I'm making a customer database application for a dancing school.
I need to display an overview of all customers that are participating in the same dancing level. But I want the overview order by couples not by the customer ID.
For this I'm joining three tables (look at the query below)
Each customer has a unique ID in the tabel CRM_CONTACTS and also has in it's row a reference to his or her partner (PARTNER_ID).
Table CRM_CONTACTS
ID CONTACTS_LNAME
1 VON KLOMPENBURG
2 Mc Donalds
3 MC Adams
4 Mr X
Then I have CRM_PRODUCTS
ID PRODUCTS_NAME
1 Beginners
2 intermediate
3 advanced
Then the table in which I assign a product/level to a contact and also indicate his/her partner
ID CONTACTS_ID PRODUCTS_ID PARTNER_ID
1 1 1 4
2 2 1 3
3 3 1 2
4 4 1 1
Now I would like to receive a list order by couple based on the parter_id
So for the beginners level I would get a list like this
1 VON KLOMPENBURG
2 Mr X
3 Mc Donalds
4 Mc Adams
Here's my select statement
$result = mysqli_query($coni,"SELECT CRM_PRODUCTS_PURCHASE.ID, CONTACTS_ID,
CRM_PRODUCTS.PRODUCTS_NAME,
CRM_PRODUCTS.PRODUCTS_PRICE,CRM_PRODUCTS_PURCHASE.PARTNER_ID,
CRM_PRODUCTS_PURCHASE.PARTNER_NAME,
PRODUCTS_PURCHASE_REMARKS,PRODUCTS_PURCHASE_DISCOUNT,
PRODUCTS_PURCHASE_PAIDBYBANK,PRODUCTS_PURCHASE_PAIDBYCASH,
CRM_CONTACTS.CONTACTS_LNAME, CRM_CONTACTS.CONTACTS_FNAME
FROM CRM_PRODUCTS_PURCHASE
LEFT JOIN CRM_CONTACTS ON CRM_PRODUCTS_PURCHASE.CONTACTS_ID = CRM_CONTACTS.ID
LEFT JOIN CRM_PRODUCTS ON CRM_PRODUCTS_PURCHASE.PRODUCTS_ID = CRM_PRODUCTS.ID
WHERE CRM_PRODUCTS_PURCHASE.PRODUCTS_ID = '". $PRODUCTS_ID . "'");
You can do something like this:
$result = mysqli_query($coni,"SELECT CRM_PRODUCTS_PURCHASE.ID, CONTACTS_ID,
CRM_PRODUCTS.PRODUCTS_NAME,
CRM_PRODUCTS.PRODUCTS_PRICE,CRM_PRODUCTS_PURCHASE.PARTNER_ID,
CRM_PRODUCTS_PURCHASE.PARTNER_NAME,
PRODUCTS_PURCHASE_REMARKS,PRODUCTS_PURCHASE_DISCOUNT,
PRODUCTS_PURCHASE_PAIDBYBANK,PRODUCTS_PURCHASE_PAIDBYCASH,
CRM_CONTACTS.CONTACTS_LNAME, CRM_CONTACTS.CONTACTS_FNAME
FROM CRM_PRODUCTS_PURCHASE
LEFT JOIN CRM_CONTACTS ON CRM_PRODUCTS_PURCHASE.CONTACTS_ID = CRM_CONTACTS.ID
LEFT JOIN CRM_PRODUCTS ON CRM_PRODUCTS_PURCHASE.PRODUCTS_ID = CRM_PRODUCTS.ID
WHERE CRM_PRODUCTS_PURCHASE.PRODUCTS_ID = '". $PRODUCTS_ID . "'
ORDER BY IF (ID < PARTNER_ID, ID, PARTNER_ID)");
And your customers will be ordered in couples.
Related
This is what I want:
Users will send one or two values in my website and I will store them in two variables $genres1 and $genres2.
Like: If user sends, Action, then my code will show all movies with Action genres. If user sends Action+Crime, then my table will fetch all movies with Action+Crime.
Got it?
My current table structure is one to many relationship, like this
tmdb_id movie_title
-----------------------------
1 Iron man
2 Logan
3 Batman
4 The hangover
tmdb_id genres
-----------------------------
1 Action
1 Crime
2 Drama
2 Action
3 Crime
3 Action
4 Comedy
4 Drama
But the problem here is, I can't achieve what I explained above with this.
