I have an array containing some words and I want to remove the words that contain either a . (fullstop) or ; (semicolon) or some other symbols. I have read the solution on [ Remove item from array if item value contains searched string character ] but this doesn't seem to answer my problem.
What can I add to this code to remove also the words containing the other symbols other than semicolon?
function myFilter($string) {
return strpos($string, ';') === false;
}
$newArray = array_filter($array, 'myFilter');
Thanks
Use preg_match function:
function myFilter($string) {
return !preg_match("/[,.]/", $string);
}
[,.] - character class which can be extended with any other symbols
// $array is your initial array
$newArray = array();
foreach ($array as $item){
if ((strpos($item, ';') > 0)||(strpos($item, '.') > 0))
continue;
$newArray[] = $item;
}
// Words with ; or . should be filtered out in newArray
print_r($newArray);
Related
I have this value:
$numbers= "|800027|800036|800079|800097|800134|800215|800317|800341|800389"
And I want to remove the values below 800130 including the starting "|". I guess it is possible, but I can not find any examples anywhere. If anyone can point me to the right direction I would be thankful.
You could split the input string on pipe, then remove all array elements which, when cast to numbers, are less than 800130. Then, recombine to a pipe delimited string.
$input= "|800027|800036|800079|800097|800134|800215|800317|800341|800389";
$input = ltrim($input, '|');
$numbers = explode("|", $input);
$array = [];
foreach ($numbers as $number) {
if ($number >= 800130) array_push($array, $number);
}
$output = implode("|", $array);
echo "|" . $output;
This prints:
|800134|800215|800317|800341|800389
This should work as well:
$numbers= "|800027|800036|800079|800097|800134|800215|800317|800341|800389";
function my_filter($value) {
return ($value >= "800130");
}
$x = explode("|", $numbers); // Convert to array
$y = array_filter($x, "my_filter"); // Filter out elements
$z = implode("|", $y); // Convert to string again
echo $z;
Note that it's not necessary to have different variables (x,y,z). It's just there to make it a little bit easier to follow the code :)
PHP has a built in function preg_replace_callback which takes a regular expression - in your case \|(\d+) - and applies a callback function to the matched values. Which means you can do this with a simple comparison of each matched value...
$numbers= "|800027|800036|800079|800097|800134|800215|800317|800341|800389";
echo preg_replace_callback("/\|(\d+)/", function($match){
return $match[1] < 800130 ? "" : $match[0];
}, $numbers);
Use explode and implode functions and delete the values that are less than 80031:
$numbers= "|800027|800036|800079|800097|800134|800215|800317|800341|800389";
$values = explode("|", $numbers);
for ($i=1;$i<sizeof($values);$i++) {
if (intval($values[$i])<800130) {
unset($values[$i]);
}
}
// Notice I didn't start the $i index from 0 in the for loop above because the string is starting with "|", the first index value for explode is ""
// If you will not do this, you will get "|" in the end in the resulting string, instead of start.
$result = implode("|", $values);
echo $result;
It will print:
|800134|800215|800317|800341|800389
You can split them with a regex and then filter the array.
$numbers= "|800027|800036|800079|800097|800134|800215|800317|800341|800389";
$below = '|'.join('|', array_filter(preg_split('/\|/', $numbers, -1, PREG_SPLIT_NO_EMPTY), fn($n) => $n < 800130));
|800027|800036|800079|800097
I need replace ',' characters with regex in php, but only in odd positions
I have:
{"phone","11975365654","name","John Doe","cpf","42076792864"}
I want replace ',' to ':', but only the odd:
{"phone":"11975365654","name":"John Doe","cpf":"42076792864"}
I'm trying this regex:
preg_replace('/,/', ':', $data)
But it get all quotes and no only the odd.
Can you help me?
Make it simple:
preg_replace('/(("[a-z]+"),(".+?"))+/', '$2:$3', $a)
Rather than regex, this just converts the list to an array (using str_getcsv() to cope with the quotes). Then loops every other item in the list, using that item as the key and the next item as the value. This can then be json_encoded() to give the result...
$data = str_getcsv(trim($input, "{}"));
$output = [];
for ( $i=0, $k=count($data); $i < $k; $i+=2) {
$output[$data[$i]] = $data[$i+1];
}
echo json_encode($output);
It is not ideal to use regex for this task. Having said that, if you know that your input can be matched by a simple regex, this should do it :
$str = '{"phone","11975365654","name","John Doe","cpf","42076792864"}';
$result = preg_replace('/,(.*?(?:,|[^,]*$))/ms', ':\\1', $str);
This lenient to some extra characters but it will fail if any string contains commas
Example
Here's an example of using standard PHP functions:
$input = '{"phone","11975365654","name","John Doe","cpf","42076792864"}';
$dataIn = str_getcsv(trim($input, '{}'));
$keys = array_filter($dataIn, function ($key) { return !($key & 1); }, ARRAY_FILTER_USE_KEY);
$values = array_filter($dataIn, function ($key) { return $key & 1; }, ARRAY_FILTER_USE_KEY);
$DataOut = array_combine($keys, $values);
$output = json_encode($DataOut);
echo $output;
This code is a lot longer than using a regex, but it is probably easier to read and maintain in the long run. It can cope with commas in the values.
Another option could be using array_splice and loop while there are still elements in the array:
$str = '{"phone","11975365654","name","John Doe","cpf","42076792864"}';
$data = str_getcsv(trim($str, '{}'));
$result = array();
while(count($data)) {
list($k, $v) = array_splice($data, 0, 2);
$result[$k] = $v;
}
echo json_encode($result);
Output
{"phone":"11975365654","name":"John Doe","cpf":"42076792864"}
I have an array like this,
$array = array(
1,2,3,'4>12','13.1','13.2','14>30'
);
I want to find any value with an ">" and replace it with a range().
