2D Array in PHP Fails When Trying to Find Matching String - php

I'm still learning PHP, but I needed a way of keeping track of a list of two associated values, a cinema and its postcode. Now before you read any further I must stress that I do not technically need this problem solving as I have since replaced it with a more efficient method. I'm really just wanting to know why it doesn't work as I can't find anything about it elsewhere.
$cinema_locations = array(
array("Odeon", "M4 2BS"),
array("Cineworld", "OL7 0PG"),
array("Vue", "M50 3AG"),
array("AMC", "M3 4EN")
);
for ($i=0; $i<count($cinema_locations); $i++) {
if ($cinema_locations[$i][0] == $_GET['cinema_name']) {
$postcode = $cinema_locations[$i][1];
return;
}
}
As you can probably tell from the code, I am trying to loop through the main array so that I may compare the first value of each child array against a $_GET variable. I have checked over this code multiple times and even showed some of my other coder friends and none of us can find anything wrong, syntax or otherwise. And yet, the browser shows only a white screen. If anyone can shed some light on the issue, I and my friends would be most appreciative; and who knows, it may help someone else with the same issue.
For anyone that may be curious, I replaced the 2D array with an associative array thus:
$cinema_locations = array(
"Odeon" => "M4 2BS",
"Cineworld" => "OL7 0PG",
"Vue" => "M50 3AG",
"AMC" => "M3 4EN"
);
$postcode = $cinema_locations[$_GET['cinema_name']];
EDIT
Thanks rishi, that did it. I never even considered that the return would nullify the result. Using break stopped the loop and the rest of the page loaded fine.

May be you should write break; instead of return;
You needed to break your for loop if you meet the condition. and continue with the below code.
return will instantly returns value from where its called.

For situations in which you cannot change the array structure, this code is a better approach.
// same array as the original post
$cinema_locations = array(
array("Odeon", "M4 2BS"),
array("Cineworld", "OL7 0PG"),
array("Vue", "M50 3AG"),
array("AMC", "M3 4EN")
);
foreach ($cinema_locations as $c_loc) {
$postcode = ($_GET'cinema_name'] == $c_loc[0]) ? $c_loc[1] : null;
}
print $postcode;
Of course, you should never use $_GET directly like this, but you probably already knew that.

Related

PHP 7 - IF statements doesn't seem to work while trying to detect KEYS in $_SESSION arrays

[PHP 7.1]
Below you can see my PHP code. My problem comes from my difficult to understand why the second IF statement doesn't work with the array $_SESSION['items'], but does work with the testing array $zoo (I just created $zoo to make tests in place of $_SESSION['items']).
I've an AJAX script that send POST data to the PHP code and then logs the response to the browser console in order to let me review the results. Everything was working fine with my tests, all changes done to other arrays where executed with fine results, the only issue I couldn't understand and solve, even after extensively searching for some clues on the web and trying different things, is the misterious ways of the $_SESSION array that doesn't seem to like to expose its keys to lurking IF statements... And I got here trying to detect the existence of a key inside an array in order to increment its value. Something I already did before with other arrays that weren't $_SESSION arrays and it worked just fine.
session_start();
$_SESSION['items'] = array();
$zoo['animals'] = array('tiger'=>2,'lion'=>3);
if(isset($_POST['item_name'])) {
if (isset($_SESSION['items'][$_POST['item_name']]) || array_key_exists($_POST['item_name'], $_SESSION['items'])) {
$_SESSION['items'][$_POST['item_name']]['qnt']++;
} else {
$_SESSION['item_name'][$_POST['item_name']] = array('model'=>$_POST['item_model'], 'qnt'=>1);
}
echo json_encode($_SESSION['items']);
exit();
}
This is a simplified version of your code with just the important stuff
session_start();
$_SESSION['items'] = array(); //items is now emtpy
if (isset($_SESSION['items'][$_POST['item_name']]) || array_key_exists($_POST['item_name'], $_SESSION['items'])) {
}
This should make it a bit easier to see, so it's simply because items is an empty array. Do to assigning it as such before the condition.
To fix it, either remove this line:
$_SESSION['items'] = array();
OR better yet:
$_SESSION['items'] = isset($_SESSION['items']) ? $_SESSION['items'] : [];
OR even
if(!isset($_SESSION['items'])) $_SESSION['items'] = [];
It's up to you how you fix it, but I am certain you don't want to reset that to an empty array. It's a very easy mistake to make, and a hard one to find because it's technically legal PHP code. I just have a built in debugger in my head now, from years of coding ... lol ... Most times I can literally picture in my mind how something will execute.
Cheers!
As noted by #artisticphoenix -
session_start();
// Check to see if there is a session variable before clearing it
// You only want to initialize it once
if (!isset($_SESSION['items'])) {
$_SESSION['items'] = [];
}
$zoo['animals'] = array('tiger'=>2,'lion'=>3);
if(isset($_POST['item_name'])) {
// This test is sufficient to check if the session variable has been set
if (isset($_SESSION['items'][$_POST['item_name']])) {
$_SESSION['items'][$_POST['item_name']]['qnt']++;
} else {
$_SESSION['items'][$_POST['item_name']] = array('model'=>$_POST['item_model'], 'qnt'=>1);
}
echo json_encode($_SESSION['items']);
exit();
}
$_SESSION['item_name'] should be $_SESSION['items']