2nd option: I make a single table like this:
movie_tile genres1 genres2 genres3 genres4
----------------------------------------------------
Logan Action Crime Drama Null
Iron man Action Crime Null Null
And I can do what, I want with this single line:
SELECT * FROM movies WHERE (genres1='$genres1' or genres2='$genres1' orgenres1='$genres3' or genres3='$genres1')
Any other option?
use a table width genres
and use an other table connecting the movie to any genre
-----
movieid title
-----
1 Logan
2 Smurf
-----
-----
genreid genre
-----
1 animated
2 blue people
-----
-----
movieid genreid
-----
1 1
2 1
2 2
-----
that way you won't be limited to 4 genres per movie
now I read your question better.
That's what you do, but you put left out the genre-table.
The 2nd option is bad, as you limit yourself to only 4 categories
Is this connected to PHP? I think is easiest to solve this further by a join query, sorted by movie and a loop in PHP
you want all movies where (by user request) the genres are both Crime And Action?
SELECT mg.movieid, count(1), m.title
FROM movies_genres mg
JOIN movies m ON m.movieid mg.movieid
WHERE mg.genreid = 1 OR mg.genreid =3
group by mg.movieid, m.title
HAVING COUNT(1) = 2
edit: see other genres as well
SELECT movies.movieid,movies.title, genres.genre
FROM movies
JOIN movie_genre mg ON mg.movieid = movies.movieid
JOIN genres on genres.genreid = mg.genreid
WHERE movie.movieid IN (
SELECT mg.movieid
FROM movies_genres mg
WHERE mg.genreid = 1 OR mg.genreid =3
GROUP BY mg.movieid
HAVING COUNT(1) = 2
)
forgot to mention: count = 2, means you gave 2 genreid's to find. This could also be 1, 3 or 25
select distinct a.tmdb_id, a.movie_tittle
from movie_tittle a inner join genre_tittle b
on a.tmdb_id = b.tmdb_id
where b.genres in ('Action', 'Crime')
Based on your comment, try this :
SELECT
a.tmdb_id, a.movie_tittle
FROM
movie_tittle a inner join genre_tittle b
ON
a.tmdb_id = b.tmdb_id
WHERE
b.genres in ('Action', 'Crime')
GROUP BY
a.tmdb_id, a.movie_tittle
HAVING
count(a.tmdb_id) = 2
tmdb_id and genres in table genre_tittle should not duplicated. Make it as primary key.
But the problem here is, I can't achieve what I explained above with [the first two tables]
Yes, you can. Assuming the two tables are called movies and movie_genres, you can select the movies which have both tags using:
SELECT movie_title FROM movies
JOIN movie_genres genre1 USING (tmdb_id)
JOIN movie_genres genre2 USING (tmdb_id)
WHERE genre1.genres = 'Action'
AND genre2.genres = 'Crime'
See it for yourself here.
try something like this :
tableA
Movie_ID Movie_title
1 Iron man
2 Logan
3 Batman
4 The hangover
tableB
Genre_ID Genre_title
1 Action
2 Crime
3 Drama
4 Comedy
tableC
ID Movie_ID Genre_ID
1 1 1
2 1 2
3 2 2
4 2 3
query :
Select A.Movie_title,B.Genre_title
from tableC C
inner join tableA A on A.Movie_ID = C.Movie_ID
inner join tableB B on B.Genre_ID = C.Genre_ID
where
C.Genre_ID in (IFNULL(val1,0),IFNULL(val2,0))
you should make a relational table to solve you issues like so
movie table
movie_id movie_name genre_id
1 alien 2
2 logan 1
3 ps i love you 4
4 click 3
then you will need a genre table
genre table
genre_id genre_type
1 action
2 sci fi
3 comedy
4 romance
then your select would link the to tables
function get_movies_by_genre($genre_id) {
global $MySQLiConnect;
$query = '
SELECT *
FROM movies m
INNER JOIN genre g ON (g.genre_id = m.genre_id)
WHERE g.genre_id = ?
';
$stmt = $DBConnect->stmt_init();
if ($stmt->prepare($query)) {
$stmt->bind_param("i", $genre_id);
$stmt->execute();
$result = $stmt->get_result();
$rows = $result->fetch_all(MYSQLI_ASSOC);
$stmt->close();
}
return $rows;
}
or
function get_movies_by_genre($genre_id) {
global $MySQLiConnect;
$query = '
SELECT *
FROM movies m
INNER JOIN genre g ON (g.genre_id = m.genre_id)
WHERE g.genre_name = ?
