how to keep php Class method in a variable - php

Question

1.here's my wrong code
class classname{
function __construct(){};
public function test(){return 0;};
}
$c = new classname();
$test = $c->test;
var_dump($test); //out put NULL, I want the method $c->test
I didn't want to execute the function and store the result
there is something wrong with my code.
howto write it!
here's the code what I wanted(by Bobot):
$test = function() use ($c) { return $c->test(); };
devmyb's answer was helpful,and he/she told me why my codes not works
Bobot 、JezEmery 、devmyb ... etc
thanks for your help

Answer 1

You're not calling the function, you're trying to access a property (which isn't found).
$test = $c->test();
That should work.

Answer 2

Your question is unclear, but I guess you want to do this :
$test = function() use ($c) { return $c->test(); };
Then when you need to run your method, just run the function : $test();
I guess that some documentation about anonymous functions can help you to understand the code.

Answer 3

Its because you didn't have your error_reporting on else you'll get the notice, warning and fatal error too
You have typographical errors, check the updated code
class classname{
function __construct(){} // removed ;
public function test(){return 0;} // removed ;
}
$c = new classname();
$test = $c->test; // You were calling variable of your class
$test1 = $c->test(); // You were calling method of your class i.e. public function test()
var_dump($test);
var_dump($test1);
Output:
Notice: Undefined property: classname::$test in /in/HBNf9 on line 9
NULL
int(0)

Answer 4

This is the correct code. After a function is no ;
class classname {
function __construct(){
}
public function test() {
return 0;
}
}
$c = new classname();
$test = $c->test;