php use value as a variable name (for a key) from an array to unpack a resultset from Drupal

I will be reusing a Drupal db_query result set unpacking function many, many times in my code for a variety of different queries - I am using O-O and as such I want to reuse it and be as 'DRY' as possible.
Therefore I have tried to strip it down to the most generic functions so that as long as the $columns supplied match the columns used in the query and similarly in the $resultset, I can loop and assign values to keys, as is shown, and return a $rows[].
I've not yet come across the issue of trying to use a variable's value as a variable name (the $key), if it's just something I should avoid entirely, please say.
foreach($this->resultSet as $aRecord) {
$c = 0;
while (isset($this->columns[$c])) {
$value = $this->columns[$c];
$rows[$i] = array(
$key[$this->columns[$c]] => $aRecord->$value,
);
$c++;
}
$i++;
}
I've read through the following and am beginning to think this is just knowledge I'm missing in my PHP experience so far.
Can I use a generated variable name in PHP?
PHP use function return value as array
https://wiki.php.net/rfc/functionarraydereferencing
It felt wrong, and someone once told me that if you have to start writing complex functions in PHP you've probably missed an available function PHP already offers.. so true... thanks to (at the time of writing...) 'MrCode' for this suggestion.
$this->sql = "SELECT foo, bar FROM foobar";
$this->result = db_query($this->sql);
if ($this->result->rowCount() > 0) {
while ($row = $this->result->fetchAssoc()) {
$this->resultArray[] = $row;
}
}

