Why I can't retrieve all data given an ID? php-codeigniter - php

I'm trying to retrieve data from datbase given an ID number.
Controller:
Usuario.php
public function seleccionar_por_id_estado(){
$id_estado = $this->input->post('id_estado');
$result = $this->usuario_m->ver_datos_por_id($id_estado);
$data['result'] = $result;
$this->load->view('paginas/administrar_usuarios', $data);
}
My Model
usuario_m.php
public function ver_datos_por_id($id_estado){
$condicion = "estado =" . "'". $id_estado ."'";
$this->db->select('*');
$this->db->from('usuarios');
$this->db->where($condicion);
$query = $this->db->get();
return $query->result();
}
My View
administrar_usuarios.php
<form action="usuario/seleccionar_por_id_estado">
<div class="content well">
<label>Ver por:
<select id="id_estado">
<option>Activo</option>
<option>Inactivo</option>
</select>
<?php
foreach ($result as $u){?>
<?php echo $u->usuario;?> <br>
<?php } ?>
</form>
The error that I'm getting is that the var $result is not defined.
Could you help me, please? Thanks!

In your model.Set condition inside $this->db->where() like this
<?php
public function ver_datos_por_id($id_estado){
$this->db->select('*');
$this->db->from('usuarios');
$this->db->where('estado',$id_estado);//set your condition here
$query = $this->db->get();
return $query->result();
}
OR use $this->db->get_where
$query = $this->db->get_where('usuarios',array('estado'=>$id_estado));
return $query->result();
For more see docs Codeigniter Query Builder
UPDATE
Controller:
public function seleccionar_por_id_estado(){
$id_estado = $this->input->post('id_estado');
$data['result'] = $this->usuario_m->ver_datos_por_id($id_estado);
$this->load->view('paginas/administrar_usuarios', $data);
}

I think issue is in your where condition in model.
use this query
$query = $this->db->get_where('usuarios', array('column name of your table' => $condicion));

First, I'd check to be certain that $id_estado isn't empty.
Another possible problem is that Codeigniter really wants you to capitalize class and file names. I'd try renaming the model to 'Usuario_m.php', name the class in the model Usuario_m, and then load it by calling $this->load->model('Usuario_m); (looks like you forgot to load the model too) and then finally call the model function like this:
$result = $this->Usuario_m->ver_datos_por_id($id_estado);
Update
Your where() parameters are wrong too. Your entire function in the model can be just this:
public function ver_datos_por_id($id_estado){
return $this->db->get_where('usurarios', array('estado' =>$id_estado)->result();
}
The get_where function combines get() and where(), chooses the table with the first parameter (so you don't need $this->db->from('usuarios');)

Related

How to call 2 model function in one function controller in codeigniter

I am new to codeigniter, so please help me to solve my problem.
I want to call my two model function in one function controller. Heres my two model function:
public function getposts($postid){
$this->db->select('*');
$this->db->from('tbl_endangered');
$this->db->where(['endangeredid'=>$postid]);
$query = $this->db->get();
return $query->result();
}
public function getSinglePost($postid){
$this->db->select('*');
$this->db->from('tbl_images');
//$this->db->join('tbl_images');
$this->db->where(['endangeredid'=>$postid]);
$query = $this->db->get();
return $query->result();
}
And here is my function controller:
public function viewAnimals($postid){
if(!$this->session->userdata("id") )
return redirect("AuthCon/login");
$this->load->model('Show');
$posts = $this->Show->getSinglePost($postid);
//$posts = $this->Show->getposts($postid);
$this->load->view('Showimage',['posts'=>$posts]);
}
In that code above I always get the first one that I declared. I want to fetch the getposts and getSinglePost inside the function viewAnimals controller.
Hopeyou can help me. Thanks in advance
I think using same variable name is creating a mess.
you can try assigning to posts array with output in it.
$this->load->model('Show');
$posts['getSinglePostData'] = $this->Show->getSinglePost($postid);
$posts['getPostsData'] = $this->Show->getposts($postid);
$this->load->view('Showimage',$posts);
Do like this in the controller
public function viewAnimals($postid){
if(!$this->session->userdata("id"))
return redirect("AuthCon/login");
$this->load->model('Show');
$data['images'] = $this->Show->getSinglePost($postid);
$data['endangered'] = $this->Show->getposts($postid);
$this->load->view('Showimage', $data);
}
Another way is to use join() and only one model function
public function getSinglePost($postid){
$this->db->select('*');
$this->db->from('tbl_images');
$this->db->join('tbl_endangered', 'tbl_endangered.endangeredid = tbl_images.endangeredid');
$this->db->where('tbl_images.endangeredid', $postid);
return $this->db->get()->result();
}

Search through name instead of id in code igniter..?

