ASSOC)){
$images[$r['Gal_ID']][] = "<a href='gallery/large/{$r['Image']}' class='fancybox-thumbs' rel='gallery'><img src='gallery/thumb/{$r['Image']}'></a>";
}
//replace shortcode with images
$result = preg_replace_callback('/\[gal=(\d+)\]/i', function($match) use ($images){
if(isset($images[$match[1]])){
return implode('', $images[$match[1]]);
} else {
return $match[0];
}
}, $string);
echo $result;
}
I tested it as much as I could, but I don't have PDO and/or your tables. This should work as a pretty much drop in replacement for what you have above.
I am facing a problem that I can't get my head around. I thought I would turn to the experts once again to shine some light.
I have a HTML template and within the template I have delimiters like:
[has_image]<p>The image is <img src="" /></p>[/has_image]
These delimiters may have multiple occurances within the template and below is what I am trying to achieve:
Find all occurances of these delimiters and replace the content between these delimiters with an image source or replace it empty if image doesn't exist but still keep the value/content of the remaining template.
Below is my code that works only for one occurance but struggling to accomplish it for multiple occurances.
function replace_text_template($template_body, $start_tag, $end_tag, $replacement = ''){
$occurances = substr_count($template_body, $start_tag);
$x = 1;
while($x <= $occurances) {
$start = strpos($template_body, $start_tag);
$stop = strpos($template_body, $end_tag);
$template_body = substr($template_body, 0, $start) . $start_tag . $replacement . substr($template_body, $stop);
$x++;
}
return $template_body;
}
$template_body will have HTML code with delimiters
replace_text_template($template_body, "[has_image]", "[/has_image]");
Whether I remove the while loop it still works for a single delimiter.
I have managed to solve the problem. If anybody finds this useful please feel free to use the code. However, if anyone finds a better way please do share it.
function replace_text_template($template_body, $start_tag, $end_tag, $replacement = ''){
$occurances = substr_count($template_body, $start_tag);
$x = 1;
while($x <= $occurances) {
$start = strpos($template_body, $start_tag);
$stop = strpos($template_body, $end_tag);
$template_body = substr($template_body, 0, $start) . $start_tag . $replacement . substr($template_body, $stop);
$template_body = str_replace($start_tag.''.$end_tag, '', $template_body); // replace the tags so on next loop the position will be correct
$x++;
}
return $template_body;
}
function replace_text_template($template_body, $start_tag, $replacement = '') {
return preg_replace_callback("~\[".preg_quote($start_tag)."\].*?\[\/".preg_quote($start_tag)."\]~i", function ($matches) use ($replacement) {
if(preg_match('~<img.*?src="([^"]+)"~i', $matches[0], $match)) {
if (is_array(getimagesize($match[1]))) return $match[1];
}
return $replacement;
}, $template_body);
}
$template_body = <<<EOL
text
[has_image]<p>The image is <img src="" /></p>[/has_image]
abc [has_image]<p>The image is <img src="http://blog.stackoverflow.com/wp-content/themes/se-company/images/logo.png" /></p>[/has_image]xyz
EOL;
echo replace_text_template($template_body, "has_image", "replacement");
Returns:
text
replacement
abc http://blog.stackoverflow.com/wp-content/themes/se-company/images/logo.pngxyz
I have a site crawler which displays a list of urls, but the problem is I cannot for the life of me get the last regex quite right.
all urls end up listed as:
http://www.website.org/page1.html&--EFTTIUGJ4ITCyh0Frzb_LFXe_eHw
http://website.net/page2/&--EyqBLeFeCkSfmvA7p0cLrsy1Zm1g
http://foobar.website.com/page3.php&--E5WRBxuTOQikDIyBczaVXveOdRFg
The Urls can all be different and the only thing which seems static is the & symbol.
How would go abouts getting rid of the & symbol and everything beyond it to the right?
Here is what I have tried with the above results:
function getresults($sterm) {
$html = file_get_html($sterm);
$result = "";
// find all span tags with class=gb1
foreach($html->find('h3[class="r"]') as $ef)
{
$result .= $ef->outertext . '<br>';
}
return $result;
}
function geturl($url) {
$var = $url;
$result = "";
preg_match_all ("/a[\s]+[^>]*?href[\s]?=[\s\"\/url?q=\']+".
