PHP - have a script call itself again to avoid timeout - php

I have a database with records to process. Number of records will vary. Too many records will cause my script to timeout but 15 records is a good safe number.
If my pseudo code is
//script begin
$sql = "SELECT id FROM table WHERE status = 0 LIMIT 0, 15";
runquery($sql);
foreach($rows as $row) {
//do things then run this sql:
$sql = "UPDATE table SET status = 1 WHERE id = {$theCurrentId};";
}
, can I achieve something like this at the end of the script:
$sql = "SELECT id FROM table WHERE status = 0";
runquery($sql);
if (rowcount() > 0) {
???? - something to call this script again as a new script
}
i.e. can I run this short script again if needed without it being counted in the timeout?

Related

Delete row after x minutes in mysqli database and php

I am creating a website in php. I have a database called database1 I have the tables cooldown and my_table The cooldown table contains the columns time(type Timestamp default value CURRENT_TIMESTAMP) and ip(type int(30) default value none). At the end of my code I have mysqli_query($conn, "DELETE FROM cooldown WHERE time < NOW() - INTERVAL 5 MINUTE"); which should delete the row after 5 minutes, but it doesn't delete the row. Could this be because the user gets redirected so the php script stops working? Or do I miss something else?
Code:
//Test if it is a shared client
if (!empty($_SERVER['HTTP_CLIENT_IP'])){
$ip=$_SERVER['HTTP_CLIENT_IP'];
//Is it a proxy address
}elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){
$ip=$_SERVER['HTTP_X_FORWARDED_FOR'];
}else{
$ip=$_SERVER['REMOTE_ADDR'];
}
//The value of $ip at this point would look something like: "192.0.34.166"
$ip = ip2long($ip);
//The $ip would now look something like: 1073732954
$query = mysqli_query($conn, "SELECT ip FROM cooldown WHERE ip = '$ip'");
$row = mysqli_fetch_array($query);
if ($row) {
//What page shall the bans be sent to?
header("Location: http://imnothere.epizy.com/cooldown.html"); //cooldownpage
exit();
} else {
$sql1= "SELECT links FROM my_table WHERE Type = 'spotify' ORDER BY RAND() LIMIT 1";
$result1 = $conn->query($sql1); //this actually runs the query on the DB, and comes back with a $result object
if($result1 === false) {
echo $conn->error();
}
$redirect = $result1->fetch_assoc()['links']; //this gets one row from the $result object, and then the 'links' column from that row.
header("Location: " . $redirect);
$sql = "INSERT INTO cooldown(ip, time) VALUES('$ip', NOW())";
$result = $conn->query($sql); //this actually runs the query on the DB, and comes back with a $result object
if($result === false) {
}
mysqli_query($conn, "DELETE FROM cooldown WHERE time < NOW() - INTERVAL 5 MINUTE");
}
Your SQL query won't delete the rows after 5 minutes, it will delete everything that is 5 minutes or older at the time of the request.
You're probably best moving that line of code to a separate file that is run by cron or setup an event in your db to do it say every minute or so.
U can with Cron job , supervisor or schedule time
Your SQL query almost as it
DELETE FROM cooldown WHERE time < NOW() - INTERVAL 5 MINUTE
If you want every five minutes, use either
*/5 * * * * fooo

How to run query until one record is found?

This is what i am trying right now but no luck
$bid = $next - 2;//This subtracts 2 from the number, this number is also auto generated
$preid = $bid;
$query = "SELECT * FROM images where imageid = '$preid'";
$sql = mysqli_query($conn,$query) or die(mysqli_error($conn));
while(mysqli_num_rows($sql) !=0) {
$select_query = "SELECT * FROM images where imageid = '$preid'";
$sql = mysqli_query($conn,$select_query) or die(mysqli_error($conn));
--$preid;
}
whats suppose to happen is that if a record does not exist it subtracts 1 from preid and runs the query again with the new preid and keeps happening until a record it found but cant figure out how to do it.
I am assuming that you are constantly checking database for new values. However, on a large scale application thi is an highly inefficient way to constantly ping the database.
You have made a variable $preid but you are not using it anywhere.
This is how i would do it if i were to go according to your way
$bid = $next - 2;//This subtracts 2 from the number, this number is also auto generated
$preid = $bid;
$query = "SELECT * FROM images where imageid = '$preid'";
$sql = mysqli_query($conn,$query) or die(mysqli_error($conn));
while(mysqli_num_rows($sql) !=0 || !$preid) { //notice here i added the condition for preid.
$select_query = "SELECT * FROM images where imageid = '$preid'";
$sql = mysqli_query($conn,$select_query) or die(mysqli_error($conn));
--$preid;
}
now what happens is that the loop will run as long as either of the two condition stays true ie either a row is returned from the database or it will keep searching until preid is not 0.
If you want to test for an empty set, your while should run while mysqli_num_rows == 0
while(mysqli_num_rows($sql) == 0) {
$select_query = "SELECT * FROM images where imageid = '$preid'";
$sql = mysqli_query($conn,$select_query) or die(mysqli_error($conn));
$preid--;
}
As #DarkBee has mentionend in his comment, this code is highly vulnerable for an infinite loop which will take down your script, as soon as there are no entries for anything.

