Adding new table column on radio button condition - php

I have the table below which I have fileld with some default values:
while($records=mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>".$records['item1']."</td>";
echo "<td>".$records['item2']."</td>";
echo "<td>".$records['item3']."</td>";
echo "<td>".$records['item4']."</td>";
echo "<td>".$records['item5']."</td>";
echo "<td>".$records['item6']."</td>";
echo "<td>".$records['item7']."</td>";
echo "</tr>";
}
echo "</table>";
I also have a my_sql query statement that looks like this and references a function which sorts all the data by asc or desc:
$sortBy=$_POST['SortBy'];
$sortIn=$_POST['SortIn'];
$sql="SELECT * FROM Results ORDER BY $sortBy $sortIn";
$result=mysql_query($sql, $conn);
echo "<table>";
All of this works successfully with a bunch of connection statements that I won't include.
I also have a 2 option radio button that looks like this:
Include newItem
<input type="radio" name="IncludeNewItem" value="1" />Yes
<input type="radio" name="IncludeNewItem" value="0" />No
What I am trying to do is set it so that when I submit the user options from the HTML page, the table is generated (and sorted) and depending on the state of the radio button, it should either display or not display another column which already exists in the database. (For examples sake, let's call this 'item 8').
I tried creating something that looks like this:
$includeNI = if(isset($_POST['IncludeNewItem']))
{Alter Table Results Add $newItem };
But I'm really unsure about the syntax as I'm new to this language.
All help is appreciated.

Related

How to INSERT multiple rows with multiple values, but only for items that have checkboxes ticked next to them

