I am trying to connect to and select data from an PostgreSQL server. I am able to connect to the server but my select query appears to be running an error. Any suggestions?
<?php
$conn = "host=#### port=5432 dbname=consolidated user=#### password=####";
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
$dbconn = pg_connect($conn);
$result = pg_query($dbconn, "SELECT id FROM retailer_retailer;");
if (!$result) {
echo "An error occurred.\n";
exit;
}
while ($row = pg_fetch_row($result)) {
echo "ID: $row[0]";
echo "<br />\n";
}
?>
you miss the schema name right here, I assume you have table in public schema and your query should like-
$result = pg_query($dbconn, "SELECT id FROM public.retailer_retailer;");
If you have another schema then you can replace public with other schema name
Related
I'm new to PHP and MySQL. While learning, I got this error that says my database is unkown.
I have already made this database.
and I have already made the table 'todos'
Here is my PHP
<?php
require 'functions.php';
$conn = new mysqli('localhost','root','', 'mytodo');
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$statement = $conn->prepare('select * from todos');
$statement->execute();
var_dump($statement->fetchAll());
require 'index.view.php';
the PHP file is named 'Index.test.php'
but when I try to access localhost/Index.test.php on my browser
it returns this
Could you tell me why I am getting the error? Appreciate the help!
try to use this select:
<?php
require 'functions.php';
$conn = new mysqli('localhost','root','', 'mytodo');
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//select query
$sql = "SELECT * FROM todos";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_array($result)) {
echo $row['your column name'];
}
//free result set
mysqli_free_result($result);
} else {
echo "no records found";
}
}
else {
echo "error: could not connect" . mysqli_error($conn);
}
require 'index.view.php';
?>
I'm trying to show all tables within a given MySQL database with php.
I'm very new to all this though and can't find a solution for it. Keeps giving an error 'no found file or directory'.
Anyone who can point out my mistakes here please?
Much appreciated!
<?php include "../inc/dbinfo.inc"; ?>
<html>
<body>
<h2>LIST TABLES FROM DATABASE</h2>
<?php
// Create connection
$conn = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
// Check connection
if ($conn->connect_error) {
die("Connection with the database failed: </br>" . $conn->connect_error);
}
echo "Connection established with the database! </br>";
// SQL to show tables
$sql = "SHOW TABLES FROM paperlessdb";
$result = mysql_query($sql);
if (!$result) {
echo "Database error, could not list tables.\n</br>";
echo 'MySQL error: ' . mysql_error();
exit;
}
while ($row = mysql_fetch_row($result)) {
echo "- {$row[0]}\n </br>";
}
mysql_free_result($result);
?>
First make up your mind, either use mysqli procedural or object orientated. Not a combination of both because its confusing. To avoid that all together use pdo instead.
Now properly connect to the database, you can select the database when connecting to it automatically:
const DB_DATABASE = 'paperlessdb';
$conn = new mysqli(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_DATABASE);
// Check connection
if ($conn->connect_error) {
die("Connection with the database failed: </br>" . $conn->connect_error);
}
if($result = $conn->query('SHOW TABLES')){
while($row = $conn->fetch_array($result)){
$tables[] = $row[0];
}
}
print_r($tables);
Use below query,
$sql = "SELECT table_name
FROM information_schema.tables
WHERE table_schema = 'paperlessdb'";
We are fetching the data from information_schema db which stores the meta data about our database.
You are using mysqli to connect to the database but use the depreciated mysql to query the database.
$conn = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
$result = mysql_query($sql);
while ($row = mysql_fetch_row($result)){}
mysql_free_result($result);
You should use mysqli_query() and mysqli_fetch_array() instead.
It'a a bit more complex but mysql is decrecated and remove as PHP 7 so no choice to jump ahead. Check out PDO ass well. I personally go for mysqli but most say pdo is more intuitive.
