I'm looking for a posibility to set minutes to "00" instead of "60". I have following code:
$minute = date('i');
$minutesround = round($minute / 10) * 10;
$hour = date('H');
$minutesround = str_pad($minutesround, 2, 0, STR_PAD_LEFT);
$time = $hour . $minutesround;
echo $time;
My problem: If it is eg. 4:56pm the output should like this: 1700
but in my case, I get this 1660
Someone has an idea, how to realize this?
Thank you!
This works well:
$myRoundedTime = round(time()/600) * 600; // round time to nearest 6th of an hour
$time = date('Hi', $myRoundedTime);
echo $time;
A working example: http://sandbox.onlinephpfunctions.com/code/b2b595683d9adf8e5273cbdef775bf69b6c036d4
A simple if statement should do the trick
$hour = date('H');
if($minutesround == 60) {
$minutesround = 0;
$hour++;
if($hour == 24) $hour = '00';
}
Related
i have two different break time
default break time
extra break time
here i want to sum of two times and display 12 hrs format
EX :
$default_time = "00:30";
$extra_time = "00:25";
my expected output : 00:55
but now display 01:00
this is my code
$default_time = $work_data->break_time;
$break_time = $work_data->extra_time;
$total_break = strtotime($default_time)+strtotime($break_time);
echo date("h:i",strtotime($total_break));
Here is the function you can calculate total time by passing the arguments to functions.
$hours, $min are supposed variable which is zero
$default_time = "00:30";
$break_time = "00:25";
function calculate_total_time() {
$i = 0;
foreach(func_get_args() as $time) {
sscanf($time, '%d:%d', $hour, $min);
$i += $hour * 60 + $min;
}
if( $h = floor($i / 60) ) {
$i %= 60;
}
return sprintf('%02d:%02d', $h, $i);
}
// use example
echo calculate_total_time($default_time, $break_time); # 00:55
There is one function call to strtotime function too much.
You should leave out the strtotime() call in the last line, as $total_break already is a UNIX timestamp:
$total_break = strtotime($default_time)+strtotime($break_time);
echo date("h:i",$total_break);
The problem is that you're trying to add too specific timestamps, but what you're trying to achieve is adding two durations. So you need to convert those timestamps into durations. For that you need a base, which in your case is 00:00.
$base = strtotime("00:00");
$default_time = $work_data->break_time;
$default_timestamp = strtotime($default_time);
$default_duration = $default_timestamp - $base; // Duration in seconds
$break_time = $work_data->extra_time;
$break_timestamp = strtotime($break_time);
$break_duration = $break_timestamp - $base; // Duration in seconds
$total_break = $default_duration + $break_duration; // 55 min in seconds
// If you want to calculate the timestamp 00:55, just add the base back to it
echo date("H:i", $base + $total_break);
Consider using standard DateTime and DateInterval classes. All you will need is to convert your second variable value to interval_spec format (see http://php.net/manual/en/dateinterval.construct.php for details):
$defaultTime = "00:30";
$breakTime = "PT00H25M"; // Or just 'PT25M'
$totalBreak = (new DateTime($defaultTime))->add($breakTime);
echo $totalBreak->format('H:i');
You could try the following code fragment:
$time1 = explode(":", $default_time);
$time2 = explode(":", $break_time);
$fulltime = ($time1[0] + $time2[0]) * 60 + $time1[1] + $time2[1];
echo (int)($fulltime / 60) . ":" . ($fulltime % 60);
<?php
$time = "00:30";
$time2 = "00:25";
$secs = strtotime($time2)-strtotime("00:00:00");
$result = date("H:i:s",strtotime($time)+$secs);
print_r($result);
?>
Use below code you will definitely get your answers.
$default_time = "00:30:00";
$extra_time = "00:25:00";
$secs = strtotime($extra_time)-strtotime("00:00:00");
$result = date("H:i:s A",strtotime($default_time)+$secs);
echo $result;die;
You can modify above code as per your need.
