Display comments for each post in PHP/mySQL site - php

I'm trying to display multiple posts, each with its own multiple comments. This, below, works for the first post (or, at least shows 2 of the 3 comments), but not for the rest. I searched but couldn't find (or didn't recognize) an answer to this exact problem on this site, or elsewhere. Thanks.
$result1 = #mysql_query('select * from posts,comments where comment_post_ID = ID and post_status="publish" and comment_approved="1" ORDER BY post_date,category,subcat1,subcat2 ASC');
$result2 = #mysql_query('select * from comments where comment_approved="1" ORDER BY comment_date');
$row = mysql_fetch_array($result1);
$row2 = mysql_fetch_array($result2);
while ($row = mysql_fetch_array($result1)) {
$post = $row['post_content'];
$id = $row['ID'];
$title = $row['post_title'];
$content = "<br /><h3 align=\"left\">" . $title . "</h3>\n";
$content .= "<h4 align=\"left\">by " . $row['post_author'] . " - " . $row['post_date'] . "</h4>\n";
$content .= "<p align=\"left\">" . var_export($post, true) . "</p>\n<p>\n";
echo $content;
while ($row2 = mysql_fetch_array($result2)) {
$comment = "<blockquote>";
$comment .= "<h4 align=\"left\">" . $row2['comment_author'] . " commented on " . $row2['comment_date'] . "</h4>\n";
$comment .= "<p align=\"left\">" . $row2['comment_content'] . "</p>\n<p>\n";
$comment .= "</blockquote>";
if($row2['comment_post_ID'] == $id) {
echo $comment;
}
}
}

This, below, finally worked as hoped:
$postData = mysqli_query($conn,"SELECT * FROM wp_posts ORDER BY post_date ASC) or die(mysqli_error());
$commentData = mysqli_query($conn,"SELECT * FROM wp_comments WHERE comment_approved = '1' ORDER BY comment_date ASC") or die(mysqli_error());
$posts = array();
while($row = mysqli_fetch_assoc($postData)) {
$posts[] = $row;
$commentrow = mysqli_fetch_assoc($commentData);
$comments[] = $commentrow;
echo '<h3>' . $row['post_title'] . '</h3>';
echo '<h5>' . $row['post_author'] . ', ' . $row['post_date'] . '</h5>';
echo '<p>' . $row['post_excerpt'] . '... read more</p>';
if($row['comment_count'] > 0) {
echo '<blockquote>';
echo '<b>Comments</b><br />';
foreach($comments as $comment) {
if($row['ID']==$comment['comment_post_ID']) {
$comment_excerpt = substr($comment['comment_content'],0,100);
echo '<br>' . $comment_excerpt . ' - <b>' . $comment['comment_author'] . '</b>, ' . $comment['comment_date'] . '<br>';
}
}
echo '</blockquote>';
}
}

Related

Sorting nested While() Loops

I'm able to sort the second tier while loop for obvious reasons but I cannot get the first one to sort. I know its cause the "for" loop is incrementing. What I want is alphabetically sort first while loop then the second ASC...any suggestions? Here's my code
function get_content() {
$sql1 = "SELECT * FROM category";
$res1 = mysql_query($sql1) or die(mysql_error());
$total = mysql_num_rows($res1) or die(mysql_error());
for($a = 1; $a <= $total; $a++) {
$sql = "SELECT * FROM weblinks INNER JOIN category ON category_weblinks = id_category WHERE id_category = '$a' AND status_weblinks = 'checked' ORDER BY title_weblinks ASC";
$res = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($res)) {
echo "\n\n\n" . '<div class="post">' . "\n";
echo '<div class="title">' . "\n";
echo '<h2><a name="' . $row['shortcut_category'] . '">' . $row['title_category'] . '</a></h2>' . "\n";
echo '<p><small>Posted by Joe email</small></p>';
echo '</div>' . "\n";
echo '<div class="entry">' . "\n";
$res = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($res)) {
echo "\n" . '<p><b>' .$row['title_weblinks']. '</b><br>' . "\n";
echo $row['description_weblinks']. '<br>' . "\n";
echo 'Link: ' .$row['link_weblinks']. '<br>' . "\n";
echo 'User: ' .$row['username_weblinks']. ' | Password: ' .$row['password_weblinks']. '</p>' . "\n";
}
echo '<p class="links"> Back to Top</p>';
echo '</div>';
echo '</div>';
}
}
}