';
$stmt = $DBConnect->stmt_init();
if ($stmt->prepare($query)) {
$stmt->bind_param("i", $genre_id);
$stmt->execute();
$result = $stmt->get_result();
$rows = $result->fetch_all(MYSQLI_ASSOC);
$stmt->close();
}
return $rows;
}
This is the base function to get you all information from the movie table depending on which genre id you send to it.
as for multiple ids you can then run the function through a foreach loop for as many genre_ids as you need and then display them as you need.
I hope this helps.
I have three tables
tbl_product
item_id | item_name
company_details
v_id | item_id | company_name
user_ratings
r_id | rate | v_id
I want to count the rate and also get the rate of the company. Here is my query
SELECT company_details.v_id,
company_details.company_name,
COUNT(user_ratings.rate) as vote,
user_ratings.rate,
tbl_product.item_name
FROM company_details
LEFT JOIN tbl_product ON tbl_product.item_id = company_details.item_id
LEFT JOIN user_ratings ON user_ratings.v_id = company_details.v_id
GROUP BY company_details.v_id, user_ratings.rate
This is Whts i am Getting after this query:
v_id company_name vote rate item_name
1 The Oberoi Udaivilas 1 4 5 Star Hotels
1 The Oberoi Udaivilas 1 5 5 Star Hotels
2 The Taj Mahal Palace 2 5 4 Star Hotels
3 Rambagh Palace 1 5 3 Star Hotels
4 Taj Lake Palace 1 5 5 Star Hotels
5 Windflower Hall 1 3 2 Star Hotels
5 Windflower Hall 1 5 2 Star Hotels
6 Leela Palace Kempinski 0 n 4 Star Hotels
7 Umaid Bhawan Palace 0 n 4 Star Hotels
8 Hotel Ratan Vilas 0 n 4 Star Hotels
9 The Leela Palace 0 n 4 Star Hotels
10 The Imperial Hotel 0 n 3 Star Hotels
You can see vote column is not counting.
This is what I am expecting
v_id company_name vote rate item_name
1 The Oberoi Udaivilas 2 5 5 Star Hotels
2 The Taj Mahal Palace 2 5 4 Star Hotels
But this query is not counting the rate from user_ratings table, because of I also want to get the rate, if I remove the user_ratings.rate from select clause, then this query works, but when I add the user_ratings.rate in the select clause, then this query is not counting the rates as(vote), and it is returning as one rows in every count.
You should remove user_ratings.rate from group by clause and add tbl_product.item_name.
SELECT
company_details.v_id,
company_details.company_name,
tbl_product.item_name,
COUNT(user_ratings.rate) as vote,
avg(user_ratings.rate) as rate
FROM
company_details
LEFT JOIN tbl_product ON tbl_product.item_id = company_details.item_id
LEFT JOIN user_ratings ON user_ratings.v_id = company_details.v_id
GROUP BY company_details.v_id, company_details.company_name, tbl_product.item_name;
Seems to me that your query is only missing an aggregation on the rate column, and from the expected output I'd say it's a max. You also should fix your group by. Try this one
SELECT company_details.v_id,
company_details.company_name,
COUNT(user_ratings.rate) as vote,
MAX(user_ratings.rate) as rate,
tbl_product.item_name
FROM company_details
LEFT JOIN tbl_product ON tbl_product.item_id = company_details.item_id
LEFT JOIN user_ratings ON user_ratings.v_id = company_details.v_id
GROUP BY company_details.v_id,
company_details.company_name,
tbl_product.item_name
Query and result are both correct. Look at the rate
you can try this query it will return your exactly output according to your given 3 tables.
"select c.v_id , c.company_name , u.rate , p.item_name from company_details c join tbl_product p on p.item_id = c.item_id join user_details u on c.v_id = u.v_id group by c.company_name ";
Currently I have 3 MySQL tables, one filed with the users information, one with their course history and the last one filled with their reward history.
