Hi I am new to mongodb..
My problem is to append array in mongodb data
My array
{
"_id" : ObjectId("5864f61111115810fc011111"),
"estimate" : {
"estimate_id" : 1122332,
"source_data" : {
"1" : {
"test":"test"
}
}
},
"updated_at" : ISODate("1970-01-15T10:47:01.399Z"),
"created_at" : ISODate("1970-01-15T10:41:56.623Z")
}
I want to add array in source_data like bellow
{
"_id" : ObjectId("5864f61111115810fc011111"),
"estimate" : {
"estimate_id" : 1122332,
"source_data" : {
"1" : {
"name":"nikhil"
},
"2" : {
"name":"nikhil"
}
}
},
"updated_at" : ISODate("1970-01-15T10:47:01.399Z"),
"created_at" : ISODate("1970-01-15T10:41:56.623Z")
}
I have tried below code but not working
$data = array("2"=>array("name":"nikhil"));
$sourcing = Sourcing::find('5864f61111115810fc011111');//return mongo data
$sourcing->put('estimate.source_data.2',$data );
To append one or more values to an array, the following which uses the push() method should work for you:
$data = array('name' => 'nikhil');
Sourcing::find('5864f61111115810fc011111')->push('estimate.source_data', $data);
Related
I am using new mongodb driver for PHP and using query want to display all relevant documents. But instead it returns only one document or boolean(false) as value.
I want all the mongo documents to be returned which satisfies the condition. Tried using limit parameter option too but to no avail.
Below is my code :
<?php
ini_set("display_errors",1);
ini_set('error_reporting', E_ALL);
//$filter = [ 'job_id' => [ '$gte' => 1 ], ];
//$options = [ 'maxScan' => 400 ];
$mongo = new MongoDB\Driver\Manager("mongodb://localhost:27017");
$query = new MongoDB\Driver\Query([]);
$rows = $mongo->executeQuery('sag.jobs', $query, $readPreference); // $mongo contains the connection object to MongoDB
//var_dump($rows);
$abc=current($rows->toArray());
var_dump($rows);
//print_r($abc);
var_dump($abc);
?>
Used both with option and filters parameter and as a empty parameter :
Mongo table content:
> { "_id" : ObjectId("596608c7f4bb66cead9762d6"), "job_id" : 1 } { "_id"
> : ObjectId("596608caf4bb66cead9762d7"), "job_id" : 2 } { "_id" :
> ObjectId("596608cef4bb66cead9762d8"), "job_id" : 3 } { "_id" :
> ObjectId("596608d0f4bb66cead9762d9"), "job_id" : 4 } { "_id" :
> ObjectId("596608d2f4bb66cead9762da"), "job_id" : 5 }
and this is the only output I am getting :
object(stdClass)#6 (2) {
["_id"]=>
object(MongoDB\BSON\ObjectID)#5 (1) {
["oid"]=>
string(24) "596608c7f4bb66cead9762d6"
}
["job_id"]=>
float(1)
}
The following lines of code should give you the results as an array:
$client = new MongoDB\Client('mongodb://localhost:27017');
$arr = $client->sag->jobs->find($filter)->toArray();
For more information on the MongoDB\Collection::find method, see here. For more information on the MongoDB\Drive\Cursor object it returns, see here.
I have a document like this:
{
"_id" : ObjectId("5629aded0760cd72078b4567"),
"name" : "Name",
"url" : "URL.com",
"updated_at" : ISODate("2015-10-23T03:47:57.050Z"),
"created_at" : ISODate("2015-10-23T03:47:57.050Z")
}
And a function like this:
public function getByName($name) {
$findQuery = array("name" => $name);
$team = Team::find($findQuery);
print_r($team);
exit;
return "Here";
}
The problem is when I find by name field I alway get the empty array return. But when I try with $findQuery = array("_id" => "5629aded0760cd72078b4567"); it's work fine.
I don't know what did I do wrong here?
I am attempting to update multiple array elements using a PHP version of the query described in how to update sequence number in mongodb safely
Which describes the query:
db.so.update(
{ _id: new ObjectId("4f55e7ba362e2f2a734c92f8")},
{ $set : { 'subs.1.order' : 3, 'subs.2.order' : 2 } }
);
I'm building a query to add an 'order' field to my document
{
"_id": {
"$oid": "5209acfd0de2316335000001"
},
"bookListId": "116ad5af-7cc6-4652-9bb3-aea852e584e8",
"favoriteBook": [
{
"title": "One Favorite Book",
},
{
"title": "Another Favorite Book",
},
{
"title": "A Third Favorite Book",
}
]
}
..and am doing it in PHP with
$criteria = array('bookListId' => $bookListId);
$favoriteBookOrder = array();
for($i=0;$i<sizeof($order);$i++) {
$key = 'favoriteBook.'.($i+1).'.order';
$val = $order[$i];
$favoriteBookOrder[] = array($key=>intval($val));
}
$setFavoriteBookOrder = array('$set' => $favoriteBookOrder);
$collection->update($criteria, $setFavoriteBookOrder);
but this doesn't produce any result because the query doesn't have the correct organization of arrays..
error_log(json_encode($setupdated));
outputs
{"$set":[{"favoriteBook.1.order":2},{"favoriteBook.2.order":1},{"favoriteBook.3.order":3}]}
which if you notice has too many quotes, brackets around the entire array, and curly braces around each item. I believe this is what is causing the error:
"Invalid modifier specified: $set"
What is the correct syntax for building the array in PHP? Thanks!
