In this program i want that name of the image gets changed after it has been displayed on the page
But it gets changed before it could be displayed ...
the text file is used to get the name of image and also to store the new name of image file
<?php
$myfile = fopen("givename.txt", "r");
$d= fread($myfile,filesize("givename.txt"));
fclose($myfile);
img src="?php echo "80/$d.jpg";?>">
$rand=(mt_rand(10,100));
$mfile = fopen("givename.txt", "w") ;
fwrite($mfile, $rand);
fclose($mfile);
rename("80"."/"."$d".".jpg","80"."/"."$rand".".jpg");
?>
<?php
$myfile = fopen("givename.txt", "r");
$d= fread($myfile,filesize("givename.txt"));
fclose($myfile);
"<img src='80/$d.jpg'>";
$rand=(mt_rand(10,100));
$mfile = fopen("givename.txt", "w") ;
fwrite($mfile, $rand);
fclose($mfile);
rename("80"."/"."$d".".jpg","80"."/"."$rand".".jpg");
?>
Related
I'm creating a code to display the name of a server with enterprise rules, So for don't use Mysql i try a new things (for me) use php to read and rewrite files, that work perfectly for one part of my code and work perfectly but for the second he only read one time, and when i do a f5 the code don't increment.
He rewrite correctly because my file was at 000 and become 001
I try to use file() but he is disable since 7.0, try to use SplFileObject but it don't want to display anything and i don't like it because i understand nothing when i use it so i come back to fopen(),fread() and fwrite() and that don't work. I'm inPHP 7.3.1
The code that works :
<?php
if ( isset($_POST) AND !empty($_POST) ) {
$nom = "./config.txt";
$filez = fopen($nom, "r") or die("Unable to open file!");
$i = fread($filez,filesize($nom));
$year = getdate();
$idy = substr($year[year], 2);
$fichier = fopen("./resultsrv.txt", "w") or die("Unable to write file!");
for ($z; $z<$_POST['nbr']+1 ; $z++) {
$id = sprintf("%04d", $i+$z);
$nome = $_POST['type'].$_POST['OS'].$idy.$id."<br>" ;
echo $nome;
$nomewout = str_replace("<br>", ";", $nome);
fwrite($fichier,$nomewout);
}
$handle = fopen("./config.txt", "w") or die("Unable to write file!");
fwrite($handle,$id);
fclose($fichier);
fclose($handle);
}
?>
and the one that doesn't work because he doesn't increment :
<?php
if ( isset($_POST) AND !empty($_POST) ) {
$fileName = 'confchass.txt';
$read = fopen($fileName,"r");
$fn = fopen($fileName,"w+");
$i = fread($read,filesize($fileName));
$id = sprintf("%03d", $i+1);
echo "<div align='center'><h1>Le Chassis</h1>";
echo $_POST['Marque'].$_POST['DC'].$id;
echo "</div>";
fwrite($fn,$id);
fclose($read);
fclose($fn);
}
?>
I want he output a thing like XXXXXX001 and when i refresh or do a new POST from my forms he output XXXXXX002 and XXXXXX003 .... But he actualy output only XXXXXX001
The problem is that you open the file for reading and then for writing. But from the manual...
'w+' Open for reading and writing; place the file pointer at the
beginning of the file and truncate the file to zero length. If the
file does not exist, attempt to create it.
So this will blank out the file before you read the value from it.
To fix this (using your current method, you should read the value, then open it for writing and write the new value...
$read = fopen($fileName,"r");
$i = fread($read,filesize($fileName));
fclose($read);
$id = sprintf("%03d", $i+1);
echo "<div align='center'><h1>Le Chassis</h1>";
echo $id;
echo "</div>";
$fn = fopen($fileName,"w+");
fwrite($fn,$id);
fclose($fn);
You could shorten this by using file_get_contents() and file_put_contents().
I have created something that once text is put inside of a text box and submit is pressed it sends this to a server and it is then stored in a session. On the press of another button you can retrieve this text and it is then transferred from the session to a txt file.
Yesterday I had this working and it was printing to my txt file but now all of a sudden it wont do it at all, can anyone spot any issues that would cause this?
This is ran when the retrieve button is pressed:
<?php session_start(); ?>
<?php
print_r($_SESSION ["input_data"]);
$myfile = fopen("TestingOut.txt", "a+") or die("Unable to open file!");
$txt = $_SESSION["input_data"];
fwrite($myfile, $txt);
fclose($myfile);
?>
I have narrowed it down to the $_SESSION["input_data"] part as it will print some random text in place for he session as seen above.