I am coding a discography tool for a music database.
Artists are able to insert tracks, singles, EPs, and albums all into separate tables on the database.
Having tracks be in their own separate table allows the same tracks to be attached to multiple singles, EPs and albums while only requiring there to be one record for that track in the database.
Which means individual track pages can have an automatically generated list of links back to the Singles, EPs and albums that they appear on. Making navigating the database through the website a much smoother experience.
I have come to the point where I am coding a tool to attach any existing tracks in the database for a given artist onto an album page.
I am using another table in the database called 'trackconnections' to create the relational links between the track ids from the track table and the album id from the album table, with an additional column called albumtracknum available to be able to output the tracks in the right order when queried on the album page.
The code for the tool is behind a button labelled 'Attach existing track(s) to album'. The code for this tool is as follows:
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "includes/db_connect.pdo.php";
$artistid = $_POST["artistid"];
$albumid = $_POST["albumid"];
echo '<strong>Select each track you would like to add to this album below and type in the track number you want it to have on the album in the box underneith the name of each selected track.</strong><br><br>';
$stmt = $pdo->query("SELECT * FROM track WHERE artist_id = '$artistid'
order by trackname");
while ($row = $stmt->fetch())
{
echo '<form action="includes/attachexistingtracktoalbum.inc.php" method = "post">';
echo '<div class="checkbox">';
echo '<label>';
echo "<input type='checkbox' name='trackid[]' value='".$row['id']."' />";
echo '<span class="cr"><i class="cr-icon glyphicon glyphicon-ok"></i></span>';
echo ' '.$row['trackname'];
echo '</label>';
echo "<br><label for='albumtracknum'>Track number:</label><br>
<input type='text' name='albumtracknum[]'>
<input type='hidden' name='albumid[]' value='".$albumid,"'>
<br><br>";
echo '</div>';
}
?>
<input type="hidden" name="albumidforreturn" value="<?php echo $albumid;?>">
<button type="submit" name="attachexistingtracktoalbum-submit">Attach track(s) to album</button>
<?php }
else {
header("Location: /index.php");
exit();
}?>
(NB: The post data here is not sanitised for the sql query as it has been passed along in a hidden form from the original album page)
This generates a page with all track names for the current artist available on a list with checkboxes, with each track name being followed by a data entry box to enter the track number for the album being added to.
Submission of the form then hands off to the following include code:
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "db_connect.pdo.php";
$albumid = implode(',',$_POST['albumid']);
$trackid = implode(',',$_POST['trackid']);
$albumtracknum = implode(',',$_POST['albumtracknum']);
$albumidforreturn = $_POST['albumidforreturn'];
// echo 'albumid: '.$albumid.'<br>';
// echo 'trackid: '.$trackid.'<br>';
// echo 'albumtracknum: '.$albumtracknum.'<br>';
$sql = "INSERT INTO trackconnections (albumid, trackid, albumtracknum) VALUES (?,?,?);";
$stmt= $pdo->prepare($sql);
$stmt->execute([$albumid,$trackid,$albumtracknum]);
header("Location: ../albumdetail.php?albumid=$albumidforreturn");
exit();
}
else {
header("Location: ../index.php");
exit();
}
(NB: The commented out echos are there to test what the output is from the previous form)
The 2 problems I am having are that my 'Attach existing tracks to album' form submit:
1. Passes on too much data.
The generated form should only pass on the track ids, album number, and track numbers that have had their checkboxes ticked. For insertion into the 'trackconnections' table.
Instead it narrows down the ticked checkbox track ids only and then creates comma separated values for every available track to select, rather than just those actually selected.
Which leads to annoying outputs such as the following when passing on data from form to include:
albumid: 4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4
trackid: 30,14
albumtracknum: ,2,3,,,,,,,,,,,,,,,,,,,,,
Where it should only read as:
albumid: 4,4
trackid: 30,14
albumtracknum: 2,3
Having too much data get passed through means that the row inserts won't be correct on multiple INSERTS once I do get this working, as they won't align with one another in the correct order.
2. The include only INSERTS 1 row to the 'trackconnections' table.
It seems I am misunderstanding how to add multiple rows to the database with my code here.
As having multiple checkboxes ticked on my 'Attach existing tracks to album' form only inserts 1 single row to the database on submission of the form each time.
Consistently the only track that gets added to the 'trackconnections' table is the first track with its checkbox ticked and, because of issue no. 1 above, the albumtracknum is always 0 unless I type a number into the first albumtracknum box on the available checklist.
I need to make tweaks to this code so that both problem 1 and 2 are addressed together, meaning that ticking the checkboxes & adding track numbers into each box following the track names actually adds multiple rows to the database along with their corresponding album track numbers.
I hope someone can help.
EDIT TO SHOW REFINED AND WORKING CODE:
New code for checkbox and textbox sections -
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "includes/db_connect.pdo.php";
$artistid = $_POST["artistid"];
$albumid = $_POST["albumid"];
echo '<strong>Select each track you would like to add to this album below and type in the track number you want it to have on the album in the box underneith the name of each selected track.</strong><br><br>';
$stmt = $pdo->query("SELECT * FROM track WHERE artist_id = '$artistid'
order by trackname");
echo '<form action="includes/attachexistingtracktoalbum.inc.php" method = "post">';
while ($row = $stmt->fetch())
{
echo '<div class="checkbox">';
echo '<label>';
echo "<input type='checkbox' name='trackid[]' value='".$row['id']."' />";
echo '<span class="cr"><i class="cr-icon glyphicon glyphicon-ok"></i></span>';
echo ' '.$row['trackname'];
echo '</label>';
echo "<br><label for='albumtracknumber'>Track number:</label><br>
<input type='text' name='albumtracknumber_".$row['id']."'>
<input type='hidden' name='albumid[]' value='".$albumid,"'>
<br><br>";
echo '</div>';
}
?>
<input type="hidden" name="albumidforreturn" value="<?php echo $albumid;?>">
<button type="submit" name="attachexistingtracktoalbum-submit">Attach track(s) to album</button>
</form>
<?php }
else {
header("Location: /index.php");
exit();
}
New code for the include INSERT processing -
if (isset($_POST['attachexistingtracktoalbum-submit'])) {
require "db_connect.pdo.php";
$albumid = implode(',',$_POST['albumid']);
$trackid = implode(',',$_POST['trackid']);
$albumidforreturn = $_POST['albumidforreturn'];
foreach($_POST['trackid'] as $trackidloop) {
$albumtracknum = $_POST["albumtracknumber_{$trackidloop}"];
$sql = "INSERT INTO trackconnections (albumid, trackid, albumtracknum) VALUES (?,?,?);";
$stmt= $pdo->prepare($sql);
$stmt->execute([$albumid,$trackidloop,$albumtracknum]);
}
header("Location: ../albumdetail.php?albumid=$albumidforreturn");
exit();
}
else {
header("Location: ../index.php");
exit();
}
This isn't an entire solution but I see some problems:
You are looping through tracks and creating a new form for each one. The first problem is , you are missing the closing form tag. I guess the browser is automatically creating one, when it sees the next form start tag. ?? That's why you only get one single posted checkbox.
I would put all the track checkboxes into a single form. Then the posted trackid[] array will contain all the checked items.
[EDIT after your comment: The hidden fields albumid[] post the entire array, whereas the trackid[] checkboxes only post the actual checked boxes (HTML spec).
Instead of having albumid[], You could put the trackID and albumID together for the checkbox value, then parse them apart when you handle the post:
$value = $row['id']. ',' . $row['albumid'];
echo "<input type='checkbox' name='trackid[]' value='".$value."' />";
ALSO, the SQL, "INSERT INTO (..) .. VALUES (...) " only inserts one row.
It's easy to do that SQL in a loop for all the checked boxes.
foreach($_POST['trackid'] as $value) {
// parse the $value...
// SQL Insert...
}
EDIT 2: From my own comment:
Like hidden fields, input (text) field arrays also post the entire array (with empty values for blank inputs). (Again, this is not a PHP thing, it's a web browser standard to only post checked checkboxes and radio buttons. But ALL text and hidden INPUTs are posted.) So in your example, you need to code a mechanism to know which textbox goes with each checkbox. Quick and dirty...You could add a row index (0,1,2,3...) as another comma-separated number in your checkbox values, then you'll have the index into the posted textbox array. Alternatively, you could name the textboxes ' .. name="textinput_' . $row['trackid'] . '" ...' (not an array), then upon post, read them in your foreach loop with
$val = $_POST["textinput_{$trackid}"];

