I am trying to display all the info in the table but when I query the information then put it into a PHP table it doesn't show any data in the last table.
Here is my PHP code for the table
<table border='1'>
<tr>
<th>Ticket ID</th>
<th>Username</th>
<th>Message</th>
<th>Date</th>
<th>Error #</th>
<th>Priority</th>
</tr>
<?php
if(!$query){
die('Invalid query: ' .mysql_error());
}
while ($row = mysql_fetch_array($query)) { ?>
<tr>
<td><?php echo $row['TicketID']; ?></td>
<td><?php echo $row['Message']; ?></td>
<td><?php echo $row['Date']; ?></td>
<td><?php echo $row['Error']; ?></td>
<td><?php echo $row['Priority']; ?></td>
</tr>
<?php } ?>
</table>
Here is the PHP code for query
<?php
$server = mysql_connect("localhost", "root", "**password**");
$db = mysql_select_db("minecraft", $server);
$query = mysql_query("SELECT * FROM tickets");
?>
All of my row names are correct but it doesn't want to put the data into that column.
Here is my table structure
You Omitted
<td><?php echo $row['Username']; ?></td>
that should be after
<td><?php echo $row['TicketID']; ?></td>
Related
I have a table for saving details including logging time.Just as soon as a new record is inserted I want the column 'Countdown' to start an automatic time countdown from 30min until it gets to zero(0).How do I go about it?Thanks.
Here is the table php code
`<?php $results = mysqli_query($db, "SELECT
Vehicle_name,Vehicle_make,Vehicle_color,Number_plate,Date,Time FROM
vehicle"); ?>
<div class="table">
<table>
<thead>
<tr>
<th>Vehicle name</th>
<th>Vehicle make</th>
<th>Vehicle color</th>
<th>Reg Number</th>
<th>Date</th>
<th>Time</th>
<th>Countdown</th>
<th colspan="4">Action</th>
</tr>
</thead>
<?php while ($row = mysqli_fetch_array($results)) { ?>
<tr>
<td><?php echo $row['Vehicle_name']; ?></td>
<td><?php echo $row['Vehicle_make']; ?></td>
<td><?php echo $row['Vehicle_color']; ?></td>
<td><?php echo $row['Number_plate']; ?></td>
<td><?php echo $row['Date']; ?></td>
<td><?php echo $row['Time']; ?></td>
<td><?php echo $row['Time']; ?></td>
<td>
<a href="php_code.php?del=<?php echo $row['Number_plate']; ?>"
class="del_btn">Delete</a>
</td>
</tr>
<?php } ?>
`
I have two tables one for products and another for items.
I want to show all items details for each product in one table like this:
I have tried to make a nested while loops but the result not as I want.
<table border="1">
<thead>
<th>Product No.</th>
<th>Product Name</th>
<th>T.Qty</th>
<th>Item No.</th>
<th>Item Name</th>
<th>Qty </th>
</thead>
<tbody>
<tr>
<td><?php echo $Product_no ?></td>
<td><?php echo $Product_name?></td>
<td><?php echo $TQty ?></td>
<?php
// my problem is here
$Items= $connect->prepare("Query Statment?");
$Items->execute();
$res = $Items->get_result();
while($GetItems = $res->fetch_assoc()){
?>
<td><?php echo GetItems['Item_no'];?></td>
<td><?php echo GetItems['Item_name']; ?></td>
<td><?php echo GetItems['Qty']; ?></td>
<?php } ?>
</tr>
</tbody>
</table>
but the items displayed beside each other not below.