Else statement doesn't work in option select

I am trying to implement a dropdown search option. All my search results are working. All the commands that I have assigned to if statements work, but when it does to else it deosn't work.
Here is my code:
if(isset($_REQUEST['submit'])){
$opt = $_POST['opt'];
if($opt==1){//if opt = 1
$sqle = "SELECT * FROM tbl_events WHERE title LIKE '%{$keywords}%'";
$resulte = mysql_query($sqle,$con) or die(mysql_error());
while($row=mysql_fetch_array($resulte)){
echo "<h4>" . $row['title'] . "</h4><br/>";
echo "<p>" . $row['description'] . "<p>";
}
}else if($opt==2){//if opt = 2
$sqls = "SELECT * FROM tbl_games WHERE games_name LIKE '%{$keywords}%'";
$results = mysql_query($sqls,$con)or die(mysql_error());
while($row=mysql_fetch_array($results)){
echo "<h4>" . $row['games_name'] . "</h4><br/>";
echo "<p>" . $row['description'] . "<p>";
}
}else{
echo "Your Searched keyword did not match";
}
}
What to do?
Try this: Take a flag to check if record exists.
$flag = false;
if($opt==1){//if opt = 1
$sqle = "SELECT * FROM tbl_events WHERE title LIKE '%{$keywords}%'";
$resulte = mysql_query($sqle,$con) or die(mysql_error());
if(mysql_num_rows($resulte) > 0) {
$flag = true;
while($row=mysql_fetch_array($resulte)){
echo "<h4>" . $row['title'] . "</h4><br/>";
echo "<p>" . $row['description'] . "<p>";
}
}
}else if($opt==2){//if opt = 2
$sqls = "SELECT * FROM tbl_games WHERE games_name LIKE '%{$keywords}%'";
$results = mysql_query($sqls,$con)or die(mysql_error());
if(mysql_num_rows($resulte) > 0) {
$flag = true;
while($row=mysql_fetch_array($results)){
echo "<h4>" . $row['games_name'] . "</h4><br/>";
echo "<p>" . $row['description'] . "<p>";
}
}
}
if(!$flag){
echo "Your Searched keyword did not match";
}

Extraction of the data from MySQL using PHP

$query = "SELECT * FROM `status_info_private` WHERE `id`=$id ORDER BY `Status_Date` DESC LIMIT 100";
if ($query_run = mysql_query($query)) {
while ($rows = mysql_fetch_array($query_run)) {
echo '<font color="#009900" > ' . $rows['Name'] . ' ' . ' Says :' . '</font><br/>';
echo '<p align="justify> ' . $rows['Private_status'] . '<br/>';
echo '<p align="right">' . $rows['Status_Date'] . '<br/>';
$like = $rows['Like'];
$unlike = $rows['Unlike'];
}
}
I think everything is correct in the piece of code. But still I am unable to get the output under the column titled as "Private_status". The above code is producing everything correctly except the message under cols "Private_status". I have already checked the spelling of the col name & there is no error in that part.
So, Please tell me what exactly is missing ?
first close your <p> tags and then do a print_r to check what is in $rows
..
Also, start using PDO or mysqli
$query = "SELECT * FROM `status_info_private` WHERE `id`=$id ORDER BY `Status_Date` DESC LIMIT 100";
if ($query_run = mysql_query($query)) {
while ($rows = mysql_fetch_array($query_run)) {
echo '<a href="view_profile.php?id=' . $id . '" color="#009900" > ' . $rows['Name'] . ' ' . ' Says :' . '</a><br/>';
echo '<p align="justify"> ' . $rows['Private_status'] . '</p>';
echo '<p align="right">' . $rows['Status_Date'] . '</p>';
$like = $rows['Like'];
$unlike = $rows['Unlike'];
}
}

Using multiple tables in a search engine?

