display mysql table with a field as the main header - php

I have a mysql data table that I am displaying on a php page. It works but I would like them be grouped under the departments they belong to. Also to remove all other field headers such as Name,Phone Email.
I tried using SORT BY but nothing happened.
eg. This is how I would like it to look like
Vehicle Department
Bob 3234234 bob#acas.com
Hanna 3434323 Hanna#asas.com
Workshop Department
Andrew 45454523 andrew#aasdasd.com
This is how it currently looks:
ID Name Phone Email Department
1 Bob 3234234 bob#asasdas.com Vehicle Department
2 Hanna 3434323 hanna#asasdas.com Workshop Department
my current code:
<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pwd = '*****';
$database = 'list';
$table = 'users';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");
if (!mysql_select_db($database))
die("Can't select database");
// sending query
$result = mysql_query("SELECT * FROM {$table}");
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result);
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
$temp = "";
while($row = mysql_fetch_row($result))
{
echo "<tr>";
if ($row['department'] != $temp){
echo "<td colspan=\"3\">" . $row['department'] . "</td></tr>\n<tr>";
$temp = $row['department'];
}
echo "<td>" . $row['name'] . "</td><td>" . $row['phone'] . "</td><td>" . $row['email'] . "</td>";
echo "</tr>\n";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
?>

If you use
"SELECT name, phone, email, department FROM {$table} ORDER BY department"
as your query, it will return only your desired columns, ordered by the department column.
Then you can arrange them in your table depending on their department.
Note that you might have to adjust the column names.
Try this code:
<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pwd = '*****';
$database = 'list';
$table = 'users';
$conn = mysqli_connect($db_host, $db_user, $db_pwd) or die("Connecting to database failed");
mysqli_select_db($conn, $database) or die("Can't select database");
// sending query
$result = mysqli_query($conn, "SELECT name, phone, email, department FROM {$table} ORDER BY department");
if (!$result) {
die("Query to show fields from table failed");
}
echo "<table border='1'><tr>";
// printing table rows
$temp = "";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
if ($row['department'] != $temp){
echo "<td colspan=\"3\" align=\"center\">" . $row['department'] . "</td></tr>\n<tr>";
$temp = $row['department'];
}
echo "<td>" . $row['name'] . "</td><td>" . $row['phone'] . "</td><td>" . $row['email'] . "</td>";
echo "</tr>\n";
}
mysqli_free_result($result);
echo "</table>"
?>

First, you have to process the data to arrange in a structure you want for it.
<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pwd = '*****';
$database = 'list';
$table = 'users';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");
if (!mysql_select_db($database))
die("Can't select database");
// sending query
$result = mysql_query("SELECT * FROM {$table}");
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result);
echo "<table border='1'><tr>";
// printing table headers
for ($i = 0; $i < $fields_num; $i++) {
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
//variable to store rearranged results;
$resultsModified = [];
// printing table rows
while ($row = mysql_fetch_row($result)) {
if (!isset($resultsModified[$result['department']]))
$resultsModified[$result['department']] = [];
$resultsModified[$result['department']][] = $row;
}
foreach ($resultsModified as $daptName => $results) {
echo "<caption> $daptName </caption>";
foreach ($results as $row) {
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach ($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
}
mysql_free_result($result);
However I have not tested it but this should work.

Related

get all values of columns in sql php [duplicate]