You have a problem in your html table code. You should close the tag for each row you have, and, in case it is not the first line for that element, insert 3 cells with no data:
<tbody>
<tr>
<td><?php echo $Product_no ?></td>
<td><?php echo $Product_name?></td>
<td><?php echo $TQty ?></td>
<?php
// my problem is here
$Items= $connect->prepare("Query Statment?");
$Items->execute();
$res = $Items->get_result();
$i=0;
while($GetItems = $res->fetch_assoc()){
if ($i!=0){
echo "<td></td><td></td><td></td>";
}
?>
<td><?php echo GetItems['Item_no'];?></td>
<td><?php echo GetItems['Item_name']; ?></td>
<td><?php echo GetItems['Qty']; ?></td>
<?php
echo "</tr>";
$i++;
} ?>
</tbody>
I wrote a MySQL query in my PHP code to join two tables, but I don't want all the columns in the result
My place details table:
My registration table:
My Code
<?php
$con= mysqli_connect("localhost", "root", "", "project");
if(!$con)
{
die('not connected');
}
$result= mysqli_query($con, "SELECT placedetails.name,placedetails.doj,placedetails.total,placedetails.stay,placedetails.food,placedetails.travel,registration.username
FROM placedetails inner join registration on placedetails.id=registration.id ;" );
?>
<div class="container">
<CENTER><h2>view Booking Details</h2>
<table class="table table-bordered">
<th>place</th>
<th>Travelling Date</th>
<th>Total Cost</th>
<th>Stay cost</th>
<th>Food cost</th>
<th>Travelling cost</th>
<th>User ID</th>
<?php
while($row =mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['doj']; ?></td>
<td><?php echo $row['total'] ;?></td>
<td><?php echo $row['stay'] ;?></td>
<td><?php echo $row['food'] ;?></td>
<td><?php echo $row['travel'] ;?></td>
<td><?php echo $row['username'] ;?></td>
<td><img src='".$row['choose']."'/></td>";
</tr>
<?php
}
?>
</table>
</div>
i wrote my code,its executing but the problem is the data is not executing,can someone please help me out with my problem.
MysqlAdmin
In your table place details create a new entry call ID_regist.
After that change or give a number that correspond to your id in tabel Regist.
code php
For the connection create a connection.php.
<?php
$con= mysqli_connect("localhost", "root", "", "project");
if(!$con)
{
die('not connected');
}
?>
Makes your database more difficult to attack
Main code
<?php
include("connection.php");
?>
<div class="container">
<CENTER><h2>view Booking Details</h2>
<table class="table table-bordered">
<th>place</th>
<th>Travelling Date</th>
<th>Total Cost</th>
<th>Stay cost</th>
<th>Food cost</th>
<th>Travelling cost</th>
<th>User ID</th>
<?php
$sql=
"SELECT ".
"pld.name, ".
"pld.doj, ".
"pld.total, ".
"pld.stay, ".
"pld.food, ".
"pld.travel, ".
"pld.username ".
"FROM placedetails pld ".
"inner join registration reg ".
"on pld.ID_regist=reg.id;";
$result= mysqli_query($con, $sql);
if($result){
while($row =mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['doj']; ?></td>
<td><?php echo $row['total'] ;?></td>
<td><?php echo $row['stay'] ;?></td>
<td><?php echo $row['food'] ;?></td>
<td><?php echo $row['travel'] ;?></td>
<td><?php echo $row['username'] ;?></td>
<td><img src='".$row['choose']."'/></td>"; // first there is no row, call chose
</tr>
<?php
}
}
else{
die("Error"); //Something of the type mysqli_error(connection);
}
?>
</table>
</div>
Attention to the row call chose, that you don't use in your sql query.
If that does not solve your problems, tell me what happens when I try to help you.
You have to alter the place table and add registration_id. Then join with this field.
SELECT placedetails.name,placedetails.doj,placedetails.total,placedetails.stay,placedetails.food,placedetails.travel,registration.username
FROM placedetails inner join registration on registration.id=place.registration_id
I wrote code to retrieve data from database and to print in form of tables on my web. I have stored 4 columns of data in my database but while retrieving it's only showing one column.
My database image
My webpage
My code:
<?php
$con = mysqli_connect("localhost", "root", "", "project");
if(!$con)
{
die('not connected');
}
$result= mysqli_query($con, "SELECT name, stay, food, travel,
SUM(stay + food + travel) AS totalamount,doj
FROM placedetails ");
?>
<div class="container">
<table class="table table-hover">
<thead>
<tr>
<th>place</th>
<th>stay cost</th>
<th>food cost</th>
<th>flight cost</th>
<th>Date of journey</th>
<th>Total cost</th>
</tr>
</thead>
<?php
while($row =mysqli_fetch_array($result))
{
?>
<tbody>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['stay']; ?></td>
<td><?php echo $row['food'] ;?></td>
<td><?php echo $row['travel'] ;?></td>
<td><?php echo $row['doj'] ;?></td>
<td><?php echo $row['totalamount'] ;?></td>
</tr>
</tbody>
<?php
}
?>
</table>
</div>
</div>
Can anyone can tell where the mistake is?
