For loop doesn't regen random string, stays the same - php

Question

So I m trying to get a random string generator to work with a for loop. I have gotten it to loop the number of times it should but it refuses to generate a new string per loop. Can someone look at my code and show me where i went wrong? Also there is no way of using unqid so do not mention it please.
if($_SERVER['REQUEST_METHOD'] == "POST")
{
$key = $_POST['keysd'];
if(isset($key) && is_string($key))
{
switch($key)
{
case "ksc";
$algor = "78.0000.".rnumstr(7);
break;
case "kpl";
$algor = "76.0000.".rnumstr(7);
break;
case "kfi";
$algor = "D01EB0A01472".rnumstr(1).strtoupper(ralphstr(3));
break;
}
$sum = $_POST['sum'];
$alg = $algor;
if(isset($sum))
{
for ($i = 0; $i < $sum; $i++)
{
echo $alg.'<br/>';
}
}
}
}

Answer 1

If you want to generate new $alg per loop's iteration, you must call your switch's code every iteration. Refactor your code:
function getRandomValue($key)
{
switch($key)
{
case "ksc":
return "78.0000.".rnumstr(7);
case "kpl":
return "76.0000.".rnumstr(7);
case "kfi":
return "D01EB0A01472".rnumstr(1).strtoupper(ralphstr(3));
}
}
if($_SERVER['REQUEST_METHOD'] == "POST")
{
$key = $_POST['keysd'];
if(isset($key) && is_string($key))
{
$sum = $_POST['sum'];
if(isset($sum))
{
for ($i = 0; $i < $sum; $i++)
{
$alg = getRandomValue($key);
echo $alg.'<br/>';
}
}
}
}