Well I've been having this issue now where my ajax form doesn't show my response value which I enter in the text field. I can't seem to understand why it doesn't show my post value at all.
reset.php
<html>
<head>
<script
src="https://code.jquery.com/jquery-3.1.1.js"
integrity="sha256-16cdPddA6VdVInumRGo6IbivbERE8p7CQR3HzTBuELA="
crossorigin="anonymous"></script>
<script>
function submitdata()
{
var email=document.getElementById( "emailfield" );
var datastring='email='+ emailfield;
{
$.ajax({
url: "work2.php",
type:'POST',
data:datastring
cache:false
success: function (html){
$('#msg').html();
}
});
});
</script>
</head>
<body>
<form method="POST">
E-mail: <input type="text" id="emailfield"><br>
<input value="submit" type="submit" onclick="return submitdata()">
</form>
<p id="msg"><p/>
</body>
</html>
work2.php
<?php
$email=$_POST['email'];
echo "response $email";
?>
There are few things you are missing here:
1) You are NOT getting the value from user.
Use:
var emailfield = document.getElementById( "emailfield" ).value;
OR simply
$("#emailfield").val();
2) You are not preventing the default submit process.
Use:
e.preventDefault();
I went ahead and wrote this for you. Just copy all the file and you'll see it working. Hope it helps!
<?php
$data = array();
if(isset($_POST['email'])){
$data = $_POST['email'];
echo json_encode($data);
die();
}
?>
<html>
<head>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
</head>
<body>
<form>
E-mail: <input type="text" id="emailfield"><br>
<input value="submit" type="submit">
</form>
<p id="msg"><p/>
<script type = "text/javascript">
$("form").on("submit", function(e){
e.preventDefault();
var emailfield = $("#emailfield").val();
var email ='email='+ emailfield;
$.ajax({
url: "testing.php",
method: "POST",
dataType: "json",
data: {email: email},
success: function (result) {
alert("result: " + result);
console.log(result);
$("#msg").html(result);
}
});
});
</script>
</body>
</html>
You didn't take value, it's element object, change here
var emailfield = document.getElementById( "emailfield" ).value;
Also put html with value
$('#msg').html(html);
Try it like this.
<html>
<head>
<body>
E-mail: <input type="text" id="emailfield"><br>
<button type="button">Submit</button>
<p id="msg"><p/>
<script
src="https://code.jquery.com/jquery-3.1.1.js"
integrity="sha256-16cdPddA6VdVInumRGo6IbivbERE8p7CQR3HzTBuELA="
crossorigin="anonymous"></script>
<script>
$(document).ready(function(){
$("#emailfield").on("click",function(){
var value = $("#emailfield").val();
$.ajax({
method: "POST",
url: "work2.php",
data: { email: value }
})
.done(function( data ) {
$('#msg').html(data);
});
});
});
</script>
</body>
</html>
Related
I have a file called try.php where there is code below having all javascript, PHP and html file in itself.
<?php
if(isset($_POST["submit"])){
echo "hello";
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Submit Form Using AJAX and jQuery</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
</head>
<body>
<form method="POST" id="myForm">
<input name="name" type="text" placeholder="Your Name">
<input name="email" type="text" placeholder="email">
<input name="submit" type="submit" value="Submit">
<div id="display"></div>
</form>
<script>
$(document).ready(function(){
$("#myForm").submit(function(event) {
event.preventDefault(); //prevent default action
window.history.back();
var form_Data = $(this).serialize();
$.ajax({
type: "POST",
url: "try.php",
data: form_data,
cache: false,
success:function(response){
alert(response);
}
});
});
});
</script>
</body>
</html>
The target of above code is just to submit form without reloading the page simply using AJAX and the form data should be handled by php here just echo "hello". The above code works fine it submits and php handles all properly but page is reloading. What should be the change in code?
Try this as javascript code
$(document).ready(function(){
$("#myForm").click(function(event) {
event.preventDefault(); //prevent default action
var form_Data = $(this).serialize();
$.ajax({
type: "POST",
url: "try.php",
data: form_Data,
cache: false,
success:function(){
alert("hello");
}
});
});
});
As the title says, i have try many times to get it working, but without success... the alert window show always the entire source of html part.
Where am i wrong? Please, help me.
Thanks.
