MySql transaction works only in console - php

Question

When i paste this into MySql console
START TRANSACTION;
INSERT INTO `orders` (customer_id) VALUES ('2');
SET #lastid=LAST_INSERT_ID();
INSERT INTO `transactions`
(order_id,product_id,product_quantity,price,ammount,customer_id)
VALUES (#lastid,'3','2','4','4','2');
INSERT INTO `transactions`
(order_id,product_id,product_quantity,price,ammount,customer_id)
VALUES (#lastid,'1','3','5','4','2');
COMMIT;
it works fine, when i try to do the same via php
$sql = "START TRANSACTION;";
$sql .="INSERT INTO `orders` (customer_id) VALUES ('$customer_id_form');";
$sql .="SET #lastid=LAST_INSERT_ID();";
foreach ($product_id_form as $key => $product){
$sql .= "INSERT INTO `transactions`
(order_id,product_id,product_quantity,price,ammount,customer_id)
VALUES
(#lastid,'$product','$quantity_form[$key]',
'$price_form[$key]','$amount_form[$key]','$customer_id_form');";
}
$sql .= "COMMIT;";
//$sql = "INSERT INTO products (`product_name`,`curent_price`,`product_quota`) VALUES ('$productname_form','$productprice_form','$productquote_form')";
if ($con->query($sql) === TRUE) {
echo "New record created successfully";
header("Location: order.php");
} else {
echo "Error: " . $sql . "<br>" . $con->error;
}
mysqli_close($con);
it does not work error shown is
You have an error in your SQL syntax; check the manual that
corresponds to your MariaDB server version for the right syntax to use
near 'INSERT INTO orders (customer_id) VALUES ('2');SET
#lastid=LAST_INSERT_ID();INS' at line 1

Answer 1

Perform the queries one at a time; do not try to send them all at once to the server. The START...COMMIT will determine the transactional semantics.

Answer 2

I think you need multi_query, to execute multiple queries