I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>

PHP Fetch row data from Mysql via ID

I am new to php. I have the following code that auto fetches all the rows and columns from the db. I want to make the script to fetch a particular row using its ID column. for example: www.site.com/view.php?id=22
I am trying to get it work with the $_GET['link']; variable like this:
if (isset($_GET['id'])) {
$result = mysqli_query($connection,"SELECT * FROM $_GET['link']");
} else {
$result = mysqli_query($connection,"SELECT * FROM reservations");
}
But I am unable to get it work.
The complete code is as below:
<?php
$host = "localhost";
$user = "user";
$pass = "Pass1";
$db_name = "test";
//create connection
$connection = mysqli_connect($host, $user, $pass, $db_name);
//test if connection failed
if(mysqli_connect_errno()){
die("connection failed: "
. mysqli_connect_error()
. " (" . mysqli_connect_errno()
. ")");
}
//get results from database
$result = mysqli_query($connection,"SELECT * FROM reservations");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table" border="1">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
array_push($all_property, $property->name); //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
?>
Any help would be appreciated..
You can do this
Add
$query = 'SELECT * FROM reservations';
if (!empty($_GET['id']) and ($id = (int)$_GET['id']))
$query .= " WHERE id = {$id} LIMIT 1";
and change this
mysqli_query($connection,"SELECT * FROM reservations");
to this
$result = mysqli_query($connection, $query);
In the above code I added a bit of security so that if $_GET['id'] is not a valid integer it will revert to query where it fetches all the data. I added that because you should never put $_GET directly into your query.
Here is a your code I have modified it to your requirements
<?php
$host = "localhost";
$user = "user";
$pass = "Pass1";
$db_name = "test";
//create connection
$connection = mysqli_connect($host, $user, $pass, $db_name);
//test if connection failed
if(mysqli_connect_errno()){
die("connection failed: "
. mysqli_connect_error()
. " (" . mysqli_connect_errno()
. ")");
}
$query = 'SELECT * FROM reservations';
if (!empty($_GET['id']) and ($id = (int)$_GET['id']))
$query .= " WHERE id = {$id} LIMIT 1";
//get results from database
$result = mysqli_query($connection, $query);
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table" border="1">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
array_push($all_property, $property->name); //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
if(isset($_GET['id'])) {
$id = $_GET['id'];
} else {
$id=NULL;
}
$sql = "SELECT * FROM reservations WHERE id = '".$id."'";
$result = mysqli_query($connection,$sql);
$row = mysqli_fetch_assoc($result);
if(mysqli_num_rows($result) == 1) {
dd($row);
} else {
echo "no records found with this id";
}
Hope this script meets your answer

Show values from a MySQL database table inside a HTML table on a webpage

I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>

SELECT * FROM Table Where ID

I am trying to retrieve information from my database depending on the ID a user types into my URL.
For example: If USER A went to www.exampleurl.com/index.php?id=1 it would echo out the user's information which has an ID of 1. Same thing if the id was 2, 3, etc. Users are entering their information via a form in a different file called submit.php.
Here is my code to retrieve data depending on ID :
<?php
$id = $_GET['id'];
//Variables for connecting to your database.
$hostname = "";
$username = "";
$dbname = "";
$password = "";
$usertable = "";
//Connecting to your database
$con = mysql_connect($hostname, $username, $password) OR DIE ("Unable to
connect to database! Please try again later.");
mysql_select_db($dbname, $con);
$query = "SELECT * FROM $usertable WHERE id = $id LIMIT 1";
$result = mysql_query($query, $con);
echo "Hello, " . $result['name'];
?>
Any ideas on if my SELECT request is wrong?
EDIT
Here is my code for showing the data altogether in a table. This works fine.
<?php
//Variables for connecting to your database.
$hostname = "";
$username = "";
$dbname = "";
$password = "!";
$usertable = "";
//Connecting to your database
$con = mysql_connect($hostname, $username, $password) OR DIE ("Unable to
connect to database! Please try again later.");
mysql_select_db($dbname, $con);
//Fetching from your database table.
$query = "SELECT * FROM $usertable";
$result = mysql_query($query, $con);
echo "<table border=1>
<tr>
<th> ID </th>
<th> Name </th>
<th> Age </th>
</tr>";
while($record = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $record['id'] . "</td>";
echo "<td>" . $record['name'] . "</td>";
echo "<td>" . $record['age'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>
→ Try This:
You should consider using PHP PDO as it is safer and a more object oriented approach:
$usertable = "";
$database = new PDO( 'mysql:host=localhost;dbname=DB_NAME', 'DB_USER_NAME', 'DB_USER_PASS' );
$statement = $database->prepare('SELECT * FROM $usertable');
$statement->execute();
$count = $statement->rowCount();
if( $count > 0 ) {
$R = $statement->fetchAll( PDO::FETCH_ASSOC );
for( $x = 0; $x < count($R); $x++ ) {
echo "<tr>";
echo "<td>" . $R[ $x ]['id'] . "</td>";
echo "<td>" . $R[ $x ]['name'] . "</td>";
echo "<td>" . $R[ $x ]['age'] . "</td>";
echo "</tr>";
}
}
else { echo "Error!"; }
you need to use mysql_fetch_assoc function for retrieve the results.
$result = mysql_fetch_assoc(mysql_query($query, $con));
echo "Hello, " . $result['name'];
You should be error checking your mysql_querys:
$query = "SELECT * FROM $usertable WHERE id = $id LIMIT 1";
$result = mysql_query($query, $con);
if(!result)
echo mysql_error();
You should also retrieve the results:
$array = mysql_fetch_assoc($result);
I'll consider some secure features like
Check if $_GET['id'] is set and if is int
Apply Mysql escape with mysql_escape_string() function