"(.*?)[\"\']+.*?>"."([^<]+|.*?)?<\/a>/",
$var, $matches);
$matches = $matches[1];
foreach($matches as $var)
{
$result .= $var."<br>";
}
echo preg_replace('/sa=U.*?usg=.*?AFQjCN/', "--" , $result);
}
if url are ALWAYS in the same format, use explode :
<?php
$tmp = explode("&", "http://foobar.website.com/page3.php&--E5WRBxuTOQikDIyBczaVXveOdRFg");
?>
$tmp[0] should content "http://foobar.website.com/page3.php" and
$tmp[1] should content "--E5WRBxuTOQikDIyBczaVXveOdRFg"
A simple way to remove everything after the & character:
$result = substr($result, 0, strpos($result, '&'));
Im working on a commenting web application and i want to parse user mentions (#user) as links. Here is what I have so far:
$text = "#user is not #user1 but #user3 is #user4";
$pattern = "/\#(\w+)/";
preg_match_all($pattern,$text,$matches);
if($matches){
$sql = "SELECT *
FROM users
WHERE username IN ('" .implode("','",$matches[1]). "')
ORDER BY LENGTH(username) DESC";
$users = $this->getQuery($sql);
foreach($users as $i=>$u){
$text = str_replace("#{$u['username']}",
"<a href='#' class='ct-userLink' rel='{$u['user_id']}'>#{$u['username']}</a> ", $text);
}
$echo $text;
}
The problem is that user links are being overlapped:
<a rel="11327" class="ct-userLink" href="#">
<a rel="21327" class="ct-userLink" href="#">#user</a>1
</a>
How can I avoid links overlapping?
Answer Update
Thanks to the answer picked, this is how my new foreach loop looks like:
foreach($users as $i=>$u){
$text = preg_replace("/#".$u['username']."\b/",
"<a href='#' title='{$u['user_id']}'>#{$u['username']}</a> ", $text);
}
Problem seems to be that some usernames can encompass other usernames. So you replace user1 properly with <a>user1</a>. Then, user matches and replaces with <a><a>user</a>1</a>. My suggestion is to change your string replace to a regex with a word boundary, \b, that is required after the username.
The Twitter widget has JavaScript code to do this. I ported it to PHP in my WordPress plugin. Here's the relevant part:
function format_tweet($tweet) {
// add #reply links
$tweet_text = preg_replace("/\B[#＠]([a-zA-Z0-9_]{1,20})/",
"#<a class='atreply' href='http://twitter.com/$1'>$1</a>",
$tweet);
// make other links clickable
$matches = array();
$link_info = preg_match_all("/\b(((https*\:\/\/)|www\.)[^\"\']+?)(([!?,.\)]+)?(\s|$))/",
$tweet_text, $matches, PREG_SET_ORDER);
if ($link_info) {
foreach ($matches as $match) {
$http = preg_match("/w/", $match[2]) ? 'http://' : '';
$tweet_text = str_replace($match[0],
"<a href='" . $http . $match[1] . "'>" . $match[1] . "</a>" . $match[4],
$tweet_text);
}
}
return $tweet_text;
}
instead of parsing for '#user' parse for '#user ' (with space in the end) or ' #user ' to even avoid wrong parsing of email addresses (eg: mailaddress#user.com) maybe ' #user: ' should also be allowed. this will only work, if usernames have no whitespaces...
You can go for a custom str replace function which stops at first replace.. Something like ...
function str_replace_once($needle , $replace , $haystack){
$pos = strpos($haystack, $needle);
if ($pos === false) {
// Nothing found
return $haystack;
}
return substr_replace($haystack, $replace, $pos, strlen($needle));
}
And use it like:
foreach($users as $i=>$u){
$text = str_replace_once("#{$u['username']}",
"<a href='#' class='ct-userLink' rel='{$u['user_id']}'>#{$u['username']}</a> ", $text);
}
You shouldn’t replace one certain user mention at a time but all at once. You could use preg_split to do that:
// split text at mention while retaining user name
$parts = preg_split("/#(\w+)/", $text, -1, PREG_SPLIT_DELIM_CAPTURE);
$n = count($parts);
// $n is always an odd number; 1 means no match found
if ($n > 1) {
// collect user names
$users = array();
for ($i=1; $i<$n; $i+=2) {
$users[$parts[$i]] = '';
}
// get corresponding user information
$sql = "SELECT *
FROM users
WHERE username IN ('" .implode("','", array_keys($users)). "')";
$users = array();
foreach ($this->getQuery($sql) as $user) {
$users[$user['username']] = $user;
}
// replace mentions
for ($i=1; $i<$n; $i+=2) {
$u = $users[$parts[$i]];
$parts[$i] = "<a href='#' class='ct-userLink' rel='{$u['user_id']}'>#{$u['username']}</a>";
}
// put everything back together
$text = implode('', $parts);
}
I like dnl solution of parsing ' #user', but maybe is not suitable for you.
Anyway, did you try to use strip_tags function to remove the anchor tags? That way you have the string without the links, and you can parse it building the links again.
strip_tags
How can I get everything from $string after "<div class='partFive'>"?
try this,
$prefix = "<div class='partFive'>";
$index = strpos($string, $prefix) + strlen($prefix);
$result = substr($string, $index);
obviously you don't have to re-calculate the "strlen" part of it each time if the $prefix value is static.
$myString = strstr($string, "<div class='partFive'>");
Do you need everything after <div class='partFive'> or everything in that DOM element?
I'm assuming you mean you want to grab everything in that DOM element, and the easiest way would be to grab it by using Zend_Dom.
$dom = new Zend_Dom_Query($html);
$results = $dom->query('div.partFive');
foreach ($results as $result) {
// $result is a DOMElement
}
You could just remove the part you don't want, like so:
$myString = str_replace("<div class='partFive'>","",$string);