I get a file from my FTP server and I want to know if it is used. I get it with :
$handle=fopen("ftp://".$username.":".$password."#".$host.":21".$directory."/".$file, "r");
But before use it or change it, I want to know if someone else is reading or updating it. Is there a php function for that please ?
Thanks in advance.
EDIT :
I tried with flock() but it doesn't work, it always pass through echo check :
if (!flock($handle, LOCK_EX | LOCK_NB, $wouldblock)) {
if (!$wouldblock) {
echo "check";
} else {
echo "test";
}
} else {
echo "try";
}
Related
I am developing a PHP script that allows me to modify tags in an XML file and move them once done.
My script works correctly but I would like to add error handling: So that if the result of my SQL query does not return anything display an error message or better, send a mail, and not move the file with the error and move to the next.
I did some tests but the code never displays the error and it moves the file anyway.
Can someone help me to understand why? Thanks
<?php
}
}
$xml->formatOutput = true;
$xml->save($source_file);
rename($source_file,$destination_file);
}
}
closedir($dir);
?>
Give this one a try
$result = odbc_fetch_array($exec);
if ($result === false || $result['GEAN'] === null) {
echo "GEAN not found for $SKU_CODE";
// continue;
}
$barcode = (string) $result['GEAN'];
echo $barcode; echo "<br>"; //9353970875729
$node->getElementsByTagName("SKU")->item(0)->nodeValue = "";
$node->getElementsByTagName("SKU")->item(0)->appendChild($xml->createTextNode($result[GEAN]));
how can I check if a php ping returned succesfull or failed using php exec, I have in mind something with a while loop but I'm not sure if ts the best approach, I tried:
exec('ping www.google.com', $output)
but I would have to do a var_dump($output); to see the results, I want for each line the ping command returns to check it
$i = 2;
while(exec('ping www.google.com', $output)) {
if($output) {
echo 'True';
} else {
echo 'False';
}
}
I know this code is WRONG but its kind of what I need, if any of you could give me a head start on how to do it or suggestions I would really appreciate it....THANKS!!
This should do it:
if(exec('ping http://www.google.com')) {
echo 'True';
} else {
echo 'False';
}
I suggest you could use CUrl See Manual but that all depends upon what you are trying to achieve.
Provide more data if needed.
NOTE
You are to use http:// before google.com as that's needed in order to make the ping.
It's probably faster and more efficient and just do it within PHP, instead of exec'ing a shell
$host = '1.2.3.4';
$port = 80;
$waitTimeoutInSeconds = 1;
if($fp = fsockopen($host,$port,$errCode,$errStr,$waitTimeoutInSeconds)){
// It worked
} else {
// It didn't work
}
fclose($fp);
Also some servers will have EXEC disabled for security reasons, so your method won't work on every server setup.
I'm trying to print the host/ip to the screen. But, it's printing: "Resource id #2" instead. I'm using SSH2_connection(). I read the doc page and know the the function parameters are host, port, methods ... but when I try fread($host), the host/ip is still not printing can someone give me some direction on this? Thanks!
Code:
<?php
if (!function_exists("ssh2_connect")) die("function ssh2_connect doesn't exist");
if(!($ssh = ssh2_connect('10.5.32.12', 22))) {
echo "fail: unable to establish connection\n";
} else {
if(!ssh2_auth_password($ssh, 'root', '********')) {
echo "fail: unable to authenticate\n";
} else {
echo "Okay: Logged in ... ";
$content = fread($ssh); //Line in question (want ip address to show here)
echo "$content <br>"; //Line in quesion
$stream = ssh2_exec($ssh, 'find / -name *.log -o -name *.txt');
stream_set_blocking($stream, true);
$data = '';
while($buffer = fread($stream, 4096)) {
$data .= $buffer;
}
fclose($stream);
echo $data; // user
}
}
?>
I believe you need the parenthesis around the variabls as well when using double quotes. "{$content} <br>"
Have you tested with your own debug methods whether the $content variable contains information? You can set a value for the variable to test whether your echo statement is correct syntax.
$content = fread($ssh);
fread() reads from a file and puts the info into a resource handler for use later. I don't think you are using this in the right way currently.
I don't see where $ssh is being defined, but I assume it holds the IP you are wanting to output? If that is the case, just replace
$content = fread($ssh);
With:
echo $ssh;
I have got this JavaScript code for uploading files to my server (named it "upload.js"):
function startUpload(){
document.getElementById('upload_form').style.visibility = 'hidden';
return true;
}
function stopUpload(success){
var result = '';
if (success == 1){
result = '<div class="correct_sms">The file name is [HERE I NEED THE VARIABLE FROM THE EXTERNAL PHP FILE]!</div>';
}
else {
result = '<div class="wrong_sms">There was an error during upload!</div>';
}
document.getElementById('upload_form').innerHTML = result;
document.getElementById('upload_form').style.visibility = 'visible';
return true;
}
And I've got a simple .php file that process uploads with renaming the uploaded files (I named it "process_file.php"), and connects again with upload.js to fetch the result:
<?php
$file_name = $HTTP_POST_FILES['myfile']['name'];
$random_digit = rand(0000,9999);
$new_file_name = $random_digit.$file_name;
$path= "../../../images/home/smsbanner/pixels/".$new_file_name;
if($myfile !=none)
{
if(copy($HTTP_POST_FILES['myfile']['tmp_name'], $path))
{
$result = 1;
}
else
{
$result = 0;
}
}
sleep(1);
?>
<script language="javascript" type="text/javascript">window.top.window.stopUpload(<?php echo $result; ?>);</script>
What I need is inside upload.js to visualize the new name of the uploaded file as an answer if the upload process has been correct? I wrote inside JavaScript code above where exactly I need to put the new name answer.