Displaying all tables in a database

How do I display out all the information in a database (All tables and records) using PHP? I read displaying tables as HTML table but how do I do it for all the tables?
I tried the example here:
http://davidwalsh.name/html-mysql-php
But it shows the table names, how do I also display all the values?
Okay got it .. try this
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "username", "password", "DB");
$result = $mysqli->query("SHOW TABLES");
while ($row = $result->fetch_row()) {
$table = $row[0];
echo '<h3>', $table, '</h3>';
$result1 = $mysqli->query("SELECT * FROM `$table`");
echo '<table cellpadding="0" cellspacing="0" class="db-table">';
$column = $mysqli->query("SHOW COLUMNS FROM `$table`");
echo '<tr>';
while ($row3 = $column->fetch_row()) {
echo '<th>' . $row3[0] . '</th>';
}
echo '</tr>';
while ($row2 = $result1->fetch_row()) {
echo '<tr>';
foreach ($row2 as $key => $value) {
echo '<td>', $value, '</td>';
}
echo '</tr>';
}
echo '</table><br />';
}
$mysqli->close();
you can use the recursive function to display the tree Structure of your database.
Here is the a sample code from http://webcodingeasy.com/PHP/Simple-recursive-function-to-print-out-database-tree-structure
<?php
function print_menu($id = 0)
{
// get all records from database whose parent is $id
$result = $query->select_result("*", "table", "where parent = '".$id."'");
//check if there are any results
if($result != 0)
{
echo "<ul> n";
while($row = $query->fetch($result))
{
//print result and call function to check if it has children
echo "<li>".$row['name']."</li> n";
print_menu($row['ID']);
}
echo "</ul> n";
}
}
print_menu();
?>
If you want to pull all tables with the values in mysql, you can use the following code:
<?php
mysql_connect ("localhost", "DB_USER", "DB_PASSWORD"); //your mysql connection
mysql_select_db('DB_NAME') or die( "Unable to select database"); //your db name
$tables = mysql_query("SELECT table_name FROM information_schema.tables WHERE table_schema='DB_NAME'"); //pull tables from theh databsase
while ($table= mysql_fetch_row($tables)) {
$rsFields = mysql_query("SHOW COLUMNS FROM ".$table[0]);
while ($field = mysql_fetch_assoc($rsFields)) {
echo $table[0].".".$field["Field"].", "; //prints out all columns
}
echo $table[0];
$query = "SELECT * FROM ".$table[0]; //prints out tables name
$result = mysql_query($query);
PullValues($result); //call function to get all values
}
//function to pull all values from tables
function PullValues($result)
{
if($result == 0)
{
echo "<b>Error ".mysql_errno().": ".mysql_error()."</b>";
}
elseif (#mysql_num_rows($result) == 0)
{
echo("<b>Query completed. No results returned.</b><br>");
}
else
{
echo "<table border='1'>
<thead>
<tr><th>[Num]</th>";
for($i = 0;$i < mysql_num_fields($result);$i++)
{
echo "<th>" . $i . " - " . mysql_field_name($result, $i) . "</th>";
}
echo " </tr>
</thead>
<tbody>";
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
echo "<tr><td>[$i]</td>";
$row = mysql_fetch_row($result);
for($j = 0;$j < mysql_num_fields($result);$j++)
{
echo("<td>" . $row[$j] . "</td>");
}
echo "</tr>";
}
echo "</tbody>
</table>";
} //end else
}
?>
I am using this and works fine in mysql, for mysqli you need to tweak it a very little.

Categories