MySQL Database Randomly Stops Taking in Data?

I'm working on a nice little application. I'm making a Tick counter, to count how many times the program runs. However, randomly it stops entering data at like 1355... I have to get it to keep running until it hits 5000. But sometimes it goes over to like 5002... Lost on that one too... I would prefer the loop to run forever until it's terminated. If anyone can help me on that you get a bit cookie. In conclusion, my main problem is putting data in the database continuously, with out random stops.
while($run && $dataA['StateOfBot'] == 1){
if($dataA['Tick'] >= 5000){
mysql_query("UPDATE state SET StateOfBot = 0 WHERE ID = 1;");
}
$dataA['Tick'] = $dataA['Tick'] + 1;
mysql_query("UPDATE state SET Tick = '".$dataA['Tick']."' WHERE ID = 1;");
$data = mysql_query("SELECT * FROM state");
$dataA = mysql_fetch_array($data);
}
I think your code is quite buggy
while($run && $dataA['StateOfBot'] == 1){
if($dataA['Tick'] >= 5000){
mysql_query("UPDATE state SET StateOfBot = 0 WHERE ID = 1;");
break; //get out of the loop
}
$dataA['Tick'] = $dataA['Tick'] + 1;
mysql_query("UPDATE state SET Tick = '".$dataA['Tick']."' WHERE ID = 1;");
$data = mysql_query("SELECT onefield_only FROM state");
$dataA = mysql_fetch_array($data);
}
I tried to fix it a little. You need a break statement to get out of the loop.

Prevent two calls to the same script from selecting the same mysql row

The below script is called every 5 seconds. The issue is that if the server is responding slow, one entry in "blog" can get selected twice in a row because the server hasn't had time to set "done" to "1" yet. Is there an industry standard (or whatever you call it) way to prevent this from happening?
$result = mysql_query("SELECT * FROM blogs WHERE done=0 LIMIT 1");
$rows = mysql_num_rows($result); //If there are no entries in with done set to 0, that means we've done them all; reset all entries to 0.
if($rows == 0)
{
mysql_query("UPDATE blogs SET done=0 WHERE done=1");
}
else
{
while($row = mysql_fetch_array($result))
{
mysql_query("UPDATE blogs SET done=1 WHERE id=$row[id]");
// Do stuff
}
}
I think I could change it to
while($row = mysql_fetch_array($result))
{
if($row['done'] == 1){ die; }
mysql_query("UPDATE blogs SET done=1 WHERE id=$row[id]");
//Do stuff
}
But will that really fix the problem? I would imagine there would be a better way that really prevents it from happening without a shadow of a doubt.
I think the best way to prevent selecting the same row is using SELECT GET_LOCK("lock_name"); and SELECT RELEASE_LOCK("lock_name");. When you get a lock from mysql server, other processing trying to get a lock will wait for the lock to be released. Below is a sample implementation:
<?php
function getLock($lockName, $dbc) {
$query = "SELECT GET_LOCK('".$lockName."', 0)";
$result = mysql_query($query, $dbc);
$lockResult = mysql_fetch_row($result);
$lockResult = $lockResult[0];
return $lockResult == 1 ? true : false;
}
function releaseLock($lockName, $dbc) {
$query = "SELECT RELEASE_LOCK('".$lockName."')";
$result = mysql_query($query, $dbc);
}
// CONNECT TO DATABASE
$dbc = mysql_connect('localhost', 'root', '');
mysql_select_db('test', $dbc);
$loopQueue = true;
$rowsProcessed = 0;
// MAIN QUEUE LOOP
while ($loopQueue) {
// TRY UNTIL GETTING A LOCK
$queueLockName = 'queue_lock_1';
while (getLock($queueLockName, $dbc) === true) {
// WE GOT THE LOCK, GET A QUEUE ROW WITH PENDING STATUS
$query = 'SELECT * FROM test WHERE status = 0 ORDER BY ID ASC LIMIT 1';
$result = mysql_query($query, $dbc);
if (mysql_num_rows($result) < 1) {
// SINCE WE DON"T HAVE ANY QUEUE ROWS, RELEASE THE LOCK
releaseLock($queueLockName, $dbc);
// WE DONT NEED TO LOOP THE MAIN QUEUE ANYMORE SINCE WE DONT HAVE ANY QUEUE ROWS PENDING
$loopQueue = false;
// BREAK THIS LOOP
break;
}
// WE GOT THE QUEUE ROW, CONVERT IT TO ARRAY
$queueRowArray = mysql_fetch_assoc($result);
// UPDATE QUEUE ROW STATUS TO SENDING
$query = 'UPDATE test SET status = 1 WHERE id = '.$queueRowArray['id'];
mysql_query($query);
// RELEASE THE LOCK SO OTHER JOBS CAN GET QUEUE ROWS
releaseLock($queueLockName, $dbc);
// DO STUFF ...
// UPDATE QUEUE ROW STATUS TO PROCESSED
$query = 'UPDATE test SET status = 2 WHERE id = '.$queueRowArray['id'];
mysql_query($query);
$rowsProcessed++;
}
}
echo "\n\n".'process finished ('.$rowsProcessed.')'."\n\n";
I would have given a go to transactions. Here is an example in another StackOverflow question
Just a question: What happens if the server is even slower? For instance, the select statament takes so long (e.g. 5 seconds) that once it finishes (returning 0 rows), the new select is executed (returning 1 or more rows)
MySQL documentation
$result = mysql_query("SELECT * FROM blogs WHERE done=0 LIMIT 1");
$rows = mysql_num_rows($result); //If there are no entries in with done set to 0, that means we've done them all; reset all entries to 0.
if($rows == 0)
{
mysql_query("UPDATE blogs SET done=0 WHERE done=1");
}
else
{
while($row = mysql_fetch_array($result))
{
mysql_query("UPDATE blogs SET done=1 WHERE id=$row[id] AND done=0");
if(mysql_affected_rows() != 1)
die();
// Do stuff
}
}

