Get a resulting array after removing similiar values from 2 different array - php

Question

There are 2 set of code and each gives 2 different array
First set is this
$this->db->select('id');
$query = $this->db->get('user');
echo "<pre>";
print_r( $query->result());
echo "</pre>";
And gives the following result
Array
(
[0] => stdClass Object
(
[id] => 1
)
[1] => stdClass Object
(
[id] => 2
)
)
Second one is this
$this->db->select('user_id');
$query_two = $this->db->get('request_user');
echo "<pre>";
print_r( $query_two->result());
echo "</pre>";
And gives the following result
Array
(
[0] => stdClass Object
(
[user_id] => 1
)
)
I wish to get final array that should not have the duplicate values, eg in the above 2 array 1 is common in both the array so it should not be there and in resulting array i should get only value 2

Answer 1

You could take the following approach. Make a list of ids from your second array. And then use that list to filter the first. If an id is not in that list: keep it.
<?php
$one = [
(object) ['id' => 1],
(object) ['id' => 2],
];
$two = [
(object) ['id' => 1],
];
$ids_in_two = [];
foreach($two as $val) {
$ids_in_two[] = $val->id;
}
$filtered = array_filter($one, function($val) use ($ids_in_two) {
return !in_array($val->id, $ids_in_two);
});
var_dump($filtered);
Output:
array(1) {
[0]=>
object(stdClass)#1 (1) {
["id"]=>
int(2)
}
}