Simple Search Engine Only Works With One SQL Row - php

Question

I'm making a rather simple search engine with PHP and I've ran into a problem... The engine will only work for one SQL row. In the table the PHP is connected to, there are two rows. One named "The Painful Truth" and the other "Darkness Rising". If you type "darkness" or "rising" into the search bar it will come back with "Darkness Rising" as expected. However, if you input "the", "painful", or "truth" into the bar it will come back with zero results.(P.S. "The Painful Truth" is the first entry in the table) I attempted to debug it by listing out the song names in the table, the search, and the array after exploding the song names. They all line up like they should work, but alas, they don't.
The code below takes the input and removes characters and spaces
$lower = strtolower($_POST["text"]);
$characterRemover = preg_replace('/[^ \w]+/', '', $lower);
$search = str_replace(' ' , '' , $characterRemover);
echo "<strong>". $search . "</strong><br>";
The code below takes data from the database, explodes the string and tries to find a match.
while($row = $result->fetch_assoc()) {
$Slower = strtolower($row["song_name"]);
echo "Song Name: " . $Slower . "<br>";
$song_name = explode(" " , $Slower);
// list array
$arrlength = count($song_name);
for($x = 0; $x < $arrlength; $x++) {
echo $song_name[$x];
echo "<br>";
}
if (in_array($search, $song_name) !== false) {
$song_result = $row["song_name"];
} else {
$song_result = "0 results buddy";
}
}
here's how it looks when I search for "the":

Answer 1

What's happening here is that the loop is running for every single row and the variable $song_result is being overwritten. Try to use a flag $found to get the song.
$found = false;
while(!$found && ($row = $result->fetch_assoc())) {
$Slower = strtolower($row["song_name"]);
echo "Song Name: " . $Slower . "<br>";
$song_name = explode(" " , $Slower);
// list array
$arrlength = count($song_name);
for($x = 0; $x < $arrlength; $x++) {
echo $song_name[$x];
echo "<br>";
}
if (in_array($search, $song_name) !== false) {
$song_result = $row["song_name"];
$found = true;
} else {
$song_result = "0 results buddy";
}
}
If you want to capture every song, then use an array or concatenate a string:
$songs = [];
while($row = $result->fetch_assoc()) {
$Slower = strtolower($row["song_name"]);
echo "Song Name: " . $Slower . "<br>";
$song_name = explode(" " , $Slower);
// list array
$arrlength = count($song_name);
for($x = 0; $x < $arrlength; $x++) {
echo $song_name[$x];
echo "<br>";
}
if (in_array($search, $song_name) !== false) {
$songs[] = $row["song_name"];
}
}
if (count($songs)) {
$song_result = implode('<br>', $songs);
} else {
$song_result = "0 results buddy";
}
Note: You should follow JimL's suggestion and request the info filtering the DB query via the WHERE clause. And then just show the result of the query. ;)

Answer 2

<?php
//Kindly make sure you have create a connection and select a db. this is a sample code to search from mysql db using data supplied
$msg=$_POST['search'];
if(isset($msg)){
$search=explode(' ',$msg);
$len=count($search);
$query="select * from news where ";
for($m=0;$m<$len;$m++){
$query.=" post like '%{$search[$m]}%' || ";
}
$query.=" post like '%{$msg}%' order by upload_date desc";
if($get=mysqli_query($connect,$query)){
$contentSearch=array();
$i=0;
while($row=mysqli_fetch_assoc($get)){
contentSearch[$i]=$row;
$i++;
}
echo"List of Search Items<br>";
print_r($contentSearch);
}
}