PHP isset not working properly on form, with loops and arrays

This is honestly the most finicky and inept language I've ever coded in. I'll be glad when this project is good and over with.
In any case I have to us PHP so here's my question.
I have an Array named $form_data as such:
$form_data = array
('trav_emer_med_insur',
'trav_emer_single',
'trav_emer_single_date_go',
'trav_emer_single_date_ba',
'trav_emer_annual',
'trav_emer_annual_date_go',
'trav_emer_extend',
'trav_emer_extend_date_go',
'trav_emer_extend_date_ef',
'trav_emer_extend_date_ba',
'allinc_insur',
'allinc_insur_opt1',
'allinc_single_date_go',
'allinc_single_date_ba',
'allinc_insur_opt2',
'allinc_annual_date_go',
'allinc_annual_date_ba',
'cancel_insur',
'allinc_annual_date_go',
'allinc_annual_date_ba',
'visitor_insur',
'country_select',
'visitor_supervisa',
'visitor_supervisa_date_go',
'visitor_supervisa_date_ba',
'visitor_student',
'visitor_student_date_go',
'visitor_student_date_ba',
'visitor_xpat',
'visitor_xpat_date_go',
'visitor_xpat_date_ba',
'txtApp1Name',
'txtApp2Name',
'txtApp1DOB',
'txtApp2DOB',
'txtApp1Add',
'txtApp1City',
'selprov',
'txtApp1Postal',
'txtApp1Phone',
'txtApp1Ext',
'txtApp1Email',
'conpref', );
These are the names of name="" fields on an HTML form. I have verified that ALL names exist and have a default value of '' using var_dump($_POST).
What I want to do is very simple, using the $form_data as reference do this:
create a new array called $out_data which can handle the data to display on a regurgitated form.
The structure of $out_data is simple the key will be the name of the element from the other array $out_data[txtApp1Name] for example, and then the value of that key will be the value.
Now what I want is to first check to see if every name="" is set or not, to eliminate errors and verify the data. Then regardless of whether it is set or not, create its placeholder in the $out_data array.
So if $_POST[$form_data[1]] (name is 'trav_emer_single') is not set create an entry in $out_data that looks like this $out_data([trav_emer_single] => "NO DATA")
If $_POST[$form_data[1]] (name is 'trav_emer_single') is set create and entry in $out_data that looks like this: $out_data([trav_emer_single] => "whatever the user typed in")
I have tried this code:
$out_data = array();
$count = count($form_data);
for( $i = 0; $i < $count; $i++ )
{
if(!isset($_POST[$form_data[$i]])) {
$out_data[$form_data[$i]] = "NO_DATA";
}
else {
$out_data[$form_data[$i]] = $_POST[$form_data[$i]];
}
}
Now this code technically is working, it is going through the array and assigning values, but it is not doing so properly.
I have hit submit on the form with NOTHING entered. Therefore every item should say "NO_DATA" on my regurgitated output (for user review), however only some items are saying it. All items I have confirmed have name="" and match the array, and have nothing entered in them. Why is "NO_DATA" not being assigned to every item in the array?
Also of note, if I fill in the form completely $out_data is fully and correctly populated. What is the problem with !isset? I've tried doing $_POST[$form_data[$i]] == '' which does put no_data in every instance of no data, however it throws an 'undefined index' warning for every single item on the page whether I write something in the box or not.
Really I just want to know WTF is going on, the dead line for this project is closing fast and EVERY step of the PHP gives me grief.
As far as I can tell by reading around my code is valid, but refuses to execute as advertised.
If you need more code samples please ask.
Really befuddled here, nothing works without an error, help please.
Thanks
-Sean
Instead of checking !isset(), use empty(). If the form posts an empty string, it will still show up in the $_POST as an empty string, and isset() would return TRUE.
I've replaced your incremental for loop with a foreach loop, which is almost always used in PHP for iterating an array.
$out_data = array();
foreach ($form_data as $key) {
if(empty($_POST[$key])) {
$out_data[$key] = "NO_DATA";
}
else {
$out_data[$key] = $_POST[$key];
}
}
PHP's isset returns TRUE unless the variable is undefined or it is NULL. The empty string "" does not cause it to return FALSE. empty() will do exactly what you need, though.
http://php.net/manual/en/function.isset.php
isset() will return FALSE if testing a variable that has been set to
NULL. Also note that a NULL byte ("\0") is not equivalent to the PHP
NULL constant.
Returns TRUE if var exists and has value other than NULL, FALSE
otherwise.

php session variable multidimensional associative array issue

I've looked around SO, but can't find an explanation to what is going on in my $_SESSION variables.
#ob_start();
$k=#ob_get_contents();
#ob_end_clean();
#session_start();
unset($s,$m);
$m1 = explode(" ", microtime());
$stime = $m1[1] + $m1[0];
echo $k;
$_SESSION['resendConfirmation']['function'] = 'resend';
$_SESSION['resendConfirmation']['id'] = '8';
print_r($_SESSION);
outputs:
Array ( [resendConfirmation] => 8esend )
Why is it string replacing? I've never had this issue before.
What I want is thus:
Array([resendConfirmation] => Array(
[id] =>8
[function} => resend
)
)
I've never had this happen before, I'm totally confused!
UPDATE
In response to #DanRedux I've changed to two non-existent variable names to take the referencing out of the equation, still the same result...
$_SESSION['resendConfirmation']['tweak'] = 'resend';
$_SESSION['resendConfirmation']['tweak2'] = '8';
Same result :(
Did a sitewide query of resendConfirmation and none were found, but once I change that array name, it all worked, baffled, but fixed...
$_SESSION['reConfirm']['function'] = 'resend';
$_SESSION['reConfirm']['id'] = '8';
print_r($_SESSION);
Since I dont really know what other sorts of shenanigans the code is up to outside of this block you gave us I would say to just try this instead:
$_SESSION['resendConfirmation'] = array('id' => 8, 'function' => 'resend');
If this also fails then there has to be something else going on outside of what you posted. Good luck!
What you think is an multidimensional array really isn't. What really happens is:
What you think is an array is really a string. After that you are trying to access the string as an array. You are trying to access the element id which doesn't exists. PHP always tries to be smarter than it should and just says: OK I'll assume you meant the first index. So basically what happens is:
<?php
$notAnArray = 'somestring';
$notAnArray['id'] = '8';
var_dump($notAnArray); // 8omestring
This is the reason you should always enable error_reporting on your development machine:
error_reporting(E_ALL | E_STRICT);
ini_set("display_errors", 1);
And never suppress errors using #. Well there are some situations where you can use #, but this really isn't one of them.