EDIT
this is the fix
$favoriteBookOrder[] = array($key=>intval($val));
should be
$favoriteBookOrder[$key] = intval($val);
also i removed the +1 from $i because Mongo indexes are 0 based
correct query now
{"$set":{"favoriteBook.0.order":1,"favoriteBook.1.order":2,"favoriteBook.2.order":3}}
To make you query work right you have to change one line:
$favoriteBookOrder[] = array($key=>intval($val));
to
$favoriteBookOrder[$key] = intval($val);
But I think you wont be happy with result, because it will something like this:
"favoriteBook" : {
"0" : { "order" : NumberLong(123) },
"1" : { "order" : NumberLong(321) },
"2" : { "order" : NumberLong(456) }
}
I suggest you rewrite code in this way:
for($i=0;$i<sizeof($order);$i++)
$favoriteBookOrder[$i]['order'] = $order[$i];
$setupdated = array('$set' => ['favoriteBookOrder' => $favoriteBookOrder]);
and you'll get:
"favoriteBookOrder" : [
{ "order" : NumberLong(123) },
{ "order" : NumberLong(321) },
{ "order" : NumberLong(456) }
]
P.S. you can play with $pushAll modificator instead of $set, it could be more suitable for you.
I have a mongodb collection of following format :
{
"_id" : ObjectId("5141916511e5b498fd2031c4"),
"itemid" : 1,
"recommendations" : [
{
"itemid" : 216,
"rating" : 0.875297364790784
},
{
"itemid" : 246,
"rating" : 0.8793363655122852
}
]
}
{
"_id" : ObjectId("5141916511e5b498fd2031c5"),
"itemid" : 2,
"recommendations" : [
{
"itemid" : 60,
"rating" : 0.9405825249353504
},
{
"itemid" : 76,
"rating" : 0.8822827294664317
}
]
}
I want to retrieve recommendations for a given itemid and then iterate over it to print all the recommended itemids and ratings.I am using php for this.
When I try to iterate over returned cursor,it throws "Fatal error: Call to a member function hasNext() on a non-object" error.
It seems the resultset returned by query is not of type cursor.
Below is the code I am using :
<?php
$mongodb = new Mongo("10.128.170.49:27017");
$database = $mongodb->ProductData;
$collection = $database->Recommendation1;
$cursor1 = $collection->findOne(array("itemid" => 1),array('recommendations'));
var_dump($cursor1);
echo "<hr/><p>iterating over a cursor</p>";
while ($cursor1->hasNext()): $document = $cursor1->getNext();
$itemid= $document['itemid'];
$probable_rating= $document['rating'];
echo ($itemid)."<br/>";
echo ($probable_rating)."<br/>";
echo "<hr/>";
endwhile;
?>
Please help me resolve this issue.
You have to change findOne() to find()
findOne() returns the first found result
find() returns a cursor
I'm trying to combine multiple JSON objects into a single one in PHP. I'm iterating through the JSON objets, decoding them, parsing out the parts I want to keep, and storing them in a property in my php class.
Supposing my json objects look like the following format:
{
"lists" : {
"list" : [
{
"termA" : 2 ,
"termB" : "FOO"
}
]
}
}
I want to eventually combine everything into a JSON object like so.
{
"lists" : {
"list" : [
{
"termA" : 2 ,
"termB" : "FOO"
},
{
"termA" : 2 ,
"termB" : "FOO"
}
]
} ,
"lists" : {
"list" : [
{
"termA" : 4 ,
"termB" : "BAR"
},
{
"termA" : 4 ,
"termB" : "BAR"
}
]
}
}
I'm trying to store Arrays in a property within my class in a function that gets called iteratrivley:
private function parseData($json){
$decodeData = json_decode($json);
$list = $decodeData->lists;
$this->output .= $list
}
However I get the following error during the "$this->output .= $list" line.
Object of class stdClass could not be converted to string
Right now $this->output has no initial value. What might be the best way to store the "list" arrays temporarily, and then reformat them after going through all of the json objects?
Thanks.
You were close:
private function parseData($json){
$decodeData = json_decode($json);
$list = $decodeData['lists'];
$this->output .= $list
}
{
"lists" : {
...
} ,
"lists" : {
...
}
}
That's not valid/meaningful JSON. You have a hash with the same key (lists) in it twice. How would you address that?