It should look more something like:
$result = mysqli_query($conn,$sql);
if(!$result){
die('MySQL error: ' . mysqli_error($conn));
}
while ($row = mysqli_fetch_row($result)) {
echo "- {$row[0]}\n </br>";
}
I am having trouble with an SQL query that I have inserted into a piece of PHP code to retrieve some data. The query itself works perfectly within SQL. I am using the following PHP script.
I have the following objectives:
Connect to the existing database. This part works well.
Get data from the column 'Brand' of the table 'Transport' in $sql. This part is not working at this stage. echo ($sql) returns SELECT Brand FROM Transport WHERE Type = 'car'
Could you please let me know if you see the solution to this issue and if the remaining part of the code is correct. This is my f_sqlConnect()
function f_sqlConnect() {
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!link) {
die('Could not connect: '.mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!$db_selected) {
die('Can not use'.DB_NAME.
': '.mysql_error());
}
}
/*This function cleans up the array to protect against injection attacks */
function f_clean($array) {
return array_map('mysql_real_escape_string', $array);
}
<?php
// Create connection
$link = f_sqlConnect();
// Getting data from the column Brand of the table Transport
$sql = "SELECT Brand FROM Transport WHERE Type = 'car'";
$result = $link->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Brand: " . $row["Brand"]. "<br>";
}
} else {
echo "0 results";
}
$link->close();
?>
Here is the code, without seeing your f_sqlConnect(); mothod. This method should return connection string for DB in your case. But you can use following code this must work.
<?php
$servername = "Your_db_host";
$username = "your_db_username";
$password = "your_db_password";
$dbname = "your_DB_name";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT Brand FROM Transport WHERE Type = 'car'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Brand: " . $row["Brand"];
}
} else {
echo "0 results";
}
$conn->close();
?>
NOTE: Object oriented way of mysqli, You can use procedural way too to connect and get data.
Mysqli query not updating table with custid
// Create connection
$db = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$db) {
die("Connection failed: " . mysqli_connect_error());
}
//$query = "Select expiry from AcctSession where id ='$id' ";
echo $custid.$id; //works fine here
$query = "update sessions SET custid = '$custid' where id = '$id' ";
if (mysqli_query($db, $query)) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . mysqli_error($db);
}
I've tried echoing $query
Query works fine on command line but it doesn't write any result when firing from php script(Plus, no error msg as well)
i am new to PHP, and i am attempting to create a simple connection from html to mySQL using php. I met with some problems when running my codes.
this is my code:
<?php
$servername = "localhost";
$username = "root";
$password = "password";
$dbname = "database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT username FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<br> id: ". $row["userid"]. ;
}
} else {
echo "0 results";
}
$conn->close();
?>
after running on a browser, this is displayed:
connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT username FROM users"; $result = $conn->query($sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { echo "
id: ". $row["userid"]. ; } } else { echo "0 results"; } $conn->close(); ?>
Do you have mysql running on your localhost machine? You must verify that it is working first before you can connect via php. Also, make sure you have TCP/IP sockets open in mysql and to make sure it isn't just listening via unix sockets.
echo "<br> id: ". $row["userid"]. ;
this is a syntax error, no need to end it with a full stop.also the correct syntax to connect to sql server is
mysqli_connect("localhost","my_user","my_password","my_db") or die("");
Debug the code before posting it here.
maybe try testing it with a try catch statement. Its what I've done. this way you can display your error messages a little more nicely. As for the cause, PressingOnAlways is probably right
If you are using wampserver or any other server you need to put your php files into c:\wamp\www folder and run them in browser by typing localhost/nameofyourfile.php (change c:\wapm\www for your server installation path or type)
you have the syntax error in blow line
echo "<br> id: ". $row["userid"]. ;
. (dot) should not be there.
second you fetch usernamestrong text by following query
$sql = "SELECT username FROM users";
but you try to get userid
echo "<br> id: ". $row["userid"]. ;
try below code.
<?php
$servername = "localhost";
$username = "root";
$password = "password";
$dbname = "databasename";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT usersname FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<br> id: ". $row["usersname"] ;
}
} else {
echo "0 results";
}
$conn->close();
?>