You could try the following:
$default_time = $work_data->break_time;
$date_start = new DateTime($default_time);
$break_time = $work_data->extra_time;
$interval = new DateInterval("PT" . str_replace(":", "H", $break_time) . "M");
$date_end = $date_start->add($interval);
echo $date_end->format("H:i");
Note that this doesn't account for times which span a 24 hour period
My problem is this: My game day is supposed to be 1/6 of a real world day. A game day has 12 game hours. Thus one game hour is 20 minutes real time. Or that's what it's supposed to be. However, when I've observed the time, instead of an hour being 20 minutes, it's in fact 30 minutes. I can't figure out what's causing this. What's wrong with my function?
public function getGameTime() {
$t = time();
$d = $t/60/60/6 - 68646;//the number taken off makes the current time day 200 instead of a really big number
$fraction = $d - floor($d);
if ($fraction<(1/12)) $hour = 0;
else if ($fraction<(1/12)*2) $hour = 1;
else if ($fraction<(1/12)*3) $hour = 2;
else if ($fraction<(1/12)*4) $hour = 3;
else if ($fraction<(1/12)*5) $hour = 4;
else if ($fraction<(1/12)*6) $hour = 5;
else if ($fraction<(1/12)*7) $hour = 6;
else if ($fraction<(1/12)*8) $hour = 7;
else if ($fraction<(1/12)*9) $hour = 8;
else if ($fraction<(1/12)*10) $hour = 9;
else if ($fraction<(1/12)*11) $hour = 10;
else $hour = 11;
for ($minute = 59; $minute>=0; $minute--) {
if ((($hour*60+$minute)/720)<$fraction) {
$min = $minute;
break;
}
}
return array(
"day" => floor($d),
"hour" => $hour,
"minute" => $min
);
}
So yes, if I want 6 four hour periods in a day I need to divide by 4. Dividing by 6 gives me four 6-hour periods instead. Because the divisor is the number of real life hours in a game day, not the number of game days in 24 hours. Problem solved.
I wish to multiply 2 variables so that one of them is in the hour format (hh:mm),
How can I do so? The answer I am getting is 0:
<?php
$num = 5;
$timeUnit = "00:01";
$waitingTime = $num * $timeUnit;
echo $waitingTime;
I need to get 00:05 (5 min) in the output, but I am getting 0.
Hope this will help you
$num=100;
$timeUnit="00:02";
$timeUnit;
$time=explode(":",$timeUnit);
$waitingTime=$num*$time[1];
$minute = sprintf("%02d", ($waitingTime%60));
$hour = sprintf("%02d", ($waitingTime/60));
$current_time = floor($hour).':'.($minute);
echo $current_time;
$num=20;
$timeUnit="00:03";
$time=explode(":",$timeUnit);
$waitingTime=$num*$time[1];
$sec=$time[0]+$waitingTime%60;
$hour=floor($waitingTime/60);
$timeUnit1="".$hour.":".$sec."";
$current=strtotime($timeUnit1); //seconds of current time
echo date("H:i",$current);
You can do like this
I ended up converting the time into seconds, did the multiply and converted it to "time format" again:
$num=200;
$timeUnit="00:01:00";
$time=explode(":",$timeUnit);
$sec=$time[1]*60;
$sec=$sec*$num;
$diff = $sec;
$format = sprintf('%02d:%02d:%02d', ($diff / 3600), ($diff / 60 % 60), $diff % 60);
echo $format;
Thanks for your help
You can't compute string and digits this way.
