I have this array in php code. I want to have that whenever page is being called it should print value of first array index and when next time second value of array index and so on... what modification I could do? for now it´s printing everything when being called single time.
<html>
<?php
$addresses = array('ifcbxespra', 'ifcheqjbmea', 'ifcqiknsa', 'ifcqirtjla', 'ifcwqsrlmn', 'ifclmkmzhz','ifcwdujhgc','ifcihddngh','icffhzudcd','ifchnsqzgs','ifcgssqrhg');
foreach ($addresses as &$value) {
echo $value ;
}
?>
</html>
I'm not sure if I understood what you want. But if you want to print the first array's value when the page loads one time, the second array's value when the page loads another time and so on, you can do this:
<?php
if(!isset($addresses) || empty($addresses)){ //checks if the array is not initialized or if it's empty
$addresses = array('ifcbxespra', 'ifcheqjbmea', 'ifcqiknsa', 'ifcqirtjla', 'ifcwqsrlmn', 'ifclmkmzhz','ifcwdujhgc','ifcihddngh','icffhzudcd','ifchnsqzgs','ifcgssqrhg');
echo $addresses[0]; //print the first value
array_splice($addresses, 0, 1); //removes the first element of the array and reindexes it
}else{
echo $addresses[0]; //print the first value
array_splice($addresses, 0, 1); //removes the first element of the array and reindexes it
}
The logic behinds it is: if the array already exists and is not empty (it has values), print the first value and then remove it, so next time the first value will be the second actual value. When the array is empty, redefine it as to start again.
You can search for more information on array_splice() here.
P.S.: you have to use PHP's $_SESSION to save the array between the pages.
You can use something like $_SESSION and store there the last index.
For example:
$array = array('one', 'two', 'three');
if (!$_SESSION['nextIndex'] || $_SESSION['nextIndex'] >= count($array)) {
$_SESSION['nextIndex'] = 0
}
// print the value
echo $array[$_SESSION['nextIndex']];
// increment the nextIndex
$_SESSION['nextIndex']++;
NOTE: This will only work for the same user. Each page reload will increment the array index. But if you need some cross-user counting, then you have to store the information somewhere on the server, like a DB or even a simple txt file.
Check out this example: http://hibbard.eu/how-to-make-a-simple-visitor-counter-using-php/
Finally I solved this problem with the MySQL. created a column with all code. and then call the script every-time when user press button. In the script first I fetch first raw and print that value, and then, delete that raw. so every-time user will get unique value from the list of code And it is working fine.
Related
I had a problem with my array_push, that i noticed.
So what i'm doing.:
I have a site, where there are some buttons with a specific value.
Each value is getting fetched from a database.
I have a session called test, that get's converted to an array(to store multiple in the same array)
Everytime one of the buttons are clicked, the value for that specific button, is getting pushed to the array.
But, i can ONLY see that it has been pushed at the second try.
[test] => Array( [0] => 21304 )
This is what i see, after second try. But my array count, says that there are 2 elements, in that array.
Here is my code:
if(isset($_POST['process'])) {
if(!isset($_SESSION['test'])) {
$_SESSION['test'] = array();
$array_merge = array_push($_SESSION['test'], $_POST['process']);
}
}
The $_POST['process'] is the button with the unique value.
Can somebody maybe see what I'm doing wrong here?
Kind regards
You are only adding to the $_SESSION['test'] array if $_SESSION['test'] was not previously set.
So you need to always add an occurance to the session array and only initialise the session array if it was not previously set
session_start();
// ...
if(isset($_POST['process'])) {
if(!isset($_SESSION['test'])) {
$_SESSION['test'] = array();
}
$_SESSION['test'][] = $_POST['process'];
}
NOTE from the manual
If you use array_push() to add one element to the array, it's better to use $array[] = because in that way there is no overhead of calling a function.
I am having a php session array like
('10/01/2017, '13/02/2017', '21/21/2107')
Now how to add and element or remove an element from this array in O(1)
The easiest way is to get the value, remove the item, and set the session variable again.
$data = $_SESSION['array']; // Get the value
unset($data[1]); // Remove an item (hardcoded the second here)
$_SESSION['array'] = $data; // Set the session value with the new array
Update:
Or like #Qirel said, you can unset the item directly if you know the number.
unset($_SESSION['array'][1]);
Update 2
If you want to remove the element by its value, you can use array_search to find the key of this element. Note that if there are to elements with this value, only the first will be removed.
