Searching in array return wrong result - php

Question

I have received array like this
Array
(
[hash] => 9761d3233f9cb256c0992be
[total] => 2736712601
[received] => 2017-01-13T21:43:32.047Z
[income] => Array
(
[0] => Array
(
[value] => 647262
[addresses] => Array
(
[0] => Address_1
)
)
[1] => Array
(
[value] => 17200000
[addresses] => Array
(
[0] => Address_2
)
)
[2] => Array
(
[value] => 3729034
[addresses] => Array
(
[0] => Address_3
)
)
[3] => Array
(
[value] => 2414997500
[addresses] => Array
(
[0] => Address_4
)
)
[4] => Array
(
[value] => 10856454
[addresses] => Array
(
[0] => Address_5
)
)
)
)
So in my database I store the hash (9761d3233f9cb256c0992be). The I hash and the address. Then based on them I match the correct array from [income]. When I found correct address in income I take the [value] and showing it on the page. Here is how I've made it
$url=get_curl_content("https://example.com/".$order->hash);
$totala =json_decode($url,true);
....
$match = true;
foreach ($totala['income'] as $data) {
if ($data['addresses'] == $order->address) {
$match = $data;
break;
}
}
$price = $data['value'];
The problem is that I'm expecting Address_2 because in database i have saved Address_2 I've got Address_3 instead.
When I var_dump($data['addresses']) i got Address_3. What can be the problem?

Answer 1

Try like this. It will search and match in array using in_array function
$match = true;
foreach ($totala['income'] as $data) {
if (in_array($order->address, $data['addresses'])) {
$match = $data;
break;
}
}
$price = $match['value'];