SQLi Error when trying to echo a certain ID in PHP - php

Question

I am making a status update page for practicing PHP and MySQL.
I am currently trying to echo the saved status on the page.
The statuses are saved in a row called "Status" and they are all given a certain ID in a row called "statusID."
The problem I am having is which fetch I want to use because converting it into a string using (string)$var doesn't work. ($var is an example).
Also, the $idNum variable is something for later use, shouldn't have anything to do with this.
Here is the code: (Obviously the first variables are censored so none tries to connect to the database, the connection working in the actual code.)
The problem lies in the $fetchRes I believe.
<?php
$idNum = 1;
$servername = "censored";
$username = "censored";
$password = "censored";
$db_name = "censored";
$conn = mysqli_connect($servername, $username, $password, $db_name);
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT Status FROM SavedStatuses WHERE statusID=1;";
$statusQuery = mysqli_query($conn, $sql);
$fetchRes = mysqli_fetch_assoc($statusQuery);
if($conn->query($sql) == TRUE)
{
echo $fetchRes;
} else {
echo "Failed to retrieve status, error: " . $conn->error;
}
?>

Answer 1

As I mentioned in comments, you are querying twice and not looping over (successful) results.
A "loop" is to use either a while or a foreach. I used a while loop for this example.
From the "official" manual:
http://php.net/manual/en/mysqli-result.fetch-assoc.php
Example:
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$query = "SELECT Name, CountryCode FROM City ORDER by ID DESC LIMIT 50,5";
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf ("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}
/* free result set */
$result->free();
}
/* close connection */
$mysqli->close();
?>
So in your case, your code would read as:
Sidenote: Status and status are two different animals, so make sure the letter case matches (in the loop).
<?php
$mysqli = new mysqli("censored", "censored", "censored", "censored");
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$query = "SELECT Status FROM SavedStatuses WHERE statusID=1";
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
echo $row["Status"];
}
/* free result set */
$result->free();
}else{
echo "The query failed: " . mysqli_error($mysqli);
}
/* close connection */
$mysqli->close();
?>