I am attempting to create a "rewards" program if you will, using these two databases and a PHP script. As far as the reward requirements, I have 2 arrays setup for the two types of rewards:
//Pen Reward with course A & B required
$pen=array("a","b")
//Cup Reward with course B & C required
$cup=array("b","c")
I can't figure out how to first query for all user IDs, then go through their history. If they match the requirements set above, then to update the reward table to 1 (to show that they received the award)
UsersDB
userid name
----------------
1 bill
2 john
3 steve
HistoryDB
userid courseid
------------------
1 a
1 b
2 b
3 a
3 c
RewardHistoryDB
userid pen cup
---------------------
1 0 0
2 0 0
3 0 0
Ideally it after the PHP script runs, it would update the RewardHistoryDB to reflect that user 1 received a pen, and user 3 received a cup.(the DB would look like this:)
RewardHistoryDB (after)
userid pen cup
---------------------
1 1 0
2 0 0
3 0 1
Here is the PHP code I am using right now (not complete):
$userid=array();
$i=0;
//Find All users
$result = mysqli_query($con,"SELECT userid FROM usersdb")
while ($row = mysqli_fetch_array($result)){
$universityid[$i]=$row['universityid'];
$i++;
}
//Find History
$courseid=array();
foreach ($userid as $userid1){
$result = mysqli_query($con,"SELECT courseid FROM historydb WHERE userid='".$userid1."'");
while ($row = mysqli_fetch_array($result)){
$courseid[]=$row;
}
}
//Update Reward DB
//Don't even know where to start...
Any help would be greatly appreciated.
If you have any questions, please let me know.
Thank you in advanced!
http://sqlfiddle.com/#!2/1a96b/1/0
You can do this just as queries and without doing any logic in PHP
update RewardHistoryDB
set Pen = 1
where UserID in (
select UserID
from HistoryDB
where CourseID in ('A','B')
group by UserID
having count(UserID)=2);
update RewardHistoryDB
set Cup = 1
where UserID in (
select UserID
from HistoryDB
where CourseID in ('B','C')
group by UserID
having count(UserID)=2);
Or you can even do it in one, large statement...
update RewardHistoryDB
left outer join (
select UserID as Pens_UserID
from HistoryDB
where CourseID in ('A','B')
group by UserID
having count(UserID)=2 ) as Pens
on RewardHistoryDB.UserID = Pens.Pens_UserID
left outer join (
select UserID as Cups_UserID
from HistoryDB
where CourseID in ('B','C')
group by UserID
having count(UserID)=2 ) as Cups
on RewardHistoryDB.UserID = Cups.Cups_UserID
set Pen = case when Pens.Pens_UserID is not null then 1 else 0 end,
Cup = case when Cups.Cups_UserID is not null then 1 else 0 end
I have 2 tables colorcode & users
colorcode
ID colorid colorname
------------------------
1 1 yellow
2 2 black
3 3 red
4 4 white
users
ID userid colorid
------------------------
1 1 1,2
2 2 3,4
3 3 1,3,4
4 4 1
How do I retrieve & query individual colorid
$aa = $db->query("SELECT * FROM colorcode");
$colors = array();
while ($colordata = mysql_fetch_assoc($aa)) {
$colors[] = $colordata["colorid"];
}
Let's say I want query which users have yellow color & what it's the statement should I use for users
SELECT .. FROM users
WHERE colorid ....
It's a bad design... since you're trying to access the individual color_ids in the user table, but have stored them as a comma-separated list, you canot have the database do a normal join for you - you've killed off the main point of using a relational database by making it impossible to for the database to do the relating for you.
However, since you're on mysql, you're in luck - mysql has a function for cases like this:
SELECT users.ID, userid, GROUP_CONCAT(colorcode.colorname)
FROM users
LEFT JOIN colorcode ON FIND_IN_SET(colorcode.ID, users.colorid)
GROUP BY users.id
SELECT * FROM users
WHERE colorid LIKE "%1%"
But what I would really do is make a link table from users to colors:
usersToColors:
ID userid colorid
------------------------
1 1 1
2 1 2
3 2 3
4 2 4
...
Then you could do:
SELECT * FROM users u, usersToColors utc
WHERE u.userid = utc.userid
AND utc.colorid = 1;
Or even:
SELECT * FROM users u, usersToColors utc, colors c
WHERE u.userid = utc.userid
AND utc.colorid = c.colorid
AND c.colorname = "yellow";
I have written a query which returns all records with some many-to-many joins correctly for the entire set or an individual article using WHERE a.id = ?
SELECT a.id, date_added, title, content, category_id, person_id, organization_id, c.name AS category_name, firstname, lastname, o.name AS organization_name
FROM articles AS a
LEFT OUTER JOIN articles_categories AS ac ON a.id=ac.article_id
LEFT OUTER JOIN categories AS c ON c.id=ac.category_id
LEFT OUTER JOIN articles_people AS ap ON a.id=ap.article_id
LEFT OUTER JOIN people AS p ON p.id=ap.person_id
LEFT OUTER JOIN articles_organizations AS ao ON a.id=ao.article_id
LEFT OUTER JOIN organizations AS o ON o.id=ao.organization_id
ORDER BY date_added
BUT!
