yii2 Gridview does not show column with joined attributes - php

Question

I have a model Certificates which has a foreign key application_id of another model called Application. So each certificate belongs to the single application.
Now there is a situation where I would like to show all the certificates of the existing user. The user id exist inside the application model like user_id.
This is the query
SELECT * FROM `certificates`
inner join applications b ON
application_id = b.id where b.user_id = 7
Now based on the records coming from the above query I would like to show some columns of the certificates and some from the applications using grid view. But for some reasons, if records are more than one then I don't get any column data from the application.
<?php Pjax::begin(); ?> <?= GridView::widget([
'dataProvider' => $dataProvider,
// 'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'application_id',
'verified_application_file_path',
'certificate_name',
'application.name',
'application.user_id',
[
'attribute' => 'creation_date',
'format' => ['date', 'php:d/m/Y']
],
[
'attribute' => 'expiry_date',
'format' => ['date', 'php:d/m/Y']
],
],
]); ?>
<?php Pjax::end(); ?></div>
The above grid shows name and user id if a single record get return otherwise it shows "Not set". I Am not sure why 'application.name' and 'application.user_id'are not working when more than one records receive.
Here is my query using yii2
/**
* Creates data provider instance with search query applied
*
* #param array $params
*
* #return ActiveDataProvider
*/
public function search_vendor_certificates($user_id)
{
$query = ApplicationCertificates::find()->joinWith('application b',true , 'INNER JOIN')->where(["b.user_id"=>$user_id]);
// add conditions that should always apply here
$dataProvider = new \yii\data\ActiveDataProvider([
'query' => $query,
]);
return $dataProvider; }
I will appreciate if someone would tell me what is the mistake I am doing in displaying the proper attributes of the application model.

Answer 1

First of all (don't use this, i'll show u an logical mistake):
->joinWith('application b',true , 'INNER JOIN')
U set alias for application b, and then in GridView use application. Anyway, it's still bad if u rename it to b in GridView.
Based on this answer:
Model TableTwo:
public function getTableOneRecord()
{
return $this->hasOne(TableOne::className(), ['id' => 't1_id']);
}
public function getTableThreeRecord()
{
return $this->hasOne(TableThree::className(), ['id' => 't3_id']);
}
public function getTableFourRecord()
{
return $this->hasOne(TableFour::className(), ['id' => 't4_id'])
->via('tableThreeRecord');
}
And the view file:
echo GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'id',
't1_id',
'tableOneRecord.id',
't3_id',
'tableThreeRecord.id',
'tableThreeRecord.t4_id',
'tableFourRecord.id',
],
]);
In easiest way to say, your relation from search won't work in GridView, you have to define relations in Model and then use thems ;)
See the code on GitHub