This is the creation of the session array:
<?php session_start(); ?>
<?php
$_SESSION["input_data"][] = $_POST["input"];
echo $_POST["input"];
?>
Many thanks to #marekful , I was tryign to print an array into a text file, I used implode() to fix this:
$strings = implode(" ", $_SESSION["input_data"]);
$myfile = fopen("TestingOut.txt", "a+") or die("Unable to open file!");
$txt = $strings;
fwrite($myfile, $txt);
fclose($myfile);
I used below HTML code and php code to Write new files.
<html>
<body>
<form action="write.php" method="get">
ID : <input type="text" name="ID"><br>
<input type="submit">
</form>
</body>
</html>
<?php
$myfile = fopen($_GET["ID"] , "w") or die("Unable to open file!");
$txt = "Your user ID =";
fwrite($myfile, $txt);
$txt = $_GET["ID"];
fwrite($myfile, $txt);
fclose($myfile);
?>
If I submit TEST to html form , php code writes a file named "test". it hasn't a file extension.
How to write "TEST.html" with above code.?
Add the extension to the filename before opening the file:-
$filename = $_GET["ID"] . '.html';
$myfile = fopen($filename, "w") or die("Unable to open file!");
Note You are opening up yourself to all kinds of security issues here.
just use this code:-
fopen($_GET["ID"].'.html' , "w")
You need to add .html with a !empty() check there, like below:-
<?php
if(!empty($_GET['ID'])){ // check first that ID is coming or not
$myfile = fopen($_GET["ID"]."html" , "w") or die("Unable to open file!");
$txt = "Your user ID =";
fwrite($myfile, $txt);
$txt = $_GET["ID"];
fwrite($myfile, $txt);
fclose($myfile);
}
?>
To open and read this file:-
<?php
if(!empty($_GET['ID'])){ // check first that ID is coming or not
$myfile = fopen($_GET["ID"]."html", "r") or die("Unable to open file!");
echo fread($myfile,filesize($_GET["ID"]));
fclose($myfile);
}
?>
OR:-
<?php
if(!empty($_GET['ID'])){ // check first that ID is coming or not
$file = fopen($_GET["ID"]."html","r") or die("Unable to open file!"); ;
while(! feof($file)){
echo fgets($file). "<br />";
}
fclose($file);
}
?>
Note:-
In my opinion you need .txt rather than .html.An HTML file with text like test really have no mean, or server any useful purpose. BTW it's up-to-you what extension you want. I just gave my opinion.
I have the below php file. When i try to run this file, nothing is getting displayed
<html>
<body>
<?php
$myfile = fopen("1.txt", "a+") or die("Unable to open file!");
echo fgetss($myfile,149,"<td>,</td>");
fclose($myfile);
?>
</body>
The 149th line of my 1. txt file is
<td>Mfg of Textile Readymade Garments</td>
According to documentation, fgetss will read length bytes for the current line. So fgetss($myfile,149,"<td>,</td>") will read 149 bytes on the first line.
You could try (quick and dirty):
<?php
$myfile = fopen("1.txt", "r") or die("Unable to open file!");
for ($i = 0; $i < 149; $i++) fgets($myfile);
echo fgetss($myfile, 4096, "<td>,</td>");
fclose($myfile);
?>
Side note, you want to read file, so replace a+ with r in your fopen call
The function fgetss() the second parameter informs the amount of bytes that will be returned in the line and not the specific line that you want to pick up.
One way to get a specific line from a file, is by using a function:
<?php
function get_line($arq,$linha)
{
$arquivo = file($arq);
$y = $linha - 1;
$x = print $arquivo[$y];
return $x;
}
get_line("1.txt",149);
?>
so i have this code for generate file.txt
<?php
$myfile = fopen("test.txt", "w") or die("Unable to open file!");
$txt = "John Doe\n";
fwrite($myfile, $txt);
$txt = "Jane Doe\n";
fwrite($myfile, $txt);
fclose($myfile);
?>
then i show it on textarea like this:
<textarea rows="5" cols="50">
<?php
$file = file_get_contents('./test.txt', FILE_USE_INCLUDE_PATH);
echo $file;
?>
</textarea>
i need to print the file test.txt directly using button in php. How can i do this in php / laravel framework?? thanks
1 instead of showing the textarea, just show a link:
print text.txt!
2 create a new file called print_test_txt.php and populate it with this php
3
<?php
$file = file_get_contents('./test.txt', FILE_USE_INCLUDE_PATH);
echo $file;
?>
which will output it to the screen so the user can print it. if you are hoping to print to a known printer, see this solution:
directly print with php