You have to change your code to the following.
<?php
$file_name = $HTTP_POST_FILES['myfile']['name'];
$random_digit=rand(0000,9999);
$new_file_name=$random_digit.$file_name;
$path= "../../../images/home/smsbanner/pixels/".$new_file_name;
if($myfile !=none)
{
if(copy($HTTP_POST_FILES['myfile']['tmp_name'], $path))
{
$result = 1;
}
else
{
$result = 0;
}
}
sleep(1);
?>
<script language="javascript" type="text/javascript">window.top.window.stopUpload(<?php echo $result; ?>, '<?php echo "message" ?>');</script>
And your JavaScript code,
function stopUpload(success, message){
var result = '';
if (success == 1){
result = '<div class="correct_sms">The file name is '+message+'!</div>';
}
else {
result = '<div class="wrong_sms">There was an error during upload!</div>';
}
document.getElementById('upload_form').innerHTML = result;
document.getElementById('upload_form').style.visibility = 'visible';
return true;
}
RageZ's answer was just about what I was going to post, but to be a little more specific, the last line of your php file should look like this:
<script language="javascript" type="text/javascript">window.top.window.stopUpload(<?php echo $result; ?>, '<?php echo $new_file_name ?>');</script>
The javascript will error without quotes around that second argument and I'm assuming $new_file_name is what you want to pass in. To be safe, you probably even want to escape the file name (I think in this case addslashes will work).
A dumb man once said; "There are no stupid questions, only stupid answers". Though he was wrong; there are in fact loads of stupid questions, but this is not one of them.
Besides that, you are stating that the .js is uploading the file. This isn't really true.
I bet you didn't post all your code.
You can make the PHP and JavaScript work together on this problem by using Ajax, I recommend using the jQuery framework to accomplish this, mostly because it has easy to use functions for Ajax, but also because it has excellent documentation.
How about extending the callback script with:
window.top.window.stopUpload(
<?php echo $result; ?>,
'<?php echo(addslashes($new_file_name)); ?>'
);
(The addslashes and quotes are necessary to make the PHP string come out encoded into a JavaScript string literal.)
Then add a 'filename' parameter to the stopUpload() function and spit it out in the HTML.
$new_file_name=$random_digit.$file_name;
Sorry, that is not sufficient to make a filename safe. $file_name might contain segments like ‘x/../../y’, or various other illegal or inconsistently-supported characters. Filename sanitisation is much harder than it looks; you are better off making up a completely new (random) file name and not relying on user input for it at all.
when I'm trying to getimagesize($img) and the image doesn't exist, I get an error. I don't want to first check whether the file exists, just handle the error.
I'm not sure how try catch works, but I want to do something like:
try: getimagesize($img) $works = true
catch: $works = flase
Like you said, if used on a non-existing file, getimagesize generates a warning :
This code :
if ($data = getimagesize('not-existing.png')) {
echo "OK";
} else {
echo "NOT OK";
}
will get you a
Warning: getimagesize(not-existing.png) [function.getimagesize]:
failed to open stream: No such file or directory
A solution would be to use the # operator, to mask that error :
if ($data = #getimagesize('not-existing.png')) {
echo "OK";
} else {
echo "NOT OK";
}
As the file doesn't exist, $data will still be false ; but no warning will be displayed.
Another solution would be to check if the file exists, before using getimagesize ; something like this would do :
if (file_exists('not-existing.png') &&
($data = getimagesize('not-existing.png'))
) {
echo "OK";
} else {
echo "NOT OK";
}
If the file doesn't exist, getimagesize is not called -- which means no warning
Still, this solution is not the one you should use for images that are on another server, and accessed via HTTP (if you are in this case), as it'll mean two requests to the remote server.
For local images, that would be quite OK, I suppose ; only problem I see is the notice generated when there is a read error not being masked.
Finally :
I would allow errors to be displayed on your developpement server,
And would not display those on your production server -- see display_errors, about that ;-)
Call me a dirty hacker zombie who will be going to hell, but I usually get around this problem by catching the warning output into an output buffer, and then checking the buffer. Try this:
ob_start();
$data = getimagesize('not-existing.png');
$resize_warning = ob_get_clean();
if(!empty($resize_warning)) {
print "NOT OK";
# We could even print out the warning here, just as PHP would do
print "$resize_warning";
} else {
print "OK"
}
Like I said, not the way to get a cozy place in programmer's heaven, but when it comes to dysfunctional error handling, a man has to do what a man has to do.
I'm sorry that raise such old topic. Recently encountered a similar problem and found this topic instead a solution. For religious reasons I think that '#' is bad decision. And then I found another solution, it looks something like this:
function exception_error_handler( $errno, $errstr, $errfile, $errline ) {
throw new Exception($errstr);
}
set_error_handler("exception_error_handler");
try {
$imageinfo = getimagesize($image_url);
} catch (Exception $e) {
$imageinfo = false;
}
This solution has worked for me.
try {
if (url_exists ($photoUrl) && is_array (getimagesize ($photoUrl)))
{
return $photoUrl;
}
} catch (\Exception $e) { return ''; }
Simple and working solution based on other answers:
$img_url = "not-existing.jpg";
if ( is_file($img_url) && is_array($img_size = getimagesize($img_url)) ) {
print_r($img_size);
echo "OK";
} else {
echo "NOT OK";
}