Output images stored in database MySQL with php - php

Question

Snippet:
$connect = //connect to db;
$db = $connect->prepare("SELECT profilepicture FROM user WHERE uname = $uname");
$db->execute();
$db->bind_result($img);
...
echo $img;
Information:
- I have image.bin stored in a column of a table in db
- Opening image.bin in hex editor reveals hex codes (File header says it is a PNG file)
- echo $img doesn't output the image
Question:
- How to output images that are stored in db?

Answer 1

Form
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
This is how you upload the file
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)){
echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
$img = basename($_FILES["fileToUpload"]["name"]);
Your insert query
$db = $connect->prepare("UPDATE user SET profilepicture =? WHERE uname = ?");
$db->bind_param("si",$img,$uname);
$db->execute();
Taken from w3schools