PHP:
<?php
if (isset($_POST['send'])) {
$file = $_POST['fblink'];
$contents = file_get_contents($file);
echo $_POST['fblink'];
exit;
}
?>
HTML:
<html>
<head>
<script type="text/javascript" src="https://code.jquery.com/jquery-1.8.3.min.js"></script>
<script>
$(document).ready(function() {
$("input#invia").click(function(e) {
if( !confirm('Are you sure?')) {
return false;
}
var fbvideo = $("#videolink").val();
$.ajax({
type: 'POST',
data: fbvideo ,
cache: false,
//dataType: "html",
success: function(test){
alert(test);
}
});
e.preventDefault();
});
});
</script>
</head>
<div style="position:relative; margin-top:2000px;">
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input id="videolink" type="text" name="fblink" style="width:500px;">
<br>
<input id="invia" type="submit" name="send" value="Get Link!">
</form>
</div>
</html>
Your Problem is that you think, that your form fields are automatic send with ajax. But you must define each one into it.
Try this code:
<script>
$(document).ready(function() {
$("input#invia").click(function(e) {
if( !confirm('Are you sure?')) {
return false;
}
var fbvideo = $("#videolink").val();
$.ajax({
type: 'POST',
data: {
send: 1,
fblink: fbvideo
},
cache: false,
//dataType: "html",
success: function(test){
alert(test);
}
});
e.preventDefault();
});
});
</script>
Instead of define each input for itself, jQuery has the method .serialize(), with this method you can easily read all input of your form.
Look at the docs.
And maybe You use .submit() instead of click the submit button. Because the user have multiple ways the submit the form.
$("input#invia").closest('form').submit(function(e) {
You must specify the url to where you're going to send the data.
It can be manual or you can get the action attribute of your form tag.
If you need some additional as the send value, that's not as input in the form you can add it to the serialized form values with formSerializedValues += "&item" + value;' where formSerializedValues is already defined previously as formSerializedValues = <form>.serialize() (<form> is your current form).
<html>
<head>
<script type="text/javascript" src="https://code.jquery.com/jquery-1.8.3.min.js"></script>
<script>
$(document).ready(function() {
$("#invia").click(function(e) {
e.preventDefault();
if (!confirm('Are you sure?')) {
return false;
}
// Now you're getting the data in the form to send as object
let fbvideo = $("#videolink").parent().serialize();
// Better if you give it an id or a class to identify it
let formAction = $("#videolink").parent().attr('action');
// If you need any additional value that's not as input in the form
// fbvideo += '&item' + value;
$.ajax({
type: 'POST',
data: fbvideo ,
cache: false,
// dataType: "html",
// url optional in this case
// url: formAction,
success: function(test){
alert(test);
}
});
});
});
</script>
</head>
<body>
<div style="position:relative; margin-top:2000px;">
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input id="videolink" type="text" name="fblink" style="width:500px;">
<br>
<input id="invia" type="submit" name="send" value="Get Link!">
</form>
</div>
</body>
I want to send data using GET or POST to another php file on a button's(NOT Submit button) onClick() Event.
Please help me.
Let I give you simple HTML with post method using AJAX
Test.php
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script>
$(function() {
$("#Submit").click(function() {
var value = jQuery("#txt").val();
var data=jQuery('#myform_new').serializeArray();
$.post('test1.php', { myform: data});
return false;
});
});
</script>
</head>
<body>
<form id="myform_new">
<input type="text" name="abc" value="abc" id="txt"/>
<input type="text" name="abc1" value="abc1" id="txt1"/>
<input type="button" name="Submit" id="Submit" value="Submit" />
</form>
</body>
</html>
Test1.php(ajax calling file)
<?php
echo "<pre>";print_r($_POST);
?>
Let i give you some of the ajax posting method
(1)
<script>
$(function() {
$("#Submit").click(function() {
var value = jQuery("#txt").val();
var data=jQuery('#myform_new').serializeArray();
$.post('test1.php', { myform: data});
return false;
});
});
</script>
(2)
<script type="text/javascript"> $(function() { $("#Submit").click(function()
{
var txt = jQuery("#txt").val();
var txt1 = jQuery("#txt").val();
$.post('test1.php', { txt: txt,txt1:txt1 }); return false; }); });
</script>
(3)
<script type="text/javascript"> $(function() { $("#Submit").click(function() {
var txt = jQuery("#txt").val();
var txt1 = jQuery("#txt").val();
$.post('test1.php', { data: "txt="+txt+"&txt1="+txt1}); return false; }); });
</script>
Hello in there i have explain both ajax and get/post method, Please have look below link for get/post method for submit a form in php.