All you would have to do would be to create a function/method that would implement the behavior you want and use it
i have lets say a $value = 5; and the valnue means 5 minutes, and i have a file saved on the server and getting modified a lot called check.txt i want a code to do a calculation of if timenow - timemodification of file <= 0 in H:i:s from the main $value of 5 minutes then continue, else echo please wait minutes left from the time now - filetimemodification of the main value of 5 minutes = $timeleft in m:s format.
i'm testing on the current code but i keep getting a value of -1376352747
my code which is know is bad :) is
$filename = 'check.txt';
$time = date("H:i:s");
$time = str_replace("00", "24", $time);
$filemodtime = filemtime($filename);
$timeleft = $time - $filemodtime;
$h = explode(':', $time);
$h = $h[0];
$h = str_replace("00", "24", $h);
$m = explode(':', $time);
$m = $m[1];
$s = explode(':', $time);
$s = $s[2];
$hms = ("$h:$m:$s");
if (count($filemodtime - $time) <= 0) {
echo "you can continue";
}
else {
echo " please wait $timeleft";
}
thanks in advance
The filemtime() function returns a UNIX-timestamp in seconds, and the time() function returns the current time as a UNIX-timestamp. So by using that difference, you get the file's age in seconds.
$age = time() - filemtime($filename);
// if older then 5 minutes (5 * 60 secounds)
if($age > $value*60)
{
// good
}
else
{
$time_left = $value * 60 - $age;
$time_left_secounds = $time_left % 60;
$time_left_minutes = ($time_left - $time_left_secounds) / 60;
$formated_time_left = sprintf("%02d:%02d", $time_left_minutes, $time_left_secounds);
echo "Please wait {$formated_time_left}";
}
I would recommend to work with time() rather than date().
that way, you can substract the file time from the current time() function, and see if it is bigger than 5 minutes * 60 seconds.
Good luck!
I want to add up time in php but after hours of google'ing and trying out im still unable to find a solution.
my values are:
$newTotal = '00:45:00';
$oldTotal = '00:16:00';
I want to add those two up which make 01:01:00.
Can you give me an example i'm getting really desperate! :p
thanks in advance,
Use strtotime() to turn them into Unix timestamps, then add them as integers:
$newTotal = '00:45:00';
$oldTotal = '00:16:00';
$total = strtotime($newTotal) + strtotime($oldTotal);
To format it as hh:mm:ss again, use date():
echo date('H:i:s', $total);
This gives:
01:01:00
If these values always look like that, you could break them down with a substr()
$hours1 = substr($newTotal, 0, 2);
etc. And then simply add up the seconds, do a divide and mod and bubble up to the hours, and voila!
$secondstotal = $seconds1+$seconds2;
$restseconds = $secondstotal % 60;
$minutesfromseconds = floor($restseconds / 60);
$minutestotal = $minutes1+$minutes2+$minutesfromseconds;
etc.
keep a start date for minimum error.
<?php
$origin = '00:00:00';
$newTotal = '00:45:00';
$oldTotal = '00:16:00';
$added = strtotime($newTotal) + (strtotime($oldTotal) - strtotime($origin));
echo date('H:i:s', $added );
output :
01:01:00
Note, if your time is more than 23:59:59 after adding, you will get wrong result.
Another solution without time function:
function sumtotal($a,$b) {
$i = explode(':',$a);
$j = explode(':',$b); // 0hh:1mm:2ss
$k = array(0,0,0,0); // 0days:1hours:2minutes:3seconds
$k[3] = $i[2]+$j[2];
$k[2] = (int)($k[3]/60)+$i[1]+$j[1];
$k[1] = (int)($k[2]/60)+$i[0]+$j[0];
$k[0] = (int)($k[1]/24);
$k[3] %= 60;
$k[2] %= 60;
$k[1] %= 24;
if ($k[3]<10) $k[3] = '0'.$k[3];
if ($k[2]<10) $k[2] = '0'.$k[2];
if ($k[1]<10) $k[1] = '0'.$k[1];
return $k[0].' days : '.$k[1].' hours : '.$k[2].' minutes : '.$k[3].' seconds';
}
$newTotal = '01:45:21';
$oldTotal = '03:16:56';
echo sumtotal($newTotal,$oldTotal); // result: 0 days : 05 hours : 02 minutes : 17 seconds