I've hit a brick wall trying to work out how to limit the articles to a specific number of IDs, for working with pagination.
I'm ideally trying to use as simple and clear SQL statements as possible because I'm using the codeigniter framework with their active record class.
http://codeigniter.com/user_guide/database/active_record.html
Would really appreciate some help as I don't want to revert to using multiple queries for this as I've tried to reduce it down to a single query for database efficiency.
Have search around and tried some alternatives but nothing seems to work. Many thanks!
For example the results I return are like this
---------------------------------------------------------------------
id title category_id person_id organization_id
---------------------------------------------------------------------
1 test 1 1 1
1 test 2 1 1
1 test 1 2 1
1 test 1 1 2
1 test 5 1 1
1 test 8 1 1
1 test 1 4 1
1 test 1 4 2
1 test 1 1 1
2 test 2 2 1 1
2 test 2 1 2 1
2 test 2 1 1 2
2 test 2 5 1 1
2 test 2 8 1 1
2 test 2 1 4 1
2 test 2 1 4 2
I need the results like this so that I can create sub-arrays in the php like this:
$articles = $query->result_array();
$output = array();
foreach ($articles as $article) {
// set up article details
$article_id = $article['id'];
// add article details
$output[$article_id]['article_id'] = $article_id;
$output[$article_id]['date_added'] = $article['date_added'];
$output[$article_id]['title'] = $article['title'];
$output[$article_id]['content'] = $article['content'];
// set up people details and add people array with details if exists
if (isset($article['person_id'])) {
$person_id = $article['person_id'];
$output[$article_id]['people'][$person_id]['person_id'] = $person_id;
$output[$article_id]['people'][$person_id]['lastname'] = $article['lastname'];
$output[$article_id]['people'][$person_id]['firstname'] = $article['firstname'];
}
// set up organizations details and add organizations array with details if exists
if (isset($article['organization_id'])) {
$organization_id = $article['organization_id'];
$output[$article_id]['organizations'][$organization_id]['organization_id'] = $organization_id;
$output[$article_id]['organizations'][$organization_id]['organization_name'] = $article['organization_name'];
}
// set up categories details and add categories array with details if exists
if (isset($article['category_id'])) {
$category_id = $article['category_id'];
$output[$article_id]['categories'][$category_id]['category_id'] = $category_id;
$output[$article_id]['categories'][$category_id]['category_name'] = $article['category_name'];
}
}
But if I just use LIMIT (with offset etc) 1
the results I get are
---------------------------------------------------------------------
id title category_id person_id organization_id
---------------------------------------------------------------------
1 test 1 1 1
instead of
---------------------------------------------------------------------
id title category_id person_id organization_id
---------------------------------------------------------------------
1 test 1 1 1
1 test 2 1 1
1 test 1 2 1
1 test 1 1 2
1 test 5 1 1
1 test 8 1 1
1 test 1 4 1
1 test 1 4 2
1 test 1 1 1
which is my desired result.
OK, so finally I worked out how it is possible.
Thought i'd include it here in case anyone else has the same problem.
Changing this line
FROM articles AS a
to this
FROM (SELECT * FROM articles LIMIT 5,3) AS a
does what I wanted.
So, why don't you use OFFSET 0,10 and LIMIT *number_of_results* in the SQL Query? (if I understood the question)
Specific number of IDs... WHERE ID IN (2,4,6,8)... ?
Are you using codeigniter's pagination?
http://codeigniter.com/user_guide/libraries/pagination.html
You can easily limit the number of records that are being returned using the MySQL LIMIT clause. This can be achieved like the following with your sample query.
SELECT a.id, date_added, title, content, category_id, person_id, organization_id, c.name AS category_name, firstname, lastname, o.name AS organization_name
FROM articles AS a
LEFT OUTER JOIN articles_categories AS ac ON a.id=ac.article_id LEFT OUTER JOIN categories AS c ON c.id=ac.category_id
LEFT OUTER JOIN articles_people AS ap ON a.id=ap.article_id LEFT OUTER JOIN people AS p ON p.id=ap.person_id
LEFT OUTER JOIN articles_organizations AS ao ON a.id=ao.article_id LEFT OUTER JOIN organizations AS o ON o.id=ao.organization_id
ORDER BY date_added
LIMIT 10
Where 10 is the number of records you wish to display. The MySQL LIMIT clause allows you to specify a limit of the number of records and an initial offset. Like so:
LIMIT <offset>,<limit>
In your case <offset> would be the current page * the number of records on a page. <limit> would be the number of records you would like to display per page.