I am a new to php, have this code in controller:
public function selectquery($id){
$this->load->database();
$this->load->model('aboutmodel');
$data['h'] = $this->aboutmodel->selectquery($id);
$this->load->view('aboutpageview', $data);
}
and this in model:
public function selectquery($id){
$query =$this->db->get_where('phone_mobileinfos',array('id'=>$id));
// return $query->row_array();
return $query;
}
this in view:
{
<p>Mobile_name:<?php echo $h['mobile_name'];?></p>
<p>Price:<?php echo $h['price'];?></p>
}
Just want to search by name instead of id any suggestions..?
In model:
public function selectByName($name){
$query =$this->db->get_where('phone_mobileinfos',array('name'=>$name));
return $query->result_array();
}
use in controller:
$data['by_name'] = $this->aboutmodel->selectquery($id);
in view:
<p>Mobile_name:<?php echo $by_name['mobile_name'];?></p>
<p>Price:<?php echo $by_name['price'];?></p>
So, If I get you correctly and Adding to j.Litvak's code, you want to search the db for a name rather than an id? If so you would need to pass the controller method the name variable i.e. http://localhost/controller_name/method/search_parameter, in your case localhost/controller/selectquery/samsung
Your controller will be
public function selectquery($id){
$this->load->database();
$this->load->model('aboutmodel');
$data['h'] = $this->aboutmodel->selectByName($id);
$this->load->view('aboutpageview', $data);
}
And Model
public function selectByName($name){
$query =$this->db->get_where('phone_mobileinfos',array('name'=>$name));
return $query->result_array();
}
And View
foreach($h as $key => $value){ The code here is obviously in php tags but I cant show them
Mobile: echo $value['mobile_name'];
Price: echo $value['price'];
}
So you create a loop through the result, iterating each result found.
CAVEAT: you will need to test for a NULL result or you will get an error and be careful passing strings through the URL, codeigniter has sql injection protection but I always like to be safe

Return a single row in model, pass it to controller and view - Codeigniter

Sorry for posting such a noob question, but I've had hard times when working with returning a single
row from database and pass it to model. Here's my method from my model:
public function test($user_id)
{
$query = $this->db->query("SELECT COUNT(*) AS test FROM test WHERE user_id = '.$user_id.'");
return $query->first_row('array');
}
Here's an example of my controller with some other returned value from my model:
class MY_Controller extends CI_Controller
{
public $layout;
public $id;
public $data = array();
public function __construct()
{
parent::__construct();
$this->output->nocache();
$this->load->model('subject_model');
$this->load->model('user_model');
$this->load->model('survey_model');
$this->id = $this->session->userdata('user_id');
$this->data['check_if_already_posted_it_survey'] = $this->survey_model->checkIfAlreadyPostedSurvey('it_survey', $this->id);
$this->data['check_if_already_posted_lvis_survey'] = $this->survey_model->checkIfAlreadyPostedSurvey('lvis_survey', $this->id);
$this->data['test']= $this->survey_model->test($this->id);
$this->layout = 'layout/dashboard';
}
I can pass all the values from that data array to my view except "test". I've basically tried everything.
CheckIfAlreadyPostedSurvey method will return
number of rows with num_rows and I can easily print the value from them in my view by writing:
<?=$check_if_already_posted_it_survey?>
What should I do to print out that "test" in my view?
Thanks in advance and apologizes...
I probably got the question wrong, but have you tried
echo $this->survey_model->test($this->id);
Try this:
public function test($user_id)
{
$query = $this->db->query("SELECT COUNT(*) AS test FROM test WHERE user_id = '".$user_id."'");
return $query->row()->test;
}
This will return a single row as an object and then the referenced row name, which in this case is test.
The following will also work.
public function test($user_id)
{
$query = $this->db->query("SELECT * FROM test WHERE user_id = '".$user_id."'");
return count($query->result());
}
You also messed up the quoting in your SQL statement.