The result I want is,
array(
1,2,3,4,5,6,7,8,9,10,11,12, '13.1', '13.2', 14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30
);
My understanding:
if any element of $array has '>' in it,
$separate = explode(">", $that_element);
$range_array = range($separate[0], $separate[1]); //makes an array of 4 to 12.
Now somehow replace '4>12' of with $range_array and get a result like above example.
May be I can find which element has '>' in it using foreach() and rebuild $array again using array_push() and multi level foreach. Looking for a more elegant solution.
You can even do it in a one-liner like this:
$array = array(1,2,3,'4>12','13.1','13.2','14>30');
print_r(array_reduce(
$array,
function($a,$c){return array_merge($a,#range(...array_slice(explode(">","$c>$c"),0,2)));},
[]
));
I avoid any if clause by using range() on the array_slice() array I get from exploding "$c>$c" (this will always at least give me a two-element array).
You can find a little demo here: https://rextester.com/DXPTD44420
Edit:
OK, if the array can also contain non-numeric values the strategy needs to be modified: Now I will check for the existence of the separator sign > and will then either merge some cells created by a range() call or simply put the non-numeric element into an array and merge that with the original array:
$array = array(1,2,3,'4>12','13.1','64+2','14>30');
print_r(array_reduce(
$array,
function($a,$c){return array_merge($a,strpos($c,'>')>0?range(...explode(">",$c)):[$c]);},
[]
));
See the updated demo here: https://rextester.com/BWBYF59990
It's easy to create an empty array and fill it while loop a source
$array = array(
1,2,3,'4>12','13.1','13.2','14>30'
);
$res = [];
foreach($array as $x) {
$separate = explode(">", $x);
if(count($separate) !== 2) {
// No char '<' in the string or more than 1
$res[] = $x;
}
else {
$res = array_merge($res, range($separate[0], $separate[1]));
}
}
print_r($res);
range function will help you with this:
$array = array(
1,2,3,'4>12','13.1','13.2','14>30'
);
$newArray = [];
foreach ($array as $item) {
if (strpos($item, '>') !== false) {
$newArray = array_merge($newArray, range(...explode('>', $item)));
} else {
$newArray[] = $item;
}
}
print_r($newArray);
Newbie here. I'm trying to make it so if $value doesn't contain two dashes then it is unset from the array. I figured out how to remove items from the array containing only ONE dash, but it needs to contain TWO. Thanks!
Removes items from an array containing only one dash:
foreach ($addkeys as $key=>&$value) {
if (strpos($value, '-') === false) {
unset($addkeys[$key]);
}
}
I also tried $value, '--' and '-''-' without success.
You need to use preg_match_all(). Here is how it would look in your code. The function returns the count of items found:
<?php
$string = "/\-/";
foreach ($addkeys as $key => &$value) {
if (preg_match_all($string, $value, &$matches)) {
if (count($matches[0]) > 1)
// greater than one.
}
}
?>
So what I need is to compare a string to an array (string as a haystack and array as a needle) and get the elements from the string that repeat within the array. For this purpose I've taken a sample function for using an array as a needle in the substr_count function.
$animals = array('cat','dog','bird');
$toString = implode(' ', $animals);
$data = array('a');
function substr_count_array($haystack, $needle){
$initial = 0;
foreach ($needle as $substring) {
$initial += substr_count($haystack, $substring);
}
return $initial;
}
echo substr_count_array($toString, $data);
The problem is that if I search for a character such as 'a', it gets through the check and validates as a legit value because 'a' is contained within the first element. So the above outputs 1. I figured this was due to the foreach() but how do I bypass that? I want to search for a whole string match, not partial.
You can break up the $haystack into individual words, then do an in_array() check over it to make sure the word exists in that array as a whole word before doing your substr_count():
$animals = array('cat','dog','bird', 'cat', 'dog', 'bird', 'bird', 'hello');
$toString = implode(' ', $animals);
$data = array('cat');
function substr_count_array($haystack, $needle){
$initial = 0;
$bits_of_haystack = explode(' ', $haystack);
foreach ($needle as $substring) {
if(!in_array($substring, $bits_of_haystack))
continue; // skip this needle if it doesn't exist as a whole word
$initial += substr_count($haystack, $substring);
}
return $initial;
}
echo substr_count_array($toString, $data);
Here, cat is 2, dog is 2, bird is 3, hello is 1 and lion is 0.
Edit: here's another alternative using array_keys() with the search parameter set to the $needle:
function substr_count_array($haystack, $needle){
$bits_of_haystack = explode(' ', $haystack);
return count(array_keys($bits_of_haystack, $needle[0]));
}
Of course, this approach requires a string as the needle. I'm not 100% sure why you need to use an array as the needle, but perhaps you could do a loop outside the function and call it for each needle if you need to - just another option anyway!
Just throwing my solution in the ring here; the basic idea, as outlined by scrowler as well, is to break up the search subject into separate words so that you can compare whole words.
function substr_count_array($haystack, $needle)
{
$substrings = explode(' ', $haystack);
return array_reduce($substrings, function($total, $current) use ($needle) {
return $total + count(array_keys($needle, $current, true));
}, 0);
}
The array_reduce() step is basically this:
$total = 0;
foreach ($substrings as $substring) {
$total = $total + count(array_keys($needle, $substring, true));
}
return $total;
The array_keys() expression returns the keys of $needle for which the value equals $substring. The size of that array is the number of occurrences.