How to split and change the json format - php

Question

I am using slimphp v2 and I have the following function
function gt($user) {
$sql = "select id, id as categoryId, mobile, task from actions where status=0";
try {
$db = newDB($user);
$stmt = $db - > prepare($sql);
$stmt - > execute();
$gs = $stmt - > fetchAll(PDO::FETCH_OBJ);
if ($gs) {
$db = null;
echo json_encode($gs, JSON_UNESCAPED_UNICODE);
} else {
echo "Not Found";
}
} catch (PDOException $e) {
echo '{"error":{"text":'.$e - > getMessage().
'}}';
}
}
The default json output looks like:
[{
"id": "1",
"categoryId": "1",
"mobile": "111",
"task": "test"
},
{
"id": "2",
"categoryId": "2",
"mobile": "222",
"task": "test2"
}]
and the output that i am trying to make. I need to generate an ID: 1_(id) then format it like this
[{
id: "1",
task: "test",
}, {
ID: "1_1", //generate this, add 1_id
categoryId: "1",
mobile: "00000",
}, {
id: "2",
task: "test2",
}, {
ID: "1_2", //generate this, add 1_id
categoryId: "2",
mobile: "11111"
}];
Is it possible?
Thanks

Answer 1

I'm not sure if this is exactly what your after but you can gain the desired JSON output by converting your original JSON into an associative array and then restructure the data on each iteration using a Foreach() loop into a new assoc array. After that, you can just convert it back to JSON using json_encode().
Code:
$json = '[{
"id": "1",
"categoryId": "1",
"mobile": "111",
"task": "test"
},
{
"id": "2",
"categoryId": "2",
"mobile": "222",
"task": "test2"
}]';
$jsonArr = json_decode($json, TRUE);
$newArr = [];
foreach ($jsonArr as $v) {
$newArr[] = ['id:'=>$v['id'], 'task:' => $v['task']];
$newArr[] = ['ID:'=>'1_' . $v['id'], 'categoryId' => $v['categoryId'], 'mobile'=>$v['mobile']];
}
$newJson = json_encode($newArr);
var_dump($newJson);
Output:
[{
"id:": "1",
"task:": "test"
}, {
"ID:": "1_1",
"categoryId": "1",
"mobile": "111"
}, {
"id:": "2",
"task:": "test2"
}, {
"ID:": "1_2",
"categoryId": "2",
"mobile": "222"
}]
Edit -- Updated Answer
As discussed in comments, your outputting your SQL array as an object. I've set the Fetch to output as an associative array using PDO::FETCH_ASSOC and changed the foreach() loop to reference the assoc array $gs. This should work but if not then output your results for $gs again using var_dump($gs). You will still need to encode to JSON if needed but this line has been commented out.
function gt($user) {
$sql = "select id, id as categoryId, mobile, task from actions where status=0";
try {
$db = newDB($user);
$stmt = $db->prepare($sql);
$stmt->execute();
$gs = $stmt->fetchAll(PDO::FETCH_ASSOC); //Fetch as Associative Array
if ($gs) {
$db = null;
$newArr = [];
foreach ($gs as $v) { //$gs Array should still work with foreach loop
$newArr[] = ['id:'=>$v['id'], 'task:' => $v['task']];
$newArr[] = ['ID:'=>'1_' . $v['id'], 'categoryId' => $v['categoryId'], 'mobile'=>$v['mobile']];
}
//$newJson = json_encode($newArr); //JSON encode here if you want it converted to JSON.
} else {
echo "Not Found";
}
} catch(PDOException $e) {
//error_log($e->getMessage(), 3, '/var/tmp/php.log');
echo '{"error":{"text":'. $e->getMessage() .'}}';
}
}