Submit values from table not working properly after filtering data

I have a bootstrap table which has a form in it, with each row containing a column where the value can be changed from a drop-down box. On clicking the 'Save changes' button, all the rows will be updated with the new values.
The form/table works as intended in normal cases. But if I use the search functionality of the bootstrap table to filter out a few of the rows and then try to update rows with the values, the wrong rows are getting affected.
So from the example in the above image, if I filter out to view just the second row like in the picture below, then the changes, or the 'Update' query is executed on the actual first row, that is to the row which had 'Bob' as the 'technician'.
I'd like to know how to solve this issue.
Here is the relevant code:
foreach($tickets as $tickets)
{
$users = $app['database']->selectAll('users');
echo ("<input type='text' style = 'display:none' value = '$tickets->id' name = 'ticketid[]'>");
echo "<td class = '$technician->color'>$technician->name</td>";
echo "<td>";
echo '<select name = "user[]" id="user" class="form-control">';
echo "<option value = $technician->id>$technician->name</option>";
foreach($users as $users)
{
echo "<option value = $users->id>$users->name</option>";
}
echo "</select>";
echo "</td>";
echo "</tr>";
}
For the database part, I am calling a function transferTask which accepts first the table name, then two arrays, one array containing updated usernames from the dropdown fields and one containing corresponding ids.
transferTask('tickets', $user[$i], $ticketid[$i])
The above function is executed for each row in the table. I think it's an issue wit the name array being passed from the form to this function but I'm not sure. Help is appreciated!

PHP/MySQL Auto select option based on previous page

I have a music database with a PHP front end where you can add/edit/delete artists, albums, tracks using the web client. The last real problem I have is getting a select box to automatically select an option I pass to the page.
Example:
On a page called 'createCD.php' I have this code:
echo "<td><a href=\"editCD.php?cdTitle=".rawurlencode($row['cdTitle'])."&cdID=$row[cdID]&artID=$row[artID]&cdGenre=".rawurlencode($row['cdGenre'])."&cdPrice=$row[cdPrice]\" </a>Edit</td>";`
This is used as a link to the next page, and collects all the information about an album in the database and sends in to a page called 'editCD.php'.
Now on this page, all the information is used to fill out the webpage as shown here (there is more but for the purposes of this post, only the first select box matters):
Artist Name:
<!-- dropdown with artist name -->
<?php
echo '<select name= "artID" id="artID">';
while ($row = mysqli_fetch_assoc($result)){
echo '<option value="'.$row['artID'].'">'.$row['artName'].'</option>';
}
echo '</select>';
?>
<p>
Album Title:
<input id="cdTitle" type="text" name="cdTitle" value ="<?php echo htmlspecialchars($cdTitle); ?>" />
</p>
What I would like is for the "selected" option for 'artID' to be the value that is passed to the page. Using the associative array, I was able to display the 'artName' associated with the 'artID'. Currently, all the information about the album appears correctly apart from the 'artName' and it defaults to the first value. This is a problem as if a user simply clicks "Update" it will update the name to the default name, therefore changing the database entry by accident.
I know I need to be using
<option selected ...>
but I'm not sure on the syntax to use.
<?php
$artID = $_GET['artID']; // get the artID from the URL, you should do data validation
echo '<select name= "artID" id="artID">';
while ($row = mysqli_fetch_assoc($result)){
echo '<option value="'.$row['artID'].'"';
if ($artID == $row['artID']) echo ' selected'; // pre-select if $artID is the current artID
echo '>'.$row['artName'].'</option>';
}
echo '</select>';
?>
$artId = $_GET['artID'];
while ($row = mysqli_fetch_assoc($result)) {
$selected = $artId == $row['artID'] ? 'selected' : '';
echo '<option value="'.$row['artID'].'" '.$selected.'>'.$row['artName'].'</option>';
}
First you get the id via $_GET['artID']. (In a real scenario use intval or something to prevent sql injection)
Then check in the loop if the id from database is the same as the id from GET and when it is print "selected, else nothing.

