Get word after certain word in split array? - php

Question

I have a path that is separated by forward slash.
$uri = getenv('REQUEST_URI');
$uri = explode('/', $uri);
$uri = array_filter($uri);
$uri = array_merge($uri, array());
The path would end up something like:
/user/john/account
This will grab the last word in the path, 'account'.
$uri = end($uri);
How can I get the first word found after 'user' into a variable?
In this case it would be 'john', but the name can change on every new URI.
'user' always stays the same word.

Answer 1

$uri = "/user/john/account";
$uri_array = explode("/", $uri);
$key = array_search("user", $uri_array);
$desired_value = array_key_exists($key+1, $uri_array) ? $uri_array[$key+1] : "error";
echo $desired_value;
Here is what you need : Note : "user" is a fixed term in array_search .. you can change it

Answer 2

Before $uri = end($uri) add this:
$uriArray = explode('/',$uri); //$uriArray[0] = 'user' //$uriArray[1] = 'john'
$name = $uriArray[1];
With this you could also get the last element after a slash
EDIT:
You could also use preg_split('pattern',$string) like this:
$name = preg_split('user/',$uri);
$name would be "john/account". Then use explode again, to save it into an array, element 0 is the name

Answer 3

Using preg_match might be more efficient in this case:
Psy Shell v0.8.1 (PHP 7.1.1-1+deb.sury.org~xenial+1 — cli) by Justin Hileman
>>> preg_match('~/user/([^/]+)/?~', '/test/user/username/tuedelue', $matches);
=> 1
>>> $matches;
=> [
"/user/username/",
"username",
]
>>> $matches[1];
=> "username"
>>> |
So these lines
$user = 'unknown';
if (preg_match('~/user/([^/]+)/?~', getenv('REQUEST_URI'), $matches)) {
$user = $matches[1];
}
would solve your problem.

Answer 4

You can use this
$uri='/user/john/account';
$from1 ='/user/';
$to1 ='/';
//$uri = explode('/', $uri);
echo get_string_between($uri,$from1,$to1);
function get_string_between ($str,$from,$to) {
$string = substr($str, strpos($str, $from) + strlen($from));
if (strstr ($string,$to,TRUE) != FALSE) {
$string = strstr ($string,$to,TRUE);
}
return $string;
}

Answer 5

Edit: Use M A SIDDIQUIs answer. It is the better way to solve this problem
You can write a function for this that finds out whitch position of the uri-Array contains the word user and then returns the next position that should contain the name.
function getName($uri)
{
$uri = explode('/', $uri);
for($i = 0; $i < sizeof($uri); $i++){
if($uri[$i] == "user"){
return $uri[$i+1];
}
}
}
Then you just have to print it out with:
echo getName("exmaple/user/username/etc");