http://www.tutorialspoint.com/php/php_get_post.htm
This below code is used for submit form using ajax
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
</head>
<body>
<form id="formoid" action="studentFormInsert.php" title="" method="post">
<div>
<label class="title">First Name</label>
<input type="text" id="name" name="name" >
</div>
<div>
<label class="title">Name</label>
<input type="text" id="name2" name="name2" >
</div>
<div>
<input type="submit" id="submitButton" name="submitButton" value="Submit">
</div>
</form>
<script type='text/javascript'>
/* attach a submit handler to the form */
$("#formoid").submit(function(event) {
/* stop form from submitting normally */
event.preventDefault();
/* get some values from elements on the page: */
var $form = $( this ),
url = $form.attr( 'action' );
/* Send the data using post */
var posting = $.post( url, { name: $('#name').val(), name2: $('#name2').val() } );
/* Alerts the results */
posting.done(function( data ) {
alert('success');
});
});
</script>
</body>
</html>
I got a problem in ajax I can't add information on mysql so here's what I got:
a index.php file with a table form
<form method="post" name="form" action="">
<textarea style="width:500px; font-size:14px; height:60px; font-weight:bold; resize:none;" name="content" id="content" ></textarea><br />
<input type="submit" value="Post" name="submit" class="submit_button"/>
</form>
and a insert.php file:
<?php
include('config.php');
$content=mysql_real_escape_string($_POST['content']);
$query=mysql_query("INSERT INTO chat(ChatId,ChatText) VALUES('','$content') ");
echo $content;
?>
I leave there the echo $content; because it helps to understand my problem. So... When i write something in my box and I click on submit to insert the information into my sql table It dosen't insert so I leave there the echo code because I'm sure the information reach to my insert.php file.. so I don't really understand why the information is not inserted because the information comes. Any help?
ajax part:
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function(){
setInterval(function(){
$("#ChatMessages").load("msgs.php");
},1000);
});
</script>
<script type="text/javascript" src="jquery.min.js"></script>
<script type="text/javascript">
$(function() {
$(".submit_button").click(function() {
var textcontent = $("#content").val();
var dataString = 'content='+ textcontent;
if(textcontent=='')
{
alert("Enter some text..");
$("#content").focus();
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html('<span class="load">Loading..</span>');
$.ajax({
type: "POST",
url: "insert.php",
data: dataString,
cache: true,
success: function(html){
$("#show").after(html);
document.getElementById('content').value='';
$("#flash").hide();
$("#content").focus();
}
});
}
return false;
});
});
</script>
I'm using jQuery's .ajax() to post to a PHP file called process.php. Process.php has a lot of code in it, but for simplicity's sake, let's just say it contains <?php echo 'hello'; ?>.
Is this the proper jQuery to insert process.php's results into div.results? :
$.get('process.php', function(data) {
$('.results').html(data);
});
So far it doesn't seem to be working.
Here's the HTML/Javascript file
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8" />
<script type="text/javascript" src="http://code.jquery.com/jquery-1.5.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("form#form").submit(function() {
var username = $('#username').attr('value');
$.ajax({
type: 'POST',
url: 'process.php',
data: 'username=' + username,
success: function() {
$('form#form').hide(function() {
$.get('process.php', function(data) {
$('.results').html(data);
});
});
}
});
return false;
});
});
</script>
</head>
<body id="body">
<form id="form" method="post">
<p>Your username: <input type="text" value="" name="username" id="username" /></p>
<input type="submit" id="submit" value="Submit" />
</form>
<div class="results"></div>
</body>
</html>
Here's process.php (greatly simplified):
<?php
/* get info from ajax post */
$username = htmlspecialchars(trim($_POST['username']));
echo $username;
?>
If you simply want to place the resulting string back into an element, use load().
$('.results').load('process.php');
However, looking at your code...
$.ajax({
type: 'POST',
url: 'process.php',
data: 'username=' + username,
success: function() {
$('form#form').hide(function() {
$.get('process.php', function(data) {
$('.results').html(data);
});
});
}
});
...shows you have misunderstood something. The correct anonymous function to assign to the success callback would be...
function(data) {
$('form#form').hide()
$('.results').html(data);
}
You could try something like this.
function ajax_login() {
if ($("#username").val()) {
$.post("/process.php", { username : $("#username").val() }, function(data) {
if (data.length) {
$("#login_form").hide();
$("#login_result").html(data);
}
})
} else {
$("#login_result").hide();
}
Then in process.php just echo out some text if the post sucesses.
process.php =>
if (isset($_POST['username'])
{
echo 'hello '.$_POST['username'];
}