PHP: testing for existence of a cell in a multidimensional array

I have an array with numerous dimensions, and I want to test for the existence of a cell.
The below cascaded approach, will be for sure a safe way to do it:
if (array_key_exists($arr, 'dim1Key'))
if (array_key_exists($arr['dim1Key'], 'dim2Key'))
if (array_key_exists($arr['dim1Key']['dim2Key'], 'dim3Key'))
echo "cell exists";
But is there a simpler way?
I'll go into more details about this:
Can I perform this check in one single statement?
Do I have to use array_key_exist or can I use something like isset? When do I use each and why?
isset() is the cannonical method of testing, even for multidimensional arrays. Unless you need to know exactly which dimension is missing, then something like
isset($arr[1][2][3])
is perfectly acceptable, even if the [1] and [2] elements aren't there (3 can't exist unless 1 and 2 are there).
However, if you have
$arr['a'] = null;
then
isset($arr['a']); // false
array_key_exists('a', $arr); // true
comment followup:
Maybe this analogy will help. Think of a PHP variable (an actual variable, an array element, etc...) as a cardboard box:
isset() looks inside the box and figures out if the box's contents can be typecast to something that's "not null". It doesn't care if the box exists or not - it only cares about the box's contents. If the box doesn't exist, then it obviously can't contain anything.
array_key_exists() checks if the box itself exists or not. The contents of the box are irrelevant, it's checking for traces of cardboard.
I was having the same problem, except i needed it for some Drupal stuff. I also needed to check if objects contained items as well as arrays. Here's the code I made, its a recursive search that looks to see if objects contain the value as well as arrays. Thought someone might find it useful.
function recursiveIsset($variable, $checkArray, $i=0) {
$new_var = null;
if(is_array($variable) && array_key_exists($checkArray[$i], $variable))
$new_var = $variable[$checkArray[$i]];
else if(is_object($variable) && array_key_exists($checkArray[$i], $variable))
$new_var = $variable->$checkArray[$i];
if(!isset($new_var))
return false;
else if(count($checkArray) > $i + 1)
return recursiveIsset($new_var, $checkArray, $i+1);
else
return $new_var;
}
Use: For instance
recursiveIsset($variables, array('content', 'body', '#object', 'body', 'und'))
In my case in drupal this ment for me that the following variable existed
$variables['content']['body']['#object']->body['und']
due note that just because '#object' is called object does not mean that it is. My recursive search also would return true if this location existed
$variables->content->body['#object']->body['und']
For a fast one liner you can use has method from this array library:
Arr::has('dim1Key.dim2Key.dim3Key')
Big benefit is that you can use dot notation to specify array keys which makes things simpler and more elegant.
Also, this method will work as expected for null value because it internally uses array_key_exists.
If you want to check $arr['dim1Key']['dim2Key']['dim3Key'], to be safe you need to check if all arrays exist before dim3Key. Then you can use array_key_exists.
So yes, there is a simpler way using one single if statement like the following:
if (isset($arr['dim1Key']['dim2Key']) &&
array_key_exists('dim3Key', $arr['dim1Key']['dim2Key'])) ...
I prefer creating a helper function like the following:
function my_isset_multi( $arr,$keys ){
foreach( $keys as $key ){
if( !isset( $arr[$key] ) ){
return false;
}
$arr = $arr[$key];
}
return $arr;
}
Then in my code, I first check the array using the function above, and if it doesn't return false, it will return the array itself.
Imagine you have this kind of array:
$arr = array( 'sample-1' => 'value-1','sample-2' => 'value-2','sample-3' => 'value-3' );
You can write something like this:
$arr = my_isset_multi( $arr,array( 'sample-1','sample-2','sample-3' ) );
if( $arr ){
//You can use the variable $arr without problems
}
The function my_isset_multi will check for every level of the array, and if a key is not set, it will return false.

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