To clean and tidy-up my code, I want to add multiple tables with the fields:
id
title
description
keywords
link
but I also want them in sections so in MySql I want different tables with categories such as: "News", "Social Networking" and "Shopping", but how can I get that? This is my code:
<?php
if( count($terms) == 0){ // If no terms entered, stop.
echo "No Search Terms Entered.";
}else{
// connect
$connect = mysql_connect("XXX", "XXX", "YYY") or die('Couldn\'t connect to MySQL Server: ' . mysql_error());
mysql_select_db("theqlickcom_774575_db1", $connect ) or die('Couldn\'t Select the database: ' . mysql_error( $connect ));
/* Query Statement Building - Terms together */
$query = " SELECT * FROM scan WHERE ";
$terms = array_map('mysql_real_escape_string', $terms);
$i = 0;
foreach ($terms as $each) {
if ($i++ !== 0){
$query .= " AND ";
}
$query .= "keywords LIKE '%{$each}%'";
}
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
$numrows = mysql_num_rows($query);
if ($numrows > 0) {
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
echo '<h2><a class="ok" href="' . $link . '">' . $title . '</a></h2>' . PHP_EOL;
echo '<p class="kk">' . $description . '<br><br><span class="keywords">' . PHP_EOL;
echo '<p><a class="okay" href="' . $link . '">' . $link . '<br><br><span class="keywords">' . PHP_EOL;
}
} else {
/* Query Statement Building - Terms Separate */
$query = " SELECT * FROM scan WHERE ";
$terms = array_map('mysql_real_escape_string', $terms);
$i = 0;
foreach ($terms as $each) {
if ($i++ !== 0){
$query .= " OR ";
}
$query .= "keywords LIKE '%{$each}%'";
}
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
$numrows = mysql_num_rows($query);
if ($numrows > 0) {
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
echo '<h2><a class="ok" href="' . $link . '">' . $title . '</a></h2>' . PHP_EOL;
echo '<p class="kk">' . $description . '<br><br><span class="keywords">' . PHP_EOL;
echo '<p><a class="okay" href="' . $link . '">' . $link . '<br><br><span class="keywords">' . PHP_EOL;
}
} else {
echo "No results found for \"<b>{$k}</b>\"";
}
}
//disconnect
}
?>
If you have to search multiple table with one query
1.use mysqli
2.use UNION ALL in query
Join table
use mysql procedure

drropdownlist values are not shown from the database on fom load

<?php
require_once("../../db_connect/db_connect.php");
$decoded = json_decode($_GET['json']);
$ias = $decoded->{'ias'};
$ian = $decoded->{'ian'};
$select = "select iacode,ianame from isdsmot_ia_creation";
$res = mysql_query($select);
while ($row = mysql_fetch_array($res)) {
$ias = $row['iacode'];
$ian = $row['ianame'];
$ia=$ias."|".$ian;
echo "<OPTION value = \"" . $row[0] . "|" . $row[1] . "\">" . $ia . "</OPTION>";
}
$result=$ia;
if ($result) {
echo "Successful" . mysql_error();
} else {
echo "Unsuccess" . mysql_error();
}
?>
Will this help you : add around your
<?php
require_once("../../db_connect/db_connect.php");
$decoded = json_decode($_GET['json']);
$ias = $decoded->{'ias'};
$ian = $decoded->{'ian'};
$select = "select iacode,ianame from isdsmot_ia_creation";
$res = mysql_query($select);
echo '<select name="myDropDown">';
while ($row = mysql_fetch_array($res)) {
$ias = $row['iacode'];
$ian = $row['ianame'];
$ia=$ias."|".$ian;
echo "<OPTION value = \"" . $row[0] . "|" . $row[1] . "\">" . $ia . "</OPTION>";
}
echo '</select>';
$result=$ia;
if ($result) {
echo "Successful" . mysql_error();
} else {
echo "Unsuccess" . mysql_error();
}
?>

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