We have the table structure like
Fieldid userid data
41 2 1
12 2 0
41 3 1
12 3 1
We want the user which have (data=1 and filedid = 41) and (data = 0 and filedid=12)
We tried the query
select userid from table
where (data=1 and filedid = 41)
AND (data = 0 and filedid=12)
but it returns empty results.
Can anyone help how we will get the record using MySQL?
You can use grouping with a conditional aggregate in the HAVING clause:
SELECT userid
FROM mytable
GROUP BY userid
HAVING COUNT(CASE WHEN data = 1 AND FieldId = 1 THEN 1 END) >= 1 AND
COUNT(CASE WHEN data = 0 AND FieldId = 12 THEN 1 END) >= 1
you need to use union all like:
select * from table1 where Fieldid = 41 and data = 1 union all
select * from table1 where Fieldid = 12 and data = 0
attached image shows the output
Similar to #Giorgos, with multicolumn compare for conciseness:
select userid
from t
group by userid
having sum((data,fieldId) = (1, 41)) > 0
and sum((data,fieldId) = (0, 12)) > 0
When searching for results with one or another set of data you have to use OR keyword, not AND.
SELECT userid FROM table
WHERE (data = 1 AND filedid = 41)
OR (data = 0 AND filedid = 12)
Related
I want to retrieve columns name from table whose value is 1
My query is give below...
mysqli_query($conn,"SELECT * FROM `tbl_therapist_schedule` WHERE `schedule_date`='30.11.2017'");
My table structure is give below...
slot1 slot2 slot3
1 1 0
2 1 1
1 1 2
3 1 0
my result...
slot1 slot2 slot3
I have the serious feeling that your data is not normalized. Instead of having separate columns for each slot, I would store all this data in a single column with metadata to relate each slot's state.
That being said, one way to get the output you want would be to aggregate over each slot column and check for the presence/absence of at least one 1 value. I then use GROUP_CONCAT to generate a CSV list of matching slots.
SELECT GROUP_CONCAT(slots)
FROM
(
SELECT
CASE WHEN SUM(CASE WHEN slot1 = 1 THEN 1 ELSE 0 END) > 0
THEN 'slot1' END AS slots
FROM tbl_therapist_schedule
WHERE schedule_date = '30.11.2017'
UNION ALL
SELECT
CASE WHEN SUM(CASE WHEN slot2 = 1 THEN 1 ELSE 0 END) > 0
THEN 'slot2' END
FROM tbl_therapist_schedule
WHERE schedule_date = '30.11.2017'
UNION ALL
SELECT
CASE WHEN SUM(CASE WHEN slot3 = 1 THEN 1 ELSE 0 END) > 0
THEN 'slot3' END
FROM tbl_therapist_schedule
WHERE schedule_date = '30.11.2017'
) t;
Demo
I have N Rows with same SlNo but different RowNo as shown below
for eg:
SlNo RowNo Status
1 1 Opened
1 2 Closed
1 3 Opened
1 4 Closed
1 5 Opened
If all the Status Column Rows are Closed , I want to return 1.
else o.
Thanks in advance.
You can do it following:
SELECT STATUS FROM `table_1` where SLNO = 1 group by status
If you get only one record with value "Closed" then execute the next query
UPDATE `table_2` SET Ref_Status = 'Closed' WHERE SLNO = 1;
Update my_table set Status='Closed' where SlNo = 1
Find the count of all rows and check it with the count of Closed values.
Query
select t.`SlNo`,
case when t.`RowNo_Count` = t.`closed_count` then 1 else 0 end as `new_col`
from(
select `SlNo`,
count(`RowNo`) as `RowNo_Count`,
sum(case `Status` when 'Closed' then 1 else 0 end) as `closed_count`
from `your_table_name`
group by `SlNo`
)t;
I got 4 fields
page_id
page_category_id
page_sequence
page_path
For example
record 1
page_id = 1
page_category_id = 22
page_sequence = 1
page_path = "1.jpg"
record 2
page_id = 1
page_category_id = 22
page_sequence = 2
page_path = "2.jpg"
record 3
page_id = 1
page_category_id = 23
page_sequence = 1
page_path = "23_1.jpg"
record 4
page_id = 1
page_category_id = 23
page_sequence = 2
page_path = "23_1.jpg"
record 5
page_id = 1
page_category_id = 23
page_sequence = 3
page_path = "23_1.jpg"
.. and more records
I want to do a draw statement that
$sql_select = "select page_category_id from my_table where max(page_sequence) < 3";
it will show all the page_category_id who max(page_sequence) is less than 3.
but I can't do it with max(page_sequence) as the where condition
How can I get it working.. Thanks!
SQL is such fun, since you can almost always solve things in several completely different ways. Here's a NOT EXISTS alternative:
select distinct page_category_id
from tablename t1
where not exists (select 1 from tablename t2
where t2.page_category_id = t1.page_category_id
and t2.page_sequence >= 3)
Return a page_category_id if there are no row with same page_category_id that has a page_sequence >= 3.
select page_category_id from my_table
GROUP BY page_category_id
HAVING max(page_sequence) < 2
I have table for student attendance like below:
id | Present | date
1 | 1
1 | 0
1 | 1
1 | 1
1 | 0
Now I want to get the total days he is present via single query. Is it possible?
Below is the way I used to get the student present/absent count:
select count(*) from table where present =1
select count(*) from table where present =0
But I think can I get both from one query instead of two.
select sum(present = 1) as present1,
sum(present = 0) as present0
from table
You can use the following query:
select (select count(*) from table where present=1) as "present"
, (select count(*) from table where present=0) as "absent";
Try this its working fine :
SELECT SUM( present =1 ) AS present, SUM( present =0 ) AS absent
FROM details
WHERE id =1
Screenshot :
Try this :
For all student with group by
select id,present,absent from
(
select id,sum(case when present = 1 then 1 else 0 end) as present,
sum(case when present = 0 then 1 else 0 end) as absent
from table_name
group by id
) as absen
if you want to show only one student, just add where clause in the end like this :
select id,present,absent from
(
select id,sum(case when present = 1 then 1 else 0 end) as present,
sum(case when present = 0 then 1 else 0 end) as absent
from table_name
group by id
) as absen
where id = '1'
Hope this help you..
I have a table and would like to calculate values. My table:
Table votes
vote type
1 1
-1 1
1 0
-1 0
1 0
-1 1
1 0
Vote: -1 - Down; +1 - Up;
I would like to get something like this:
Count votes up type 1: 1
Count votes down type 1: 2
Votes up type 0: 3
Votes down type 0: 1
Sum votes type 1: 1+(-1)+(-1) = -1
Sum votes type 0: 1+(-1)+1+1 = 2
Is it possible to get results from mysql using single query?
Thanks!
I guess your problem is how to distinct up and down votes here.
You want to group by type (which sounds like a vote/poll ID) and then just pick up and down votes. It can be done using CASE or IF in combination with COUNT or SUM.
COUNT does not count NULL values so I suggest to wrap two COUNTs in IFs.
SELECT
type,
COUNT(IF(vote = -1, TRUE, NULL)) AS down,
COUNT(IF(vote = 1, TRUE, NULL)) AS up
FROM votes
GROUP BY type
SQL Fiddle: http://sqlfiddle.com/#!2/36008/1/0
you can write
select count(*) from table where type = 1 and vote = -1
select count(*) from table where type = 1 and vote = 1
the above will give you the result count which you want .
This will work
select sum(vote),type from table group by type;