Passing parameter (that is result of another model function) to a model function

How can i pass a parameter (that is a returned value of another model function) to a function of a model class.
here's my model class functions
public function get_products_categories()
{
$query = $this->db->query('SELECT DISTINCT category
FROM products');
return $query->result_array();
}
public function get_products_names($category)
{
$query = $this->db->query('SELECT name
FROM products
WHERE category=$category');
return $query->result_array();
}
and here's how I am doing in the controller class
$this->load->model('products_model');
$data['products_categories'] = $this->products_model->get_products_categories();
$data['products_names'] = $this->products_model->get_products_names();
Now what I want is to pass $products_categories to the function $this->products_model->get_products_names(); but this is not possible $products_categories is not variable here in the controller class but in the view file, it can be used as a variable
Any Ideas ?
What do you want to do? For example, if you want to list all of your products in the categories, you can do this:
$data['products_categories'] = $this->products_model->get_products_categories();
$data['products_names'] = array();
foreach($data['products_categories'] as $product){
$data['products_names'][$product['category']] = $this->products_model->get_products_names($product['category']);
}
Try like:
$this->load->model('main_model');
$data1 = $this->main_model->function1();
//if u wnt to pass data1 to fun2() then
$data2 = $this->main_model->function2($data1);
if the second fun is in another model try to load it and then give as:
$data2 = $this->another_model->function2($data1);
damn sure it wotrks.....

Code Igniter Count Function

What I want to do is I want to count the total records from the table called "songs_tbl" from my database. So I wrote this function in controller.
private function getHeaderInfo()
{
$total_songs = $songs->count('distinct songs_tbl.song_id');
$this->mysmarty->assign('total_songs',$total_songs);
}
I got this error
Fatal error: Call to a member function count() on a non-object in
Any suggestion ? Thank you.
With Regards,
I think you are looking for:
$this->db->count_all('songs_tbl');
or if you want the distinct in there you will need to do something like this:
$this->db->select('song_id');
$this->db->distinct();
$this->db->from('songs_tbl');
$query = $this->db->get();
return $query->num_rows();
As there is/was? an issue with using count_all_results() function and DISTINCT
EDIT
I have never used smarty but based on the code in the question I imagine something like this might work, please correct me if I am wrong:
private function getHeaderInfo()
{
$total_songs = get_all_songs();// This function should be called through a model
$this->mysmarty->assign('total_songs',$total_songs);
}
function get_all_songs(){ //THIS SHOULD BE IN A MODEL
$this->db->select('song_id');
$this->db->distinct();
$this->db->from('songs_tbl');
$query = $this->db->get();
return $query->num_rows();
}
Edit 2
My suggested layout would be something along these lines (UNTESTED) using CodeIgniter WITHOUT smarty:
Model Song.php
class Song extends CI_Model {
//Constructor and other functions
function count_all_songs(){
$this->db->select('song_id');
$this->db->distinct();
$this->db->from('songs_tbl');
$query = $this->db->get();
return $query->num_rows();
}
}
Controller Songs.php
class Song extends CI_Controller {
//Constructor and other functions
function index(){ //This could be any page
$this->load->model('Song'); //Could be in constructor
$total_songs = $this->Song->count_all_songs();
$this->load->view('songs_index.html', array('total_songs' => $total_songs));
}
}
View songs_index.html
<html><head></head><body>
Total Songs: <?php echo $total_songs ?>
</body></html>
You could query the table and request a count from the table itself, like this:
$result = mysql_query(SELECT count(*) FROM songs_tbl);
Try this
echo $this->db->count_all('songs_tbl');
It permits you to determine the number of rows in a particular table.
you can use this
$query = $this->db->get('distinct');
if($query->num_rows())
{
return $query->num_rows();
}else{
return 0;
}

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