Reuse PDO result set multiple times [duplicate] - php

Question

This question already has answers here:
Resetting array pointer in PDO results
(7 answers)
Closed 3 years ago.
I am trying to create a select box that will display several times on the page, where the options are populated by my SQL query. I am able to get this to display once but when I try to create a second, identical select box, there are no options in the dropdown box. Here is what I have working:
<?php include_once "app/init.php";
$dataQuery = $db->prepare("
SELECT column FROM dataType");
$dataQuery->execute([]);
$dataTypes = $dataQuery->rowCount() ? $dataQuery : [];
?>
<div>
<select>
<?php foreach($dataTypes as $dataType): ?>
<option>
<?php echo $dataType['dataType']; ?>
</option>
<?php endforeach; ?>
</select>
</div>
But when I try to add a second select box, it it blank. I am creating a table that will have this select box on every row for the user to select a data type so I need to recreate this dynamically several times. I am new to php, so what is the best way to go about this?
My init.php to show using PDO:
<?php session_start();
$_SESSION['user']=1;
$db = new PDO ('mysql:dbname=myDB;host=localhost', 'root', 'root');
if(!isset($_SESSION['user'])) {
die('You are not signed in');
};

Answer 1

You can only loop through the PDO statement once, so you should put the result in a temporary array.
Instead of:
$dataTypes = $dataQuery->rowCount() ? $dataQuery : [];
Do
$dataTypes = $dataQuery->fetchAll(\PDO::FETCH_ASSOC);