sum and divide depends on input php - php

Question

I have a form like this
for($x=0;$x<8;$x++){
echo "<input name='test[]'> <br>";
}
then i'm input, and i get this result
Array
(
[0] => 1
[1] => 2
[2] => 0
[3] => 0
[4] => 0
[5] =>
[6] => 0
[7] =>
)
I want to sum then divide it. I'm using array_sum to sum it. Now the problem, how can i divide it depends on my input(s) not the many of input field(s) and i don't want count the zero as input.
so it will become something like this
(1+2) / 2
how can i achieve that? sorry for my bad english.

Answer 1

If you want only non-zero values to be counted, you'll need to filter those zero and empty values away. You can still use array_sum(), to sum the array, but you'll need a filter on your count(), because count() will count all elements, regardless of the content (except null-values).
array_filter() takes care of this. So you'll simply need this
echo array_sum($myArray) / count(array_filter($myArray)); // Outputs 1.5 with your sample-array
Live demo
http://php.net/count
http://php.net/array_filter

Answer 2

Try This:
$myArray = Array
(
[0] => 1
[1] => 2
[2] => 0
[3] => 0
[4] => 0
[5] =>
[6] => 0
[7] =>
)
$countArray = 0;
foreach($myArray as $v){
if($v !== 0 || $v !== ''){ //skip if 0 or empty
$countArray++
}
}
$result = array_sum($myArray) / $countArray;

Answer 3

You may use this PHP custom Function
<?php
/* Function for check and remove blank and empty element from array */
function remove_blank($arra)
{
$newArr = array();
$total = count($arra);
for($i = 0; $i <= $total; $i++)
{
if($arra[$i] != "" && $arra[$i] >= 0)
{
$newArr[] = $arra[$i];
}
}
echo "<pre>";
print_r($newArr);
}
$arra = array(1, 2, 0, 0,'', 0,'');
remove_blank($arra);
?>