$value_to_delete = '13/02/2017';
if (($key = array_search($value_to_delete, $_SESSION['array'])) !== false)
unset($_SESSION['array'][$key]);
To delete and element from an array use unset() function:
<?php
//session array O
unset(O["array"][1]);
?>
I used this but my array show blank.
foreach($page_data->result() as $text){ $i++;
echo $name="text".$i; //this line print ok.
$$name=array();
echo $$name['content']=$text->$content; //this line print ok.
print_r($text1);
} print_r($text1);
here i am tying to name the array dynamically as text1,text2,text3.......
but when i print $text1 it shows me a blank array.
can any one help me out with this.
It's simply a syntax ambiguity. $$name['content'] is understood as:
${$name['content']}
I.e. the name of the variable is supposed to be the value of $name['content'], which obviously doesn't exist, which actually leads to an error if you'd enable error reporting. You can solve this with:
${$name}['content'] = $text->$content;
However, you really should solve this by using an array instead of variable variables:
$texts[] = array('content' => $text->$content);
You're incrementing the index before you echo the contents of the variable, so if you only have 1 result, it will try and access an undefined index, you are also re initialising the name array every time you pass through the loop, you should not do this
Results
------------------
Num Content
0 I am a text post
If these were the results returned and you wanted to point to index i, then when your loop goes through this would happen:
i = 0;
i = 1;
assign values to name array
As there is only one result this would then happen
Results
------------------
Num Content
0 I am a text post
- - <----- i = 1 (null pointer exception?)
This would be why no values are showing in your array, try change your code to this:
// Declare i to point at the 0 index
$i = 0;
$name=array();
foreach($page_data->result() as $text){
$name[i]['content']=$text;
$i++;
}
Your name array will no add the text content to a new index with each pass of the loop, i.e. if you had 2 results
$name[0]['content'] = "This is a text post";
$name[1]['content'] = "Here is another post";
Hope this helps.
foreach($_POST['door_check'] as $door_check)
{
$_SESSION['front_door']['door'] = $door_check;
}
I have this little section of code that checks how many boxes were checked and then creates an array of the check box values.
The thing is, when I add that 'door' key, the array only adds one value no matter how many checkboxes were checked. When I just leave it empty, it adds all of them like [0], [1], [2] etc
Why is this?,
Your foreach() loops overwrites old variable each time. You need to make your session variable an array, for example
foreach($_POST['door_check'] as $door_check)
{
$_SESSION['front_door']['door'][] = $door_check;
}
edit: Don't forget to validate that data when you save it for later use.
Try something like this:
foreach($_POST['door_check'] as $door_check) {
$_SESSION['front_door']['door'][] = $door_check;
}
or maybe even:
$_SESSION['front_door']['door'] = $_POST['door_check'];
When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number.
The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array.
(A 2-Dimensional Table is used)
Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ?
$test1 = $_SESSION["table"][0];
$test2 = $_SESSION["table"][1];
$test3 = $_SESSION["table"][2];
$test4 = $_SESSION["table"][3];
$test5 = $_SESSION["table"][4];
What exactly is this, and how can i fix this?
Is it some sort of override that needs to happen?
Best Regards.
You don't need any sort of override. The script is printing "Array" rather than a value, because you're trying to print to the screen a whole array, rather than a value within an array for example:
$some_array = array('0','1','2','3');
echo $some_array; //this will print out "Array"
echo $some_array[0]; //this will print "0"
print_r($some_array); //this will list all values within the array. Try it out!
print_r() is not useful for production code, because its ugly; however, for testing purposes it can keep you from pulling your hair out over nested arrays.
It's perfectly fine to access elements in your array by index: $some_array[2]
if you want it in a table you might do something like this:
<table>
<tr>
for($i = 0 ; $i < count($some_array) ; $i++) {
echo '<td>'.$some_array[$i].'</td>';
}
</tr>
</table>
As noted, try
echo "<pre>";
print_r($_SESSION);
echo "</pre>";
That should show you what's in the session array.
A 2-dimensional table is just an array of arrays.
So, by pulling out $_SESSION["table"][0], you're pulling out an array that represents the first row of the table.
If you want a specific value from that table, you need to pass the second index, too. i.e. $_SESSION["table"][0][0]
Or you could just be lazy and do $table = $_SESSION["table"]; at which point $table would be your normal table again.
A nice way ...
<?php
foreach ($_SESSION as $key => $value) {
echo $key . " => " . $value . "<br>";
}
?>