Php/MySQL help - random daily pick?

I'm trying to get a pick from my DB that would last for a day (daily pick). I use the following code:
$query = 'SELECT * FROM table ORDER BY rand() LIMIT 1
But as you can see it only gives me a random pick from the table, and every time I refresh the page it gets me a new random pick. How can I make the pick to last for a whole day?
Thanks in advance <3
I'm trying this:
$query = "SELECT * FROM table ORDER BY rand(" . date("Ymd") . ") LIMIT 1";
But I get the following error: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource. This is the part that gets broken:
$results = mysql_query($query);
while($line = mysql_fetch_assoc($results))
So... it should look like this, right? (I mean, choosing the daily random pick?)
$dailyPick = 'SELECT * FROM table ORDER BY rand() LIMIT 1';
$cacheKey = 'dailyPick'. date('dmY');
if($cache->has($cacheKey)) {
$dailyPick = $cache->get($cacheKey);
} else {
// hit database
$dailyPick = $cache->save($cacheKey);
}
I'm trying this now:
$dailyPick = 'SELECT * FROM table ORDER BY rand() LIMIT 1';
$cacheKey = 'dailyPick'. date('dmY');
if($cache->has($cacheKey)) {
$dailyPick = $cache->get($cacheKey);
} else {
// hit database
$dailyPick = $cache->save($cacheKey);
}
However, it gets me a mistake that I'm using the 'has' function on a non-object.
If you set the SEED for the rand to an integer value that changes daily, that would solve your problem
$query = "SELECT * FROM table ORDER BY rand(" . date("Ymd") . ") LIMIT 1";
Would do the trick.
A sane means of doing this would be to automatically generate the pick of the day content via a cron job that was setup to run once a day.
As such, the cron job would execute the SQL you provided and store the appropriate content in a flat file/database table, etc. (or perhaps even just store the choosen id in another table for future lookup purposes).
You can try something like this:
$total = 'SELECT COUNT(*) FROM table;';
$query = 'SELECT * FROM table ORDER BY id ASC LIMIT 1 OFFSET ' . (date('Ymd') % $total) . ';';
I think you'll need to update the random picked record with "today" field = 1..
Something like this:
// ------------
// Run this 3 commands once a day
// Reset all records
mysql_query("UPDATE `table` SET `today` = 0");
// Pick one
$sql = mysql_query("SELECT `id` FROM `table` ORDER BY RAND() LIMIT 1");
$id = mysql_result($sql, 0, 'id');
// Update the record
mysql_query("UPDATE `table` SET `today` = 1 WHERE `id` = {$id}");
// ------------
// Now you can find again your "random found record":
$query = mysql_query("SELECT * FROM `table` WHERE `today` = 1");

Categories