And one more question: I want to diplay only the recent uploaded data on my web page. Suppose I have 4 names as mumbai, but uploaded at different times, I want to display the most recently added mumbai name on my web page
Can anyone help me out in this matter? I will be very thankful..
update your code as move tbody from php loop
<div class="container">
<table class="table table-hover">
<thead>
<tr>
<th>place</th>
<th>stay cost</th>
<th>food cost</th>
<th>flight cost</th>
<th>Date of journey</th>
<th>Total cost</th>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_assoc($result))
{
?>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['stay']; ?></td>
<td><?php echo $row['food'] ;?></td>
<td><?php echo $row['travel'] ;?></td>
<td><?php echo $row['doj'] ;?></td>
<td><?php echo $row['totalamount'] ;?></td>
</tr>
<?php
}
?>
</tbody>
</table>
</div>
1) <tbody> should be outside of while loop
2) if you want show only one record means no need to use while loop
3) if you want show recent record means just do descending sort by date column or id column
Query :
SELECT name, stay, food, travel, SUM(stay + food + travel) AS totalamount,doj FROM placedetails order by doj desc limit 1;
Table :
<tbody>
<?php
$row = mysqli_fetch_assoc($result); //fetch first record set only
?>
<tr>
<td><?php echo $row['name']; ?></td>
<td><?php echo $row['stay']; ?></td>
<td><?php echo $row['food']; ?></td>
<td><?php echo $row['travel']; ?></td>
<td><?php echo $row['doj']; ?></td>
<td><?php echo $row['totalamount'];?></td>
</tr>
</tbody>
Here is my code, I get the items to show but nothing will echo in the tags. I tried just removing the php echo statements and just try writing in some text but still nothing. Thanks in advance
<?php
//Create a connection
$connect = mysqli_connect('localhost', 'root', 'bachi619', 'company');
//check connection
if(mysqli_connect_errno($connect)){
echo 'Failed to connecto to database'.mysqli_connect_error();
}
$result= mysqli_query($connect, "SELECT * FROM employees");
?>
<br>
<table width="500", cellpadding=5 callspacing=5 border=1>
<tr>
<th>ID</th>
<th>Name</th>
<th>Last Name</th>
<th>Department</th>
<th>Email</th>
</tr>
<?php while($rows = mysqli_fetch_array($result)): ?>
<tr>
<td><?php echo $rows['id']; ?></td>
<td><?php echo $rows['first_name']; ?></td>
<td><?php echo $rows['last_name']; ?></td>
<td><?php echo $rows['department']; ?></td>
<td><?php echo $rows['email']; ?></td>
</tr>
<?php endwhile; ?>
</table>
You're missing PHP in several places:
<?php
$connect = mysqli_connect('localhost', 'root', '11111', 'company');
if(mysqli_connect_errno($connect)){
echo 'Failed to connecto to database'.mysqli_connect_error();}
$result= mysqli_query($connect, "SELECT * FROM employees");
?>
<table width="500", cellpadding=5 callspacing=5 border=1>
<tr>
<th>ID</th>
<th>Name</th>
<th>Last Name</th>
<th>Department</th>
<th>Email</th>
</tr>
<?php while($rows = mysqli_fetch_array($result)): ?>
<tr>
<td><?php echo $rows['id']; ?></td>
<td><?php echo $rows['first_name']; ?></td>
<td><?php echo $rows['last_name']; ?></td>
<td><?php echo $rows['department']; ?></td>
<td><?php echo $rows['email']; ?></td>
</tr>
<?php endwhile; ?>
</table>
I used to have the same issue. At first I thought mysqli_fetch_array() couldn't work inside tag. But now it finally did. Anyways, after checking your codes have you tried removing the : in <?php while($rows = mysqli_fetch_array($result)): ?>
Because as far as I know you don't need a ; or a : if you're calling a function inside while-loop or any loop function.
Try this:
while($row=mysqli_fetch_assoc($result))