JQUERY autocomplete get id instead of value - php

Question

I have a mysql database where I would like to use the autocomplete one.
So far I am able to receive the results of the query.
For example this is the result: [{"LNAME":"Napoleon","id":"1"}]
But I want the id of the customer in this case to be filled in another input field of my form. (so in Napoleons case I want the "1" to be filled in to my clienteID field of the form)
At the moment the field does not get updated.
Here's the HTML part:
<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript" src="js/jquery.autocomplete.js"></script>
<script>
$(document).ready(function(){
$("#tag").autocomplete("autocomplete.php", {
minLength: 3,
select: function(event, ui) {
$('#clienteId').val(ui.item.id);
},
});
});
</script>
<form name='form_update_details' id='form_update_details' method='post' action=''>
<input type='text' name='clienteName' id='tag'>
<input type='text' name='clienteId' id='clienteId'>
</form>
Then the php part:
<?php
include("include/db.php");
$q=$_GET['q'];
$my_data=mysql_real_escape_string($q);
$sql="SELECT ID, CONTACTS_LNAME, CONTACTS_FNAME FROM CRM_CONTACTS WHERE CONTACTS_LNAME LIKE '%$my_data%' or CONTACTS_FNAME LIKE '%$my_data%' ORDER BY CONTACTS_LNAME";
$result = mysqli_query($coni,$sql) or die(mysqli_error());
if($result)
{
while($row=mysqli_fetch_array($result))
{
$data[] = array(
'LNAME' => $row['CONTACTS_LNAME'],
'id' => $row['ID']
);
}
echo json_encode($data);
flush();
}
?>

Answer 1

Try with a sample data:use label and value as keys instead of LNAME and id. Use event.preventDefault(); to set the label in #tag field otherwise by default it will set the value.
var data = [
{
value: "1",
label: "jQuery"
},
{
value: "2",
label: "jQuery UI"
},
{
value: "3",
label: "Sizzle JS"
}
];
$(document).ready(function(){
$("#tag").autocomplete( {
source: data,
minLength: 3,
select: function(event, ui) {
event.preventDefault();
$("#tag").val(ui.item.label);
$('#clienteId').val(ui.item.value);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<form name='form_update_details' id='form_update_details' method='post' action=''>
<input type='text' name='clienteName' id='tag'>
<input type='text' name='clienteId' id='clienteId'>
</form>

Answer 2

Try this:
$( function() {
var projects = [
{
value: "1",
label: "jQuery"
},
{
value: "2",
label: "jQuery UI"
},
{
value: "3",
label: "Sizzle JS"
}
];
$( "#project" ).autocomplete({
minLength: 0,
source: projects,
focus: function( event, ui ) {
$( "#project" ).val( ui.item.label );
return false;
},
select: function( event, ui ) {
$( "#project" ).val( ui.item.label );
$( "#project-id" ).val( ui.item.value );
return false;
}
})
.autocomplete( "instance" )._renderItem = function( ul, item ) {
return $( "<li>" )
.append( "<div>" + item.label + "</div>" )
.appendTo( ul );
};
});
Html:
<div id="project-label">Select a project (type "j" for a start):</div>
<input id="project">
<input type="text" id="project-id">
Demo Fiddle