Generate a query that changes a single element on multiple rows PHP MySQL

I'm working on a homework assignment that involves PHP. Basically, I have a page that contains a web form that renders items pulled from a database. There's checkboxes on each row and 2 radio buttons. The user selects "accept" or "deny" and when submit is clicked, the items that are checked are supposed to change to that approval status. All of the items in the form are submitted into post. I thought that post is an array so I could just use a while loop with a counter so that the loop traverses through the array and when it gets to the last index (which should contain approve or deny). A query is generated that changes all of the previous indexes to approve or deny. I'm sorry if this isn't making much sense.
Here's a picture for more clarification
Here's the code I used to generate the webform:
<?php
#create a query string
$query = "SELECT * FROM Request WHERE superemail = '$user'";
#echo $query;
#run the query
$result = mysqli_query($link, $query) or die('error querying');
while($row = mysqli_fetch_array($result)){
#print out each row of the queryi
#line up the query results with temporary strings
$change = $row['KEY'];
$name = $row['first']. " " . $row['last'];
#echo $name;
$email = $row['email'];
#echo $email;
$type = $row['type'];
#echo $type;
$duration = $row['duration'];
$status = $row['status'];
#create a table row with the query results
echo "<tr><td><input type=checkbox name=$change /></td>
<td>$name</td>
<td>$email</td><td>$type</td>
<td>$duration</td><td>$status</td></tr>";
} #end while
?>
<label for=update>Change status to:</label><br />
<input type=radio name=update value=A />Approved<br />
<input type=radio name=update value=D />Denied<br />
<input type = submit value = "Change Status" />
Each input tag (your checkboxes and your radio button) in your html should have a name attribute, such as: <input type='radio' name='accept' value='1' />. When the form is submitted and processed by PHP, your script will be able to access that info at $_POST['accept'] (or $_GET['accept'] depending on the form's method).
So you should be able to specify a name for the radio button, then check to see if there is a value in the POST array at that index.
I am going to assume a few things. First, that it is a design goal of yours to only process items in your approval queue that you choose to select, leaving the others alone. Second, that you want to change their status to what is chosen in a radio button. Third, that you want both a code snippet and an explanation as to how the task got accomplished.
So, here goes.
You have a series of checkboxes; I assume they have the same name. If you wish for the values to be passed to PHP as an array, you absolutely need to name the inputs whatever[] with emphatic emphasis on the []! This is what creates an array from the checkbox to appear in the $_POST/$_GET. Only those items selected will appear in the array. The value ought to be something useful (A value in the corresponding database table, say) which you can select for and query on...after sanitizing the input, of course.
So, your HTML input tag should look like this:
<input type="checkbox" name="process[]" value="<?php echo $employeeName ?>" >
You should have this coming back at you...
$_POST['process'][array(0=>name1, 1=>name2/*...etc*/)]
...which you can loop through with a foreach at your leisure.

Dynamic web record

I'm trying to build a simple app:
Six columns with these values
Nr, Name, checkbox 1, checkbox 2, checkbox 3, checkbox 4.
The checkboxes are project stages. I'm using MySQL to store the data and retrieving it to a webpage with PHP.
My problem is on how to go updating the checkboxes, and also how to filter the results (display only records with checkbox 1 checked).
Or can anyone recommend other solutions/platforms?
This is not overly complex I thought someone must knew a better or easier way to do this.
After your sql query, something like this would work:
if($row['checkbox1'])
echo "<INPUT TYPE=CHECKBOX NAME=checkbox1 CHECKED>";
else
echo "<INPUT TYPE=CHECKBOX NAME=checkbox1>";
Query for filtering:
select * from table where checkbox1 = 1;
<input type='checkbox' name='aname' value='avalue' <?php
if(isChecked($dbrow, $itemname)) // you write this function
{
echo "checked='checked'";
}
?>/>

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