Grab video URL from external URL [closed] - php

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I'm trying to access the URL of the video element from an external URL.
That's an example of the url I'm trying to access:
https://www.musical.ly/v/MzA4NTExODI2MDI0MjMzNDgxOTEyMzI.html
file_get_contents and curl return an html code without the video in it, what am I doing wrong?
Any PHP/jQuery solution would be great!

Answer 1

It seems like the MzA4NTExODI2MDI0MjMzNDgxOTEyMzI-part of the url is the video key.
They are calling: https://www.musical.ly/rest/v2/musicals/shareInfo?key=MzA4NT‌​ExODI2MDI0MjMzNDgxOT‌​EyMzI to fetch the video information in json format.
You could do the same and just use the videoUri from the json response?
Example
Just for fun, I created an example how to fetch it from the initial URL. This would of course need a bit of validation and such, but it is a working example:
<?php
$url = 'https://www.musical.ly/v/MzA4NTExODI2MDI0MjMzNDgxOTEyMzI.html';
// Extract the url path and explode the segments
$segments = explode('/', parse_url($url, PHP_URL_PATH));
if (isset($segments[2])) {
// We have the key segment so let's build the URL to fetch the info
$infoUrl = 'https://www.musical.ly/rest/v2/musicals/shareInfo?key=' . rtrim($segments[2], '.html');
$info = file_get_contents($infoUrl);
$info = $info ? json_decode($info, true) : null;
}
if (isset($info['result'], $info['result']['videoUri'])) {
// We have all we need, let's get the video uri
echo $info['result']['